Let’s Warm Up! 1) Solve the system of equations by graphing: 2x + 3y = 12 2x – y = 4 Answer: (3, 2) 2) Find the slope-intercept form for the equation of a line that passes through (0, 5) and is parallel to a line whose equation is 4x – y = 3? Answer: y=4x+5 3)Solve 3│x – 5│= 12 Answer: x= 1, 9 Let’s chat about finals Wednesday Jan 23rd: 2, 4, 6 Thursday Jan 24th: 1, 3, 5 Minimum Days Final Review sheet due DAY OF FINAL Extra Credit: “Additional Practice Problems” Mini Quiz Time! 3 graphing Questions Get out a pencil please. 8-2 Substitution Objective: To use the substitution method to solve systems of equations. Two Algebraic Methods: Substitution Method Elimination Method will learn about next RECALL…Three Types of Solutions: Intersection is Solution One Solution Different slope Different y-intercept “Intersect at one point” No Solution Same slope Different y-intercept “Run parallel Never intersect” Infinite Solutions Same slope Same y-intercept “Same line Intersect infinitely” Substitution Method Use the substitution method when: one equation is set equal to a variable y = 2x + 1 or x = 3y - 2 Example 1 Instead of x = 2 we have: x=y+2 These are all the same! x + 2y = 11 (y + 2) + 2y = 11 x = 3 + 2 x=5 3y + 2 = 11 Answer: (5,3) 3y = 9 y=3 Try with a Mathlete 1) 2) y = 3x x + 2y = -21 y = 2x – 6 3x + 2y = 9 Answers: 1) (-3,-9) 2) (3,0) Example 2 x + 4y = 1 Solve for x (because there 2x – 3y = -9 is no number in front of it) First, solve for a variable x = -4y + 1 x = -4(1) + 1 2(-4y + 1) – 3y = -9 x = -3 -8y + 2 – 3y = -9 -11y + 2 = -9 -11y = -11 y=1 Answer: (-3,1) TOO 1) 2y = -3x 4x + y = 5 Answers: 1) (2,-3) 2) (13,30) 2) 2x – y = -4 -3x + y = -9 Special Cases x + y = 16 2y = -2x + 2 x = 16 – y 2y = -2(16 – y) + 2 2y = -32 + 2y + 2 2y = -30 + 2y 0 = -30 False NO SOLUTION 6x – 2y = -4 y = 3x + 2 6x – 2(3x + 2) = -4 6x – 6x – 4 = -4 -4 = -4 True INFINITELY MANY TOO for Homework 1) y = -x + 3, 2y + 2x = 4 2) x + y = 0, 3x + y = -8 3) y = 3x – 7, 3x – y = 7 Homework Pg. 467 #17-32 left column MORE Explanations The following slides have more examples and explanations of the substitution method. Examples: Use the substitution method to solve the system of equations. the substitution method when a variable is 1) 2x + 3y = 2 (use already isolated or when a variable has a x – 3y = –17 coefficient of 1 and can easily be transformed) 1st: Transform one equation to isolate a variable 2nd: Substitute into the other equation and solve for variable #1 3rd: Substitute into transformed equation from 1st step and solve for variable #2 2x + 3y = 2 “x = 3y – 17” x – 3y = –17 2(3y – 17) + 3y = 2 +3y +3y 6y – 34 + 3y = 2 x = 3y – 17 –34 + 9y = 2 +34 +34 (we picked 9y = 36 x – 3y = – 17 because x has a 9 9 coefficient of 1 y=4 x = 3y – 17 “y = 4” x = 3(4) – 17 x = 12 – 17 x = –5 and can easily be transformed) Write answer as an ordered pair (x, y): One Solution (–5 , 4) Examples: Use the substitution method to solve the system of equations. 2) –9x + 3y = –21 3x – y = 7 1st: Transform one equation to isolate a variable 3x – y = 7 -3x -3x –y = –3x + 7 -1 -1 -1 y = 3x – 7 (use the substitution method when a variable is already isolated or when a variable has a coefficient of 1 and can easily be transformed) 2nd: Substitute it into the other equation and solve for variable #1 3rd: Substitute into the transformed equation from 1st step and solve for variable #2 –9x + 3y = –21 “y = 3x – 7” –9x + 3(3x – 7) = –21 –9x + 9x – 21= –21 –21 = –21 True!! (we picked 3x – y = 7 because y has a coefficient of -1 and can easily be transformed) Write answer as an ordered pair (x, y): Infinite Solutions Examples: Use the substitution method to solve the system of equations. 3) 4x – 2y = 5 y = 2x + 1 1st: Transform one equation to isolate a variable y = 2x + 1 (already isolated) (use the substitution method when a variable is already isolated or when a variable has a coefficient of 1 and can easily be transformed) 2nd: Substitute into the other equation and solve for variable #1 4x – 2y = 5 4x – 2(2x + 1) = 5 4x – 4x – 2 = 5 –2=5 “y = 2x + 1” False!! No Solution 3rd: Substitute into transformed equation from 1st step and solve for variable #2