6-3/6-4 Elimination

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Goal: Solve systems of linear equations
using elimination.
Eligible Content:
A1.1.2.2.1 / A1.1.2.2.2
 Elimination
Method – the process of adding
two equations together to get a variable to
cancel out.
 Also
called the Linear Combinations
Method.
 Opposites
– two numbers that are the same
distance from 0.
1.
2.
3.
4.
5.
Multiply one or both equations by any
numbers that will give you opposite
coefficients for a variable.
Add the two equations together and solve
for the remaining variable.
Plug your answer from Step 2 into any
equation to solve for the other variable.
Write your answer as an ordered pair.
Check your answer.
3 ( 2x + 5y = 5)
-2( 3x + 2y = -9)
2x + 5y = 5
2x + 5 * 3 = 5
2x + 15 = 5
- 15 -15
2x = -10
2
2
x = -5
6x + 15y = 15
-6x – 4y = 18
11y = 33
11 11
y=3
(-5, 3)
What would you multiply by for each problem?
 2x + 3y = 9 and 4x + 4y = 10
 -5x
 2x
– 2y = 10 and 3x + 7y = 12
+ y = 5 and 3x – 4y = 14
 18x
+ 12y = 90 and 12x + 8y = 72
1.
4x + 3y = 16
2x – 3y = 8
(4, 0)
4.
2x + 3y = 0
5x – 6y = 27
(3, -2)
2.
-2x + 3y = 12
2x – 8y = -52
(6, 8)
5.
-7x + 9y = 3
6x – 4y = 16
(6, 5)
3.
3x + 5y = 6
-4x + 2y = 5
(-0.5, 1.5)
Use elimination to solve the system of equations.
3x – 5y = 1
2x + 5y = 9
A. (1, 2)
B. (2, 1)
C. (0, 0)
D. (2, 2)
Use elimination to solve the system of equations.
9x – 2y = 30
x – 2y = 14
A. (2, 2)
B. (–6, –6)
C. (–6, 2)
D. (2, –6)
Use elimination to solve the system of equations.
x + 7y = 12
3x – 5y = 10
A. (1, 5)
B. (5, 1)
C. (5, 5)
D. (1, 1)
Use elimination to solve the system of equations.
3x + 2y = 10
2x + 5y = 3
A. (–4, 1)
B. (–1, 4)
C. (4, –1)
D. (–4, –1)
1.
x + 3y = 5
2x – 3y = 1
(2, 1)
2.
4x – 3y = 0
2x + 4y = -22
(-3, -4)
3.
5x + 7y = 31
2x + 3y = 12
(9, -2)
Page 354 #8-12 even
Page 360 #8-12 even
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