MATH 0322 Intermediate Algebra Unit 2

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MATH 0322 Intermediate Algebra
Unit 2
Radical Expressions
and Functions
Section: 10.1
Radical Expressions and Functions
οƒ˜ Radical expressions contain a radical sign 𝑛 ( ).
• Match the name with the correct part of
the radical expression:
radical
𝑛
π‘Ž
radicand
index
• Square Root when 𝑛 is 2: 2 ( ) → ( )
3
• Cube Root when 𝑛 is 3:
( ) ….and so on.
𝑛
οƒ˜Depending on the _____,
( ) can either be
index
an even root or an odd root.
Radical Expressions and Functions
οƒ˜Definition: The ________
Principal Square Root (p693)
π‘Ž = ____
𝑏 ,
If 𝑏2 = π‘Ž, then (___)
where π‘Ž and 𝑏 are nonnegative real numbers.
• For example:
6 2 = ____
36 inside the square root.
36 = 6 because (___)
1
9
=
1
3
because
1 2
3
=
1
____
9
inside the square root.
Radical Expressions and Functions
 − (π‘Ž) is “the negative of” square root π‘Ž.
(Not the same as square root of negative π‘Ž.)
• For example:
− 9 is read as “the negative of” 9 , so
− 9= − 9
Since 9 is a real number,
=− 3
= −3
P
then − 9 is also.
Radical Expressions and Functions
 …but, what about (−π‘Ž), not a real number
is it a real number also?
• Try to simplify using the definition of the
Principal Square Root.
?
O
O
only if −3
3 2 = ____.
−9 Is it?
?
= −3 only if −3 2 = ____.
−9 Is it?
−9 is not a real number, so in general…
−9 = 3
Radical Expressions and Functions
• Practice: Evaluate the following.
121 = 11
− 81 = −9
−4 𝒏𝒐𝒕 𝒂 𝒓𝒆𝒂𝒍 π’π’–π’Žπ’ƒπ’†π’“
49
100
=
7
10
64 + 36 = 8 + 6 = 14
9 + 16 = 25 = 5
Radical Expressions and Functions
• Use your notes to explain the following:
“Why is −25 not a real number?”
οƒ˜In general, to produce real numbers,
even roots can only operate on
radicand values that are:
P greater than or equal to zero?
A.
B.
less than or equal to zero?
• This also applies to the function 𝑓 π‘₯ = π‘₯ .
Radical Expressions and Functions
οƒ˜ Complete the table to plot the graph of 𝑓 π‘₯ = π‘₯.
𝒙≥𝟎
𝒇 𝒙 = 𝒙
(𝒙, π’š)
0
𝑓 0 = 0=0
(0,0)
1
𝑓 1 = 1=1
(1,1)
𝑓 4 = 4=2
(4,2)
∞
5
2
3
4
−∞
6
7
8
9
∞
−∞
5
𝑓 9 = 9=3
(9,3)
9
Radical Expressions and Functions
οƒ˜ The domain of a square root function 𝑓 π‘₯ = ( )
radicand be nonnegative.
requires that the ________
(Nonnegative means ≥ 0.)
οƒ˜ Practice: To find domain of 𝑓 π‘₯ = 6π‘₯ − 18
1) set the radicand ≥ 0
6π‘₯ − 18 ≥ 0
2) solve for π‘₯
6π‘₯ ≥ 18
π‘₯≥3
οƒ˜ The domain written in Interval Notation is [3, ∞).
P
Radical Expressions and Functions
οƒ˜ Definition: The Cube Root of a number
3
π‘Ž 3 = ____
𝑏
π‘Ž = 𝑏, means that (___)
real numbers have cube roots.
• All ____
3
3
3
since if 5 3 = 125.
125 = 5
−64 = −4 since if −4 3 = −64.
8
−
27
=
2
−
3
since if
οƒ˜ The domain of 𝑓 π‘₯ =
3
2 3
−
3
=
8
− .
27
real numbers.
π‘₯ is all ____
Radical Expressions and Functions
οƒ˜Suggested Practice: Form a table of squares
and cubes, then review for quicker recall of
square roots and cube roots in later sections.
π‘₯
π‘₯2
0
0
1
1
2
4
3
9
4
16
5
25
…
…
π‘₯3
0
1
8
27
64
125
…
MATH 0322 Intermediate Algebra
Unit 2
Rational Exponents
Section: 10.2
Rational Exponents
Complete the Exponent Properties below
for your notes and Formula Sheet.(p.709)
οƒ˜ Properties(π‘Ž, 𝑏 are real and π‘š, 𝑛 are rational exponents):
1)
2)
3)
π‘π‘š
βˆ™
𝑏𝑛
=_____________
π‘π‘š
= _____________
𝑏𝑛
𝑏 π‘š 𝑛 = _____________
4)
π‘Žπ‘
5)
π‘Ž 𝑛
π‘π‘š
−
6) π‘Ž
𝑛
𝑛
= _____________
Multiply like bases: keep base, add powers,
then simplify
Divide like bases: keep base, subtract powers,
then simplify
Power to power: keep base, multiply powers,
then simplify
Product to power: raise each factor to power,
then simplify
= _____________
Quotient to power: raise numerator and
denominator to power, then simplify
= _____________
Negative power: take reciprocal of base,
π’Ž
𝒏
𝒂 must be nonzero
Rational Exponents
fraction form.
• Rational exponents: exponents in _______
4
5
1
2
2
3
Example: 9 , (−32) , (16π‘₯ 3 )
οƒ˜ Definition:
1
𝑛
π‘Ž =
𝑛
π‘Ž
Radical notation
Rational Exponent
notation
• If index is even, radicand must be ≥ 0.
81 = 81P
(−25) = −25
P
O
• If index is odd, radicand can be any real number.
0 = 0P
32 = 32P
(−128) = −128P
1
6
6
1
3
3
0 =
0
1
4
4
1
5
5
1
2
1
7
7
Rational Exponents
• Practice: Use the previous definition to rewrite
in radical notation, then simplify.
1
𝑛
π‘Ž =
1
4
81 =
4
π‘Ž
81 =
P
4
3βˆ™3βˆ™3βˆ™3 =3
1
3
3
−64 =
1
5
5
7π‘₯ 𝑦 =
(−64) =
(7π‘₯ 4 𝑦)
𝑛
=
4
3
P
(−4) βˆ™ (−4) βˆ™ (−4) = −4
P
5
7βˆ™π‘₯βˆ™π‘₯βˆ™π‘₯βˆ™π‘₯βˆ™π‘¦
Rational Exponents
• Practice: Use the previous definition to only
rewrite in rational exponent notation.
𝑛
4
5
3
π‘Ž=π‘Ž
1
𝑛
21 = 21
𝑀3
6
1
4
1
3 5
=
𝑀
6
−5π‘₯𝑦 =
P
P
−5π‘₯𝑦
1
3
P
Rational Exponents
• Numerator of rational exponent can be > 1.
4
5
3
2
Example: 9 , (−32) ,
π‘š
𝑛
οƒ˜Definition: If π‘Ž is real and
reduced, then

π‘š
𝑛
π‘Ž =
π‘š
𝑛
 andt π‘Ž =
𝑛
𝑛
π‘Ž
π‘Žπ‘š
π‘š
π‘š
𝑛
2
(16π‘₯ 3 )7
is positive and
This form will be easier to
work with.
Rational Exponents
• Practice: Evaluate using definitions only.
π‘š
𝑛
π‘Ž =
No calculator.
𝑛
π‘š
𝑛
π‘Žπ‘š
3
5
𝑛
and π‘Ž =
Exp. Prop. #6
2
125
3
4
=
π‘š
P…?
= )3 P
32
= …?
= −27 P
3
5
3
3
3
−32768
(−32)
= −2
(−32)
= −8=
−32 =
55
(−32) =
−3
π‘Ž
2
33
−81 = −
𝟏𝟏 2
33
(−32)
πŸπŸπŸ“
πŸπŸπŸ“
3
4
3
𝟏
(11 ) == 1πŸ“ (
81
1
𝟏
𝟏
πŸπŸ“πŸ”πŸπŸ“ πŸπŸ“
2
=− 3
3
Rational Exponents
• Practice: Simplify using properties.
Property
1
2
3
2
Expo.
Prop. #1
6 βˆ™6 =
Expo.
Prop. #2
7
86
5
86
Expo.
Prop. #6
3
1
1 33
+ )
( 2+
2
6 22
7
1 35
− )
( 2+
2
=8
−
16
1
4
6
6
=
P
=8
= 8=2P
1 = P
12
(2)
=8
6
1 1
43
= ( )4 =
16
125π‘₯ 6 =
14
6( 2 )
1
(125π‘₯
125π‘₯6 ) 3
11
(2)
3
3
𝟏
(
)
πŸπŸ”
=
= 6(2) = 36
𝟏
𝟐
1
6
(2
)
3 6) 3
( (5)
1 25π‘₯
5
π‘₯
1 1
2 1
3
3βˆ™ 3
= (5
5) 1( π‘₯5)633 βˆ™ 31
= 5π‘₯ 2
P
Rational Exponents
Practice and Complete
HW10.2
MATH 0322 Intermediate Algebra
Unit 2
Multiplying and Simplifying
Radical Expressions
Section: 10.3
Multiplying and Simplifying
Radical Expressions
• To multiply and simplify Radical Expressions,
you must learn to use:
1) Factoring
2) Product Rule for Radicals
• Compare the following:
a)
4 βˆ™ 25 = 100 = 10
4 βˆ™ 25 = 2
βˆ™5
P
= 10
3
b)
3
3
8 βˆ™ 27 =
3
216 = 6
3
8 βˆ™ 27 = 2
βˆ™3
Since 4 βˆ™ 25 = 4 βˆ™ 25 and 8 βˆ™ 27 =
Even and Odd Roots seem to follow the
same type of rule for multiplication.
3
3
P
=6
8 βˆ™ 27,
Multiplying and Simplifying
Radical Expressions
οƒ˜ Definition: Product Rule for Radicals
If
𝑛
π‘Ž and
𝑛
𝑏 are real numbers,
𝑛
𝑛
𝑛
then
π‘Žβˆ™ 𝑏 ⇔ π‘Žβˆ™π‘.
(*index 𝑛 must be the same.)
Practice: Multiply and simplify.
3
5 βˆ™ 11
=
3
5 βˆ™ 11
=
3
55
a)
3
P
b)
π‘₯+3βˆ™ π‘₯−3
=
(π‘₯ + 3) βˆ™ (π‘₯ − 3)
=
π‘₯2
−9
P
c)
=
=
7
3π‘₯ 2
7
7
3π‘₯ 2 βˆ™ 18π‘₯ 3
7
54π‘₯ 5
βˆ™ 18π‘₯ 3
P
Multiplying and Simplifying
Radical Expressions
• Question?
Can the radicals below be multiplied directly?
3
6βˆ™ 7
No, the index 𝑛 must be the same.
• Question?
Is π‘₯ 2 − 9 the same as π‘₯ 2 − 9?
Let π‘₯ = 5 to find out.(read p716)
Multiplying and Simplifying
Radical Expressions
• Simplify the Radical Expression by Factoring
and the Product Rule: ? 3 2 βˆ™ 40 ? 3 5 βˆ™ 16
3
3
3
4
βˆ™
20
?
8 βˆ™ 10
?
80
3
3
80 = 8 βˆ™ 10
1) Factor radicand.
P
…make sure one factor of 80 is the
largest perfect 𝒄𝒖𝒃𝒆.
2) Apply Product Rule.
3) Simplify.
=
3
3
8 βˆ™ 10
3
= 2 βˆ™ 10
3
= 2 10
P
Multiplying and Simplifying
Radical Expressions
• Simplify the Radical Expression by Factoring
and the Product Rule:
5
64
5
5
64 = 32 βˆ™ 2
1) Factor radicand.
…make sure one factor is the
largest perfect 5π‘‘β„Ž power of 64.
2) Apply Product Rule.
3) Simplify.
=
5
5
32 βˆ™ 2
5
=2βˆ™ 2
5
=2 2
P
Multiplying and Simplifying
Radical Expressions
• Simplify the Radical Expression by Factoring
and the Product Rule:
500π‘₯𝑦 2
1) Factor radicand.
500π‘₯𝑦 2 = 100 βˆ™ 5 βˆ™ π‘₯ βˆ™ 𝑦 2
=
100 βˆ™ 𝑦 2 βˆ™ 5 βˆ™ π‘₯
2) Apply Product Rule.
=
100𝑦 2 βˆ™ 5π‘₯
3) Simplify.
= 10 𝑦 βˆ™ 5π‘₯
p.696: Simplifying π‘Ž2
= 10 𝑦 5π‘₯
P
MATH 0322 Intermediate Algebra
Unit 2
Adding, Subtracting, Dividing
Radical Expressions
Section: 10.4
Adding, Subtracting, Dividing
Radical Expressions
• When adding or subtracting variable expressions,
like terms can be combined.
only ___
• In this section, like radical terms have:
index
1) the same _____
radicand
2) and the same ________.
• When combining like radical terms,
only the __________
coefficients are added or subtracted.
3
3
3
3
P
Example: 6 2π‘₯ + 5 2π‘₯ = 6 + 5 2π‘₯ = 11 2π‘₯
3
Example: 6 2π‘₯ + 5 2π‘₯ = Can’t simplify, index not the same
3
3
Example: 6 7π‘₯ + 5 2π‘₯ = Can’t simplify, radicand not the same
Adding, Subtracting, Dividing
Radical Expressions
Practice: Simplify by combining like radical terms.
3
3
3
3
P
a)
9 5+ 5 = 9+1
b)
6 π‘₯ + 1 − 4 π‘₯ + 1 + 7 π‘₯ + 1 = (6 − 4 + 7) π‘₯ + 1
5 = 10 5
=9 π‘₯+1
c)
=
7
3π‘₯ 2
7
3π‘₯ 2
7
18π‘₯ 3
7
3π‘₯ 2
7
3π‘₯ 2
+2
+4
= (1 + 4)
P
7
+ 4 3π‘₯ 2
7
+ 2 18π‘₯ 3
+2
7
18π‘₯ 3
=5
7
3π‘₯ 2
7
+ 2 18π‘₯ 3
P
Adding, Subtracting, Dividing
Radical Expressions
Practice: Simplify by combining like radical terms,
if possible.
a)
b)
5 12 − 6 27 = 5 4 βˆ™ 3 − 6 9 βˆ™ 3
factor
factor = 5 βˆ™ 2 3 − 6 βˆ™ 3 βˆ™ 3
= 10 3 − 18 3 = −8 3
3
5
7 2+9 2
Cannot be simplified.
P
P
Adding, Subtracting, Dividing
Radical Expressions
• Compare the following:
a)
36
4
36
4
= 9 =3
=
6
2
P
=3
b)
3
3
3
64
=
8
3
64
4
2
8
=
8 =2
=2
What do you notice?
Looks like a Rule for Dividing Radicals!
P
Adding, Subtracting, Dividing
Radical Expressions
οƒ˜ Definition: Quotient Rule for Radicals
If
𝑛
π‘Ž and
then
𝑛
π‘Ž
𝑏
𝑛
𝑏 are real numbers and 𝑏 ≠ 0,
⇔
𝑛
π‘Ž
𝑛
𝑏
.
Read the “Great Question!” on page 727.
Adding, Subtracting, Dividing
Radical Expressions
Practice: Simplify using the Quotient Rule.
(Assume all variables represent positive real numbers.)
50
81
a)
Not square
Square
Factor
=
50
81
=
25βˆ™2
81
=
5 2
9
P
b)
3
=
27π‘₯ 8
𝑦 12
3
27βˆ™π‘₯ 8
3
𝑦 12
3
=
c)
3π‘₯
π‘₯2 π‘₯ 2
3
𝑦4
P
500π‘₯ 3
20π‘₯ −1
=
500π‘₯ 3
20π‘₯ −1
=
25π‘₯π‘₯33−(−1)
= 25π‘₯ 4
= 5π‘₯ 2
P
MATH 0322 Intermediate Algebra
Unit 2
Radical Equations
Section: 10.6
Radical Equations
• In this section, students will be asked to solve
Radical Equations by using:
Properties
of Exponents and Radicals,
P
Factoring
skills, Product Rule, Quotient Rule
P
and
P learned strategies for simplifying radical expressions.
• Radical Equation: an equation containing a
radicand of a radical expression.
variable in the ________
Examples:
π‘₯ + 3 = 6,
π‘₯ − 8 = π‘₯ − 2,
3
2π‘₯ − 1 + 5 = 0
Radical Equations
• Think about what you already know about
…to…..hmmm,
get π‘₯ = 16,
the
value
of
π‘₯
in
the
following
equation?
How
the
…so
this
how I
π‘Ž = to
𝑏
…but
ifcan
Iissquare
I need
definition
of
can
solve
get
onlysquare
if π‘Ž = 4,…
𝑏 2 ….
the
right to
side,
π‘₯ = 4
𝑏…
π‘₯ π‘Ž=
I have
to=16
square
help
solve
for π‘₯?
Fan-tastic!
the
left side.
π‘₯ 2= 4 2
π‘₯ = 16
π‘₯ has to be 16,
because 16 = 4.
Radical Equations
• To solve a Radical Equation:
1) isolate the radical,
2) raise both sides to the 𝑛th power and simplify,
3) solve, then check solution(s).
(If equation contains more than one radical,
repeat Steps 1 & 2 until all radicals are eliminated.)
Radical Equations
Practice: Solve.
a)
Check:
3π‘₯ + 4 2 = 8
3π‘₯ + 4 = 64
3π‘₯ = 60
π‘₯ = 20
2
Step 1)
Step 2)
Step 3)
3(20)
20 + 4 = 8
60 + 4 = 8
P 64 = 8
P
Your turn.
3
b)
6π‘₯ − 3 3= 3
6π‘₯ − 3 = 27
6π‘₯ = 30
π‘₯=5
3
P
Check:
Radical Equations
Practice: Solve.
Check:
Step 1)
2π‘₯ − 1 − 4 = 3
2π‘₯ − 1 2= 7 2 Step 2)
2π‘₯ − 1 = 49 Step 3)
2π‘₯ = 50
π‘₯ = 25
Your turn.
b)
6π‘₯ + 3 + 15 = 24
6π‘₯ + 3 2= 9 2
6π‘₯ + 3 = 81
6π‘₯ = 78
π‘₯ = 13
2 20
25 − 1 − 4 = 3
a)
P
P
50 − 1 − 4 = 3
49 − 4 = 3
7−4=3
P
Check:
Radical Equations
Practice: Solve.
Check:
Step 1)
π‘₯−1+7 =2
20
26 − 1 + 7 = 2
π‘₯ − 1 2= −5 2 Step 2)
25 + 7 = 2
Step 3)
π‘₯ − 1 = 25
5+7=2
π‘₯ = 26
This is considered an “extraneous solution”.(See p745)
Your turn.
b)
7π‘₯ + 8 + 15 = 9
Did you figure out when it
would not have a solution?
7π‘₯ + 8 2 = −6 2
7π‘₯ + 8 = 36
7π‘₯ = 28
Check:
π‘₯=4
“extraneous solution”
a)
O
O
O
Radical Equations
Practice: Solve.
a)
6π‘₯ + 7 − π‘₯ = 2
6π‘₯ + 7 2 = π‘₯ + 2 2
6π‘₯ + 7 = π‘₯ 2 + 4π‘₯ + 4
7 = π‘₯ 2 − 2π‘₯ + 4
Step 1)
Step 2)
Step 3) Need Quadratic
Equation in Standard Form.
0 = π‘₯ 2 − 2π‘₯ − 3 Factor
0 = (π‘₯ − 3)(π‘₯ + 1)
π‘₯−3 =0
π‘₯=3
π‘₯+1 =0
π‘₯ = −1
P
P
Don’t forget to check for “extraneous solutions”.
Radical Equations
Practice: Solve.
b)
6π‘₯ + 2 − 5π‘₯ + 3 = 0
Step 1)
6π‘₯ + 2 2 =
Step 2)
5π‘₯ + 3
6π‘₯ + 2 = 5π‘₯ + 3
π‘₯+2=3
P
2
Step 3)
π‘₯=1
Don’t forget to check for “extraneous solutions”.
Radical Equations
Complete and
Practice HW 10.6.
MATH 0322 Intermediate Algebra
Unit 2
Complex Numbers
Section: 10.7
Complex Numbers
• In this section, students complete Chapter 10
by learning:
P
P
P
 what a Complex Number is,
 the components of a Complex Number,
 and how to operate with Complex Numbers.
• To prepare, we revisit −4 in Section 10.1.
Was −4 a real number? Yes or No
radicand must
Why? For even roots, the ________
be non-negative.
Complex Numbers
 Complex numbers: A number of the form
π‘Ž + 𝑏𝑖
imaginary part
real part
 where π‘Ž and 𝑏 are real number coefficients,
 and 𝑖 is the imaginary unit.
P
P
οƒ˜ Definition: 𝑖 = −1
𝑖 2 = −1
𝑖 2 = −1
So what is
−4 ?
2
Product Rule
−4 = 4 βˆ™ −1 = 4 βˆ™ −1
= 2𝑖
imaginary
The square root of a negative number is ________.
 You will see this again in College Algebra.(learn it well)
Complex Numbers
Practice: Write as a multiple of 𝑖.
a)
−81
= 81 βˆ™ −1
= 81 βˆ™ −1
= 9𝑖
P
b)
−26
c)
−45
= 26 βˆ™ −1
= 2 βˆ™ 13 βˆ™ −1
= 45 βˆ™ −1
= 9 βˆ™ 5 βˆ™ −1
= 26 βˆ™ −1
= 9 βˆ™ 5 βˆ™ −1
= 26 𝑖
P
=3 5𝑖
P = 3𝑖
5
Your turn.
d)
−16
= 4𝑖
P
e)
−35
= 35 𝑖
P
f)
−28
=2 7𝑖
P = 2𝑖
7
Complex Numbers
 Operations with Complex numbers.
 To add or subtract, combine only like terms.
 To multiply, use Distributive Property with 𝑖 2 = −1.
 To divide, use a Conjugate to rationalize denominator.
οƒ˜ The conjugate of 2 − 5𝑖 is _______.
2 + 5𝑖
−4 − 9𝑖
οƒ˜ The conjugate of −4 + 9𝑖 is ________.
−3𝑖
οƒ˜ The conjugate of 3𝑖 is _____.
 All important in College Algebra-Chapter 5.
Complex Numbers
Practice: Perform the indicated operations.
Write the result in the form π‘Ž + 𝑏𝑖.
Combine like terms.
a)
2 − 𝑖 + (−6 + 3𝑖)
Real parts
b)
Imaginary parts
(2) + (−6) (−𝑖) + (3𝑖)
(−4)
(2𝑖)
+
−4 + 2𝑖
P
Your turn.
c) 9 − 5𝑖 + (−2 + 8𝑖)
7 + 3𝑖
P
−1 + 4𝑖 − (5 + 8𝑖)
−1 + 4𝑖 + (−5 − 8𝑖)
Real parts
Imaginary parts
(−1) + (−5) (4𝑖) + (−8𝑖)
(−6)
+
(−4𝑖)
−6 − 4𝑖
P
d)
−3 + 7𝑖 − (6 + 2𝑖)
−9 + 5𝑖
P
Complex Numbers
Practice: Perform the indicated operations.
Write the result in the form π‘Ž + 𝑏𝑖.
a) 5𝑖(−6 + 3𝑖)
b)
Distribute.
Distribute(FOIL).
−5 −4𝑖 +10𝑖 +8𝑖 2
−5 + 6𝑖 + 8𝑖 2
−5 + 6𝑖 + 8(−1)
−5 + 6𝑖 − 8
−13 + 6𝑖
−30𝑖 +15𝑖 2
−30𝑖 + 15(−1)
−15 − 30𝑖
P
Your turn.
c) 2𝑖(4 + 3𝑖)
−6 + 8𝑖
−1 + 2𝑖 (5 + 4𝑖)
P
P
d)
2 − 8𝑖 (−1 + 6𝑖)
46 + 20𝑖
P
Complex Numbers
Practice: Divide and simplify to form π‘Ž + 𝑏𝑖.
a)
2+𝑖 βˆ™
5−3𝑖5+3𝑖
Rationalize denominator
5+3𝑖
by multiplying conjugate.
=
10 + 6𝑖 + 5𝑖 + 3𝑖 2
25 + 15𝑖 − 15𝑖 − 9𝑖 2
=
10+11𝑖+3(−1)
25−9(−1)
=
10+11𝑖−3
25+9
=
=
7+11𝑖
34
7
11
+ 𝑖
34
34
P
Radical Equations
Complete and
Practice HW 10.7.
to prepare for Ch10 Exam.
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