MATH 0322 Intermediate Algebra Unit 2 Radical Expressions and Functions Section: 10.1 Radical Expressions and Functions ο Radical expressions contain a radical sign π ( ). • Match the name with the correct part of the radical expression: radical π π radicand index • Square Root when π is 2: 2 ( ) → ( ) 3 • Cube Root when π is 3: ( ) ….and so on. π οDepending on the _____, ( ) can either be index an even root or an odd root. Radical Expressions and Functions οDefinition: The ________ Principal Square Root (p693) π = ____ π , If π2 = π, then (___) where π and π are nonnegative real numbers. • For example: 6 2 = ____ 36 inside the square root. 36 = 6 because (___) 1 9 = 1 3 because 1 2 3 = 1 ____ 9 inside the square root. Radical Expressions and Functions οΆ − (π) is “the negative of” square root π. (Not the same as square root of negative π.) • For example: − 9 is read as “the negative of” 9 , so − 9= − 9 Since 9 is a real number, =− 3 = −3 P then − 9 is also. Radical Expressions and Functions οΆ …but, what about (−π), not a real number is it a real number also? • Try to simplify using the definition of the Principal Square Root. ? O O only if −3 3 2 = ____. −9 Is it? ? = −3 only if −3 2 = ____. −9 Is it? −9 is not a real number, so in general… −9 = 3 Radical Expressions and Functions • Practice: Evaluate the following. 121 = 11 − 81 = −9 −4 πππ π ππππ ππππππ 49 100 = 7 10 64 + 36 = 8 + 6 = 14 9 + 16 = 25 = 5 Radical Expressions and Functions • Use your notes to explain the following: “Why is −25 not a real number?” οIn general, to produce real numbers, even roots can only operate on radicand values that are: P greater than or equal to zero? A. B. less than or equal to zero? • This also applies to the function π π₯ = π₯ . Radical Expressions and Functions ο Complete the table to plot the graph of π π₯ = π₯. π≥π π π = π (π, π) 0 π 0 = 0=0 (0,0) 1 π 1 = 1=1 (1,1) π 4 = 4=2 (4,2) ∞ 5 2 3 4 −∞ 6 7 8 9 ∞ −∞ 5 π 9 = 9=3 (9,3) 9 Radical Expressions and Functions ο The domain of a square root function π π₯ = ( ) radicand be nonnegative. requires that the ________ (Nonnegative means ≥ 0.) ο Practice: To find domain of π π₯ = 6π₯ − 18 1) set the radicand ≥ 0 6π₯ − 18 ≥ 0 2) solve for π₯ 6π₯ ≥ 18 π₯≥3 ο The domain written in Interval Notation is [3, ∞). P Radical Expressions and Functions ο Definition: The Cube Root of a number 3 π 3 = ____ π π = π, means that (___) real numbers have cube roots. • All ____ 3 3 3 since if 5 3 = 125. 125 = 5 −64 = −4 since if −4 3 = −64. 8 − 27 = 2 − 3 since if ο The domain of π π₯ = 3 2 3 − 3 = 8 − . 27 real numbers. π₯ is all ____ Radical Expressions and Functions οSuggested Practice: Form a table of squares and cubes, then review for quicker recall of square roots and cube roots in later sections. π₯ π₯2 0 0 1 1 2 4 3 9 4 16 5 25 … … π₯3 0 1 8 27 64 125 … MATH 0322 Intermediate Algebra Unit 2 Rational Exponents Section: 10.2 Rational Exponents Complete the Exponent Properties below for your notes and Formula Sheet.(p.709) ο Properties(π, π are real and π, π are rational exponents): 1) 2) 3) ππ β ππ =_____________ ππ = _____________ ππ π π π = _____________ 4) ππ 5) π π ππ − 6) π π π = _____________ Multiply like bases: keep base, add powers, then simplify Divide like bases: keep base, subtract powers, then simplify Power to power: keep base, multiply powers, then simplify Product to power: raise each factor to power, then simplify = _____________ Quotient to power: raise numerator and denominator to power, then simplify = _____________ Negative power: take reciprocal of base, π π π must be nonzero Rational Exponents fraction form. • Rational exponents: exponents in _______ 4 5 1 2 2 3 Example: 9 , (−32) , (16π₯ 3 ) ο Definition: 1 π π = π π Radical notation Rational Exponent notation • If index is even, radicand must be ≥ 0. 81 = 81P (−25) = −25 P O • If index is odd, radicand can be any real number. 0 = 0P 32 = 32P (−128) = −128P 1 6 6 1 3 3 0 = 0 1 4 4 1 5 5 1 2 1 7 7 Rational Exponents • Practice: Use the previous definition to rewrite in radical notation, then simplify. 1 π π = 1 4 81 = 4 π 81 = P 4 3β3β3β3 =3 1 3 3 −64 = 1 5 5 7π₯ π¦ = (−64) = (7π₯ 4 π¦) π = 4 3 P (−4) β (−4) β (−4) = −4 P 5 7βπ₯βπ₯βπ₯βπ₯βπ¦ Rational Exponents • Practice: Use the previous definition to only rewrite in rational exponent notation. π 4 5 3 π=π 1 π 21 = 21 π€3 6 1 4 1 3 5 = π€ 6 −5π₯π¦ = P P −5π₯π¦ 1 3 P Rational Exponents • Numerator of rational exponent can be > 1. 4 5 3 2 Example: 9 , (−32) , π π οDefinition: If π is real and reduced, then ο§ π π π = π π ο§ andt π = π π π ππ π π π 2 (16π₯ 3 )7 is positive and This form will be easier to work with. Rational Exponents • Practice: Evaluate using definitions only. π π π = No calculator. π π π ππ 3 5 π and π = Exp. Prop. #6 2 125 3 4 = π P…? = )3 P 32 = …? = −27 P 3 5 3 3 3 −32768 (−32) = −2 (−32) = −8= −32 = 55 (−32) = −3 π 2 33 −81 = − ππ 2 33 (−32) πππ πππ 3 4 3 π (11 ) == 1π ( 81 1 π π πππππ ππ 2 =− 3 3 Rational Exponents • Practice: Simplify using properties. Property 1 2 3 2 Expo. Prop. #1 6 β6 = Expo. Prop. #2 7 86 5 86 Expo. Prop. #6 3 1 1 33 + ) ( 2+ 2 6 22 7 1 35 − ) ( 2+ 2 =8 − 16 1 4 6 6 = P =8 = 8=2P 1 = P 12 (2) =8 6 1 1 43 = ( )4 = 16 125π₯ 6 = 14 6( 2 ) 1 (125π₯ 125π₯6 ) 3 11 (2) 3 3 π ( ) ππ = = 6(2) = 36 π π 1 6 (2 ) 3 6) 3 ( (5) 1 25π₯ 5 π₯ 1 1 2 1 3 3β 3 = (5 5) 1( π₯5)633 β 31 = 5π₯ 2 P Rational Exponents Practice and Complete HW10.2 MATH 0322 Intermediate Algebra Unit 2 Multiplying and Simplifying Radical Expressions Section: 10.3 Multiplying and Simplifying Radical Expressions • To multiply and simplify Radical Expressions, you must learn to use: 1) Factoring 2) Product Rule for Radicals • Compare the following: a) 4 β 25 = 100 = 10 4 β 25 = 2 β5 P = 10 3 b) 3 3 8 β 27 = 3 216 = 6 3 8 β 27 = 2 β3 Since 4 β 25 = 4 β 25 and 8 β 27 = Even and Odd Roots seem to follow the same type of rule for multiplication. 3 3 P =6 8 β 27, Multiplying and Simplifying Radical Expressions ο Definition: Product Rule for Radicals If π π and π π are real numbers, π π π then πβ π ⇔ πβπ. (*index π must be the same.) Practice: Multiply and simplify. 3 5 β 11 = 3 5 β 11 = 3 55 a) 3 P b) π₯+3β π₯−3 = (π₯ + 3) β (π₯ − 3) = π₯2 −9 P c) = = 7 3π₯ 2 7 7 3π₯ 2 β 18π₯ 3 7 54π₯ 5 β 18π₯ 3 P Multiplying and Simplifying Radical Expressions • Question? Can the radicals below be multiplied directly? 3 6β 7 No, the index π must be the same. • Question? Is π₯ 2 − 9 the same as π₯ 2 − 9? Let π₯ = 5 to find out.(read p716) Multiplying and Simplifying Radical Expressions • Simplify the Radical Expression by Factoring and the Product Rule: ? 3 2 β 40 ? 3 5 β 16 3 3 3 4 β 20 ? 8 β 10 ? 80 3 3 80 = 8 β 10 1) Factor radicand. P …make sure one factor of 80 is the largest perfect ππππ. 2) Apply Product Rule. 3) Simplify. = 3 3 8 β 10 3 = 2 β 10 3 = 2 10 P Multiplying and Simplifying Radical Expressions • Simplify the Radical Expression by Factoring and the Product Rule: 5 64 5 5 64 = 32 β 2 1) Factor radicand. …make sure one factor is the largest perfect 5π‘β power of 64. 2) Apply Product Rule. 3) Simplify. = 5 5 32 β 2 5 =2β 2 5 =2 2 P Multiplying and Simplifying Radical Expressions • Simplify the Radical Expression by Factoring and the Product Rule: 500π₯π¦ 2 1) Factor radicand. 500π₯π¦ 2 = 100 β 5 β π₯ β π¦ 2 = 100 β π¦ 2 β 5 β π₯ 2) Apply Product Rule. = 100π¦ 2 β 5π₯ 3) Simplify. = 10 π¦ β 5π₯ p.696: Simplifying π2 = 10 π¦ 5π₯ P MATH 0322 Intermediate Algebra Unit 2 Adding, Subtracting, Dividing Radical Expressions Section: 10.4 Adding, Subtracting, Dividing Radical Expressions • When adding or subtracting variable expressions, like terms can be combined. only ___ • In this section, like radical terms have: index 1) the same _____ radicand 2) and the same ________. • When combining like radical terms, only the __________ coefficients are added or subtracted. 3 3 3 3 P Example: 6 2π₯ + 5 2π₯ = 6 + 5 2π₯ = 11 2π₯ 3 Example: 6 2π₯ + 5 2π₯ = Can’t simplify, index not the same 3 3 Example: 6 7π₯ + 5 2π₯ = Can’t simplify, radicand not the same Adding, Subtracting, Dividing Radical Expressions Practice: Simplify by combining like radical terms. 3 3 3 3 P a) 9 5+ 5 = 9+1 b) 6 π₯ + 1 − 4 π₯ + 1 + 7 π₯ + 1 = (6 − 4 + 7) π₯ + 1 5 = 10 5 =9 π₯+1 c) = 7 3π₯ 2 7 3π₯ 2 7 18π₯ 3 7 3π₯ 2 7 3π₯ 2 +2 +4 = (1 + 4) P 7 + 4 3π₯ 2 7 + 2 18π₯ 3 +2 7 18π₯ 3 =5 7 3π₯ 2 7 + 2 18π₯ 3 P Adding, Subtracting, Dividing Radical Expressions Practice: Simplify by combining like radical terms, if possible. a) b) 5 12 − 6 27 = 5 4 β 3 − 6 9 β 3 factor factor = 5 β 2 3 − 6 β 3 β 3 = 10 3 − 18 3 = −8 3 3 5 7 2+9 2 Cannot be simplified. P P Adding, Subtracting, Dividing Radical Expressions • Compare the following: a) 36 4 36 4 = 9 =3 = 6 2 P =3 b) 3 3 3 64 = 8 3 64 4 2 8 = 8 =2 =2 What do you notice? Looks like a Rule for Dividing Radicals! P Adding, Subtracting, Dividing Radical Expressions ο Definition: Quotient Rule for Radicals If π π and then π π π π π are real numbers and π ≠ 0, ⇔ π π π π . Read the “Great Question!” on page 727. Adding, Subtracting, Dividing Radical Expressions Practice: Simplify using the Quotient Rule. (Assume all variables represent positive real numbers.) 50 81 a) Not square Square Factor = 50 81 = 25β2 81 = 5 2 9 P b) 3 = 27π₯ 8 π¦ 12 3 27βπ₯ 8 3 π¦ 12 3 = c) 3π₯ π₯2 π₯ 2 3 π¦4 P 500π₯ 3 20π₯ −1 = 500π₯ 3 20π₯ −1 = 25π₯π₯33−(−1) = 25π₯ 4 = 5π₯ 2 P MATH 0322 Intermediate Algebra Unit 2 Radical Equations Section: 10.6 Radical Equations • In this section, students will be asked to solve Radical Equations by using: ο±Properties of Exponents and Radicals, P ο±Factoring skills, Product Rule, Quotient Rule P ο±and P learned strategies for simplifying radical expressions. • Radical Equation: an equation containing a radicand of a radical expression. variable in the ________ Examples: π₯ + 3 = 6, π₯ − 8 = π₯ − 2, 3 2π₯ − 1 + 5 = 0 Radical Equations • Think about what you already know about …to…..hmmm, get π₯ = 16, the value of π₯ in the following equation? How the …so this how I π = to π …but ifcan Iissquare I need definition of can solve get onlysquare if π = 4,… π 2 …. the right to side, π₯ = 4 π… π₯ π= I have to=16 square help solve for π₯? Fan-tastic! the left side. π₯ 2= 4 2 π₯ = 16 π₯ has to be 16, because 16 = 4. Radical Equations • To solve a Radical Equation: 1) isolate the radical, 2) raise both sides to the πth power and simplify, 3) solve, then check solution(s). οΆ(If equation contains more than one radical, repeat Steps 1 & 2 until all radicals are eliminated.) Radical Equations Practice: Solve. a) Check: 3π₯ + 4 2 = 8 3π₯ + 4 = 64 3π₯ = 60 π₯ = 20 2 Step 1) Step 2) Step 3) 3(20) 20 + 4 = 8 60 + 4 = 8 P 64 = 8 P Your turn. 3 b) 6π₯ − 3 3= 3 6π₯ − 3 = 27 6π₯ = 30 π₯=5 3 P Check: Radical Equations Practice: Solve. Check: Step 1) 2π₯ − 1 − 4 = 3 2π₯ − 1 2= 7 2 Step 2) 2π₯ − 1 = 49 Step 3) 2π₯ = 50 π₯ = 25 Your turn. b) 6π₯ + 3 + 15 = 24 6π₯ + 3 2= 9 2 6π₯ + 3 = 81 6π₯ = 78 π₯ = 13 2 20 25 − 1 − 4 = 3 a) P P 50 − 1 − 4 = 3 49 − 4 = 3 7−4=3 P Check: Radical Equations Practice: Solve. Check: Step 1) π₯−1+7 =2 20 26 − 1 + 7 = 2 π₯ − 1 2= −5 2 Step 2) 25 + 7 = 2 Step 3) π₯ − 1 = 25 5+7=2 π₯ = 26 This is considered an “extraneous solution”.(See p745) Your turn. b) 7π₯ + 8 + 15 = 9 Did you figure out when it would not have a solution? 7π₯ + 8 2 = −6 2 7π₯ + 8 = 36 7π₯ = 28 Check: π₯=4 “extraneous solution” a) O O O Radical Equations Practice: Solve. a) 6π₯ + 7 − π₯ = 2 6π₯ + 7 2 = π₯ + 2 2 6π₯ + 7 = π₯ 2 + 4π₯ + 4 7 = π₯ 2 − 2π₯ + 4 Step 1) Step 2) Step 3) Need Quadratic Equation in Standard Form. 0 = π₯ 2 − 2π₯ − 3 Factor 0 = (π₯ − 3)(π₯ + 1) π₯−3 =0 π₯=3 π₯+1 =0 π₯ = −1 P P Don’t forget to check for “extraneous solutions”. Radical Equations Practice: Solve. b) 6π₯ + 2 − 5π₯ + 3 = 0 Step 1) 6π₯ + 2 2 = Step 2) 5π₯ + 3 6π₯ + 2 = 5π₯ + 3 π₯+2=3 P 2 Step 3) π₯=1 Don’t forget to check for “extraneous solutions”. Radical Equations Complete and Practice HW 10.6. MATH 0322 Intermediate Algebra Unit 2 Complex Numbers Section: 10.7 Complex Numbers • In this section, students complete Chapter 10 by learning: P P P ο± what a Complex Number is, ο± the components of a Complex Number, ο± and how to operate with Complex Numbers. • To prepare, we revisit −4 in Section 10.1. Was −4 a real number? Yes or No radicand must Why? For even roots, the ________ be non-negative. Complex Numbers ο± Complex numbers: A number of the form π + ππ imaginary part real part ο§ where π and π are real number coefficients, ο§ and π is the imaginary unit. P P ο Definition: π = −1 π 2 = −1 π 2 = −1 So what is −4 ? 2 Product Rule −4 = 4 β −1 = 4 β −1 = 2π imaginary The square root of a negative number is ________. οΆ You will see this again in College Algebra.(learn it well) Complex Numbers Practice: Write as a multiple of π. a) −81 = 81 β −1 = 81 β −1 = 9π P b) −26 c) −45 = 26 β −1 = 2 β 13 β −1 = 45 β −1 = 9 β 5 β −1 = 26 β −1 = 9 β 5 β −1 = 26 π P =3 5π P = 3π 5 Your turn. d) −16 = 4π P e) −35 = 35 π P f) −28 =2 7π P = 2π 7 Complex Numbers ο± Operations with Complex numbers. ο§ To add or subtract, combine only like terms. ο§ To multiply, use Distributive Property with π 2 = −1. ο§ To divide, use a Conjugate to rationalize denominator. ο The conjugate of 2 − 5π is _______. 2 + 5π −4 − 9π ο The conjugate of −4 + 9π is ________. −3π ο The conjugate of 3π is _____. οΆ All important in College Algebra-Chapter 5. Complex Numbers Practice: Perform the indicated operations. Write the result in the form π + ππ. Combine like terms. a) 2 − π + (−6 + 3π) Real parts b) Imaginary parts (2) + (−6) (−π) + (3π) (−4) (2π) + −4 + 2π P Your turn. c) 9 − 5π + (−2 + 8π) 7 + 3π P −1 + 4π − (5 + 8π) −1 + 4π + (−5 − 8π) Real parts Imaginary parts (−1) + (−5) (4π) + (−8π) (−6) + (−4π) −6 − 4π P d) −3 + 7π − (6 + 2π) −9 + 5π P Complex Numbers Practice: Perform the indicated operations. Write the result in the form π + ππ. a) 5π(−6 + 3π) b) Distribute. Distribute(FOIL). −5 −4π +10π +8π 2 −5 + 6π + 8π 2 −5 + 6π + 8(−1) −5 + 6π − 8 −13 + 6π −30π +15π 2 −30π + 15(−1) −15 − 30π P Your turn. c) 2π(4 + 3π) −6 + 8π −1 + 2π (5 + 4π) P P d) 2 − 8π (−1 + 6π) 46 + 20π P Complex Numbers Practice: Divide and simplify to form π + ππ. a) 2+π β 5−3π5+3π Rationalize denominator 5+3π by multiplying conjugate. = 10 + 6π + 5π + 3π 2 25 + 15π − 15π − 9π 2 = 10+11π+3(−1) 25−9(−1) = 10+11π−3 25+9 = = 7+11π 34 7 11 + π 34 34 P Radical Equations Complete and Practice HW 10.7. to prepare for Ch10 Exam.