Computational Geometry Piyush Kumar (Lecture 2: NN Search) Welcome to CIS5930 Our First Problem Nearest neighbor searching Applications? o Pattern Classification o Graphics o Data Compression o Document retrieval o Statistics o Machine Learning o… Similarity Measure In terms of Euclidean distance dist ( p , q ) d i 1 ( pi qi ) (4,5) dist ( p , q ) (2 4) 2 (3 5) 2 2 2 (2,3) 2 Similarity Measure Similar? Similarity measure Other similarity Measures d ( p , q ) cos( p, q ) d i 1 pi qi | p || q | d ( p, q) e || p q ||2 2 r 2 The dimension Lets assume that our points are in one dimensional space. ( d = 1 ). We will generalize to higher dimension ( Where d = some constant ). Fixed radius near neighbor problem Question Given a set of points S on the real line, preprocess them to answer the following question : Find all the pair of points (p,q) such that distance of (p,q) < r . q Points in S Nearest neighbor search Question Given a set of points S on the real line, preprocess them to answer the following query : Given a query point q, find the neighbor of q which is closest in S. q nn(q) Points in S Answers? Fixed NN Search NN Search Answers? NN Search O( n ) ? O( log n) ? Brute Force [ Trivial ] Binary Search Tree Fixed NN Search O( n2 ) ? Brute Force O(nlogn + k) ? Sorting O(n + k) ? Hashing? NN search NN Searching : Balanced binary tree q nn(q) Points in S K-nearest neighbor search Problem: Given a set of points P on the real line and a query point q, find the k-nearest neighbors of q in P. O(nlogn) Trivial bruteforce Do you see how? Thought Problem: How do we do this in O(n) time? (Hint: Median finding works in O(n) time). Fixed NN Search Brute Force implementation What can we speed up here? How do we speed this up? Fixed NN Search: By Sorting Once we sort the points on the real line, we can just go left and right to identify the pairs we need. Each pair is visited at most twice, so the asymptotics do not change. Total work done after sorting Total work done after sorting • ki denotes the pairs generated when visiting pi • With this approach, we need at least Ω(nlogn) (for sorting). Fixed radius near neighbor searching How do we avoid sorting? How do we get a running time of O(n+k) ? Solution using bucketing • Put points in infinite number of buckets (Assume an infinite array B) b=0 { b= -2 r 0 Interval b is [ br, (b+1)r ] x lies in b = floor (x/r) Solution using bucketing Only n buckets of B might get occupied at most. How do we convert this infinite array into a finite one: Use hashing In O(1) time, we can determine which bucket a point falls in. In O(1) expected time, we can look the bucket up in the hash table Total time for bucketing is expected O(n) The total running time can be made O(n) with high probability using multiple hash functions ( essentially using more than one hash function and choosing one at run time to fool the adversary ). The Algorithm Store all the points in buckets of size r In a hash table [ Total complexity = O(n) ] For each point x b = floor(x/r); Retrieve buckets b, b+1 Output all pairs (x,y) such that y is either in bucket b or b+1 and x < y and ||xy|| < r 0 x Running Time Let nb denote the number of points in bucket b of the input pointset P. Define Note that there are nb2 pairs in bucket b alone that are within distance r of each other. Observation Since each pair gets counted twice : S n n bB 2 b bB 2 b 1 2k Running Time Depends on the number of distance computations D. Since : Total Running Time = O(n+k) Higher Dimensions Send (x,y) (floor(x/r),floor(y/r)) Apply hash with two arguments Running time still O(n+k) Higher Dimensions The running time of this algorithm increases exponentially with diemension. Why? Introduction: Geometry Basics Geometric Systems Vector Space Affine Geometry Euclidean Geometry o AG + Inner Products = Euclidean Geometry Vector Space Scalar ( + , * ) = Number Types Usual example is Real Numbers R. Let V be a set with two operations +:VxVV *:FxVV o Here F is the set of Scalars Vector Space If (V , +, * ) follows the following properties, its called a vector space : (A1) u + (v + w) = (u + v) + w for all u,v,w in V. (A2) u + v = v + u for all u,v in V. (A3) there is unique 0 in V such that 0 + u = u for all u in V. (A4) for every u in V, there is unique -u in V such that u + u = 0. (S1) r(su) = (rs)u for every r,s in R and every u in V. (S2) (r +s)u = ru + su for every r,s in R and every u in V. (S3) r(u + v) = ru + rv for every r in R and every u,v in V. (S4) 1u = u for every u in V. Note: Vectors are closed under linear combinations A basis is a set of n linearly independent vectors that span V. Affine Geometry Geometry of vectors Not involving any notion of length or angle. Consists of A set of scalars o Say Real numbers A set of points o Position specification A set of free vectors. o Direction specification Affine Geometry Legal operations Point - Point = Vector Point +/- Vector =Point Vector +/- Vector = Vector Scalar * Vector = Vector Affine Combination o ∑Scalar * Points = Point – such that ∑Scalar = 1 – Note that scalars can range from –Infinity to +Infinity Affine Geometry aff ( p0 , p1;0 , 1 ) 0 p0 1 p1 p0 1 ( p1 p0 ) Affine Combination i ( , ) Convex Combination i (0,1) Affine Combinations [ Affine Span or Affine Closure ] The set of all affine combinations of three points generates a plane. [ Convex Closure ] The set of all convex combinations of three points generates all points inside a triangle. Euclidean Geometry One more element added Inner Products o Maps two vectors into a scalar o A way to `multiply’ two vectors Example of Inner Products Example : Dot products (u.v) = u0v0+ u1v1+…+ ud-1vd-1 o Where u,v are d-dimensional vectors. o u = (u0,u1,…, ud-1); v = (v0,v1,…, vd-1) Length of |u| = sqrt(u.u) (Distance from origin) Normalization to unit length : u/|u| Distance between points |p - q| Angle (u’,v’) = cos-1(u’.v’) o where u’=u/|u| and v’=v/|v| Dot products (u.v) = (+/-)|u|(projection of v on u). u is perpendicular to v (u,v) = 0 u.(v+w) = u.v + u.w If u.u not equal to zero then u.u > 0 positive definite Some proofs using Dot Products Cauchy Schwarz Inequality (u.v) <= |u||v| Homework. o Hint: For any real number x v – (u+xv).(u+xv) >= 0 Triangle Inequality |u+v|<=|u|+|v| o Hint: expand |u+v|2 u and use Cauchy Schwarz. Next Lecture Orientation and Convex hulls Optional Homework: (Programming) Play with dpoint.hpp and example.cpp (Implement orientation in d-D). Implement your own dvector.hpp, dsegment.hpp using metaprogramming Make sure you understand how things work. Due Monday Homework: (Theory) Cauchy Schwarz Triangle Inequality dot n cross prod. Reading Assignment: Page 1-5, Notes of Dr. Mount Lecture 33 and Section 1.3 of the text book. Crash course on C++ “dpoint.hpp” Namespaces Solve the problem of classes/variables with same name namespace _cg {code} Outside the namespace use _cg::dpoint Code within _cg should refer to code outside _cg explicitly. E.g. std::cout instead of cout. Object Oriented Programming Identify functional units in your design Write classes to implement these functional units Separate functionality for code-reuse. Class membership Public Private Always : Keep member variables private This ensures that the class knows when the variable changes Protected Inheritance ‘is a’ relationship is public inheritance Class SuperDuperBoss : public Boss Polymorphism : Refer an object thru a reference or pointer of the type of a parent class of the object SuperDuperBoss JB; Boss *b = &JB; Virtual functions Templates Are C macros on Steroids Give you the power to parametrize Compile time computation Performance “The art of programming programs that read, transform, or write other programs.” - François-René Rideau Generic Programming How do we implement a linked list with a general type inside? void pointers? Using macros? Using Inheritance? Templates Function Templates Class Templates Template templates * Full Template specialization Partial template specialization Metaprogramming Programs that manipulate other programs or themselves Can be executed at compile time or runtime. Template metaprograms are executed at compile time. Good old C C code Double square(double x) { return x*x; } o sqare(3.14) Computed at compile time #define square(x) ((x)*(x)) Static double sqrarg; #define SQR(a) (sqrarg=(a), sqrarg*sqrarg) Templates Help us to write code without being tied to particular type. Question: How do you swap two elements of any type? How do you return the square of any type? Function Templates C++ template< typename T > inline T square ( T x ) { return x*x; } A specialization is instantiated if needed : o square<double>(3.14) Template arguments maybe deduced from the function arguments square(3.14) MyType m; … ; square(m); expands to square<MyType>(m) Operator * must be overloaded for MyType Function Templates template<typename T> void swap( T& a, T& b ){ T tmp(a); // cc required a = b; // ao required b = tmp; } Mytype x = 1111; Mytype y = 100101; swap(x,y); swap<Mytype>(…) is instantiated Note reliance on T’s concepts (properties): In above, T must be copyable and assignable Compile-time enforcement (concept-checking) techniques available Function Template Specialization template<> void swap<myclass>( myclass& a, myclass& b){ a = b = 0; } Custom version of a template for a specific class Class Templates template<typename NumType, unsigned D> class dpoint{ public: NumType x[D]; }; A simple 3-dimensional point. dpoint<float,3> point_in_3d; point_in_3d.x[0] = 5.0; point_in_3d.x[1] = 1.0; point_in_3d.x[2] = 2.0; Note the explicit instantiation Class Templates: Unlike function templates Class template arguments can’t be deduced in the same way, so usually written explicitly: dpoint <double, 2> c; // 2d point Class template parameters may have default values: template< class T, class U = int > class MyCls { … }; Class templates may be partially specialized: template< class U > class MyCls< bool, U > { … }; Using Specializations First declare (and/or define) the general case: template< class T > class C { /* handle most types this way */ }; Then provide either or both kinds of special cases as desired: template< class T > class C< T * > { /* handle pointers specially */ }; template<> // note: fully specialized class C< int * > { /* treat int pointers thusly */ }; Compiler will select the most specialized applicable class template Template Template Parameters A class template can be a template argument Example: template< template<class> class Bag > class C { // … Bag< float > b; }; Or even: template< class E, template<class> class Bag > class C { // … Bag< E > b; }; Recall C Enumerations #define SPRING 0 #define SUMMER 1 #define FALL 2 #define WINTER 3 enum { SPRING, SUMMER, FALL, WINTER }; More Templates template<unsigned u> class MyClass { enum { X = u }; }; Cout << MyClass<2>::X << endl; Template Metaprograms Factorials at compile time template<int N> class Factorial { public: enum { value = N * Factorial<N-1>::value }; }; class Factorial<1> { public: enum { value = 1 }; }; Int w = Factorial<10>::value; Template Metaprograms Metaprogramming using C++ can be used to implement a turning machine. (since it can be used to do conditional and loop constructs). Template Metaprograms template< typename NumType, unsigned D, unsigned I > struct origin { static inline void eval( dpoint<NumType,D>& p ) { p[I] = 0.0; origin< NumType, D, I-1 >::eval( p ); } }; // Partial Template Specialization template <typename NumType, unsigned D> struct origin<NumType, D, 0> { static inline void eval( dpoint<NumType,D>& p ) { p[0] = 0.0; } }; const int D = 3; inline void move2origin() { origin<NumType, D, D-1>::eval(*this); }; Food for thought You can implement IF WHILE FOR Using metaprogramming. And then use them in your code that needs to run at compile time For the more challenged: Implement computation of determinant / orientation / volume using metaprogramming. (Extra credit) Traits Technique Operate on “types” instead of data How do you implement a “mean” class without specifying the types. For double arrays it should output double For integers it should return a float For complex numbers it should return a complex number Traits Template< typename T > struct average_traits{ typedef T T_average; }; Template<> struct average_traits<int>{ typedef float T_average; } Traits average_type(T) = T average_type(int) = float Traits template<typename T> typename average_traits<T>::T_average average(T* array, int N){ typename avearage_traits<T>::T_average result = sum(array,N); return result/N; } Sources C++ Templates by Vandevoorde and Josuttis. (A must have if you template) Template Metaprogramming by Todd Veldhuizen C++ Meta<Programming> Concepts and results by Walter E. Brown C++ For Game programmers by Noel Llopis C++ Primer by Lippman and Lajoie GNU MP GMP is a free library for arbitrary precision arithmetic, operating on signed integers, rational numbers, and floating point numbers. Get yourself acquinted with : Mpz : Integer arithmetic mpq : Rationals Mpf : Floats Recall: Determinant 2x2 3x3 Determinants Volume of Parallelepiped Orientation primitive for points +ve in this case Orientation function Homeworks Prove that for two vectors v1 = (v1x,v1y) and v2 = (v2x,v2y) v1x* v2x + v1y * v2y = |v1||v2| cos Ө v1y* v2x - v2y * v1x = |v1||v2| sin Ө What do these quantities mean geometrically? Note that one changes sign when Ө is negative. Problems with fixed point arithmetic : 3.141592653589793238462643383.... float pi = 2 * asin(1); printf("%.35f\n", pi); Outputs 3.14159274101257324218750000000000000 typically are 32 bits and can deal with 7 digits after decimal float Exaggerating the error Suppose our computer computes in base 10, but only keeps the two most significant digits. We call this fixed precision computation Let us take three points: o p = (-94,0) o q = (92,68) o r = (400,180) Triangle pqr is oriented clockwise, hence area < 0. Determinant True value: (92+94)*180(400+94)*68=186*180-494*68=3348033592 =-112 Fixed precision computation : (92+94)*180-(400+94)*68=190*180490*68=34000-33000 =+1000 Floating point computation Sometimes produces wrong results Exact computation is possible (And hence we will use GMP : An easy way out) Exact computations are slow and can be avoided. One simple method : Use floating point to estimate whether you really need Exactness, only then invoke exact computation. Convexity A set S is convex if for any pair of points p,q S we have pq S. p p q convex q non-convex Convex hulls The smallest convex body that contains a set of points The intersection of all convex sets that contain S. p12 p6 p9 p11 p0 p7 p8 p5 p4 p2 p1