Computational Chemistry G. H. CHEN Department of Chemistry University of Hong Kong Beginning of Computational Chemistry In 1929, Dirac declared, “The underlying physical laws necessary for the mathematical theory of ...the whole of chemistry are thus completely know, and the difficulty is only that the exact application of these laws leads to equations much too complicated to be soluble.” Theory is reality ! W.A. Goddard III Dirac Computational Chemistry Quantum Chemistry SchrÖdinger Equation Molecular Mechanics F=Ma Bioinformatics Create & Analyse Bio-information Nobel Prizes for Computational Chemsitry Mulliken,1966 Pople, 1998 Fukui, 1981 Hoffmann, 1981 Kohn, 1998 Computational Chemistry Industry Company Software Gaussian Inc. Gaussian 94, Gaussian 98 Schrödinger Inc. Jaguar Wavefunction Spartan Q-Chem Q-Chem Accelrys InsightII, Cerius2 HyperCube HyperChem Celera Genomics (Dr. Craig Venter, formal Prof., SUNY, Baffalo; 98-01) Applications: material discovery, drug design & research R&D in Chemical & Pharmaceutical industries in 2000: US$ 80 billion Bioinformatics: Total Sales in 2001 Project Sales in 2006 US$ 225 million US$ 1.7 billion Software Development at HKU LODESTAR v1.02 --Localized Density Matrix: STAR performer http://yangtze.hku.hk Quantum Chemistry Methods • Ab initio molecular orbital methods • Semiempirical molecular orbital methods • Density functional method SchrÖdinger Equation Hy=Ey Wavefunction Hamiltonian H = (-h2/2m)2 - (h2/2me)ii2 + ZZe2/r - i Ze2/ri + i j e2/rij Energy C60 energy Vitamin C heme Cytochrome c OH + D2 --> HOD + D C60 and Superconductor What is superconductor? Electrical Current flows for ever ! Applications: Magnet, Magnetic train, Power transportation Crystal Structure of C60 solid Crystal Structure of K3C60 K3C60 is a Superconductor (Tc = 19K) The mechanism of superconductivity in K3C60 was discovered using computational chemistry methods Varma et. al., 1991; Schluter et. al., 1992; Dresselhaus et. al., 1992;Chen & Goddard, 1992 Effective Attraction ! Vibration Spectrum of K3C60 Erwin & Pickett, Science, 1991 GH Chen, Ph.D. Thesis, Caltech (1992) Carbon Nanotubes (Ijima, 1991) Calculated STM Image of a Carbon Nanotube (Rubio, 1999) STM Image of Carbon Nanotubes (Wildoer et. al., 1998) Computer Simulations (Saito, Dresselhaus, Louie et. al., 1992) Carbon Nanotubes (n,m): Conductor, if n-m = 3I Semiconductor, if n-m 3I I=0,±1,±2,±3,…;or Metallic Carbon Nanotubes: Semiconducting Nanotubes: Conducting Wires Transistors Molecular-scale circuits ! 1 nm transistor! 30 nm transistor! 0.13 µm transistor! Experimental Confirmations: Lieber et. al. 1993; Dravid et. al., 1993; Iijima et. al. 1993; Smalley et. al. 1998; Haddon et. al. 1998; Liu et. al. 1999 Wildoer, Venema, Rinzler, Smalley, Dekker, Nature 391, 59 (1998) Science 9th November, 2001 Logic gates (and circuits) with carbon nanotuce transistor Science 7th July, 2000 Carbon nanotube-Based nonvolatile RAM for molecular computing Nanoelectromechanical Systems (NEMS) K.E. Drexler, Nanosystems: Molecular Machinery, Manufacturing and Computation (Wiley, New York, 1992). Large Gear Drives Small Gear G. Hong et. al., 1999 Nano-oscillators Nanoscopic Electromechanical Device (NEMS) Zhao, Ma, Chen & Jiang, Phys. Rev. Lett. 2003 Oscillation (5,0)@(14,0) 55A @ 70A, 500K 40 Relative distance (Angstrom) 30 20 10 0 -10 -20 -30 0 500 1000 1500 2000 Time (ps) Hibernation Awakening Quantum mechanical investigation of the field emission from the tips of carbon nanotubes Zheng, Chen, Li, Deng & Xu, Phys. Rev. Lett. 2004 Zettl, PRL 2001 Computer-Aided Drug Design Human Genome Project GENOMICS ALDOSE REDUCTASE HO HO OH HO OH HO Aldose Reductase Diabetes HO O HO glucose OH Glucose NADPH NADP HO sorbitol OH Sorbitol Diabetic Complications Design of Aldose Reductase Inhibitors Inhibitor Aldose Reductase Hu & Chen, 2003 Database for Functional Groups Electronic Affinity(eV) -0.026661055 -0.706309133 -1.270557034 -0.76855741 -0.160533773 -1.182299665 -1.561982616 -2.573416988 -2.444365755 -2.356589514 -2.296956191 -1.683414531 -2.024168064 -1.226684615 -0.370141762 -2.507617614 2.123404035 -2.062392576 0.363370563 1.946070446 1.933493026 2.202225384 -2.221199855 -0.3938852 -1.024625532 0.930074828 0.064048786 -0.238732972 0.023658445 -0.98717652 -1.515044158 1.277315225 -0.44795408 -0.29063744 -1.86670608 -1.09197392 -2.00731648 -2.0214088 -1.1650712 -1.66132432 -1.8973088 -0.72427344 -1.38209456 -1.72708304 -2.19444704 -2.16905312 1.3880432 -0.59915888 -0.59987968 1.8424872 -6.5978496 1.32051376 1.33964352 Volume(cm**3/mol) 61.953 73.033 133.816 75.698 81.572 88.289 28.975 40.829 45.863 60.671 84.137 88.078 86.479 49.929 31.487 29.582 23.704 8.547 38.708 36.34 23.893 24.052 10.315 22.034 64.609 27.083 31.575 54.174 55.761 25.579 15.942 50.894 28.721 46.036 90.357 88.207 45.533 107.122 78.805 121.142 87.058 90.468 145.166 90.469 116.447 97.131 73.451 137.142 55.06 86.718 154.362 111.819 140.502 O Structure-activity-relation NH 5.0 R4 HN O R3 NMe 4.5 Supervise Values Database of Function Group Ionic Potential(eV) 2-Thienyl 9.38414881 3-Cl-C6H4 8.749035019 4-C6H5-C6H4 8.407247908 4-Cl-C6H4 8.746870744 4-NO2-C6H4 9.217321674 4-OCH3-C6H4 8.242902306 C2H3 8.260300105 C2H5 7.780243105 C3H7 6.81804497 C4H9 6.670585636 C5H11 6.598274428 C6H5-CH2 6.902499381 C6H5-CH2CH2 5.575403173 C6H5 12.8343891 CF3 8.758052916 CH3 8.935004666 Cl 14.52590929 H 13.55771463 SCH3 10.38525408 3-4-Methylenedioxo 6.761934134 Br 13.24832638 CN 16.12363076 F 11.71218241 NH2 19.92831772 NHAC 8.159304652 NO2 9.624434885 OCF3 10.21475618 OCH2CH2CH3 6.173209263 OCH2CHCH2 7.543726177 OCH3 8.206405401 OH 15.02158915 SO2CH3 8.676981042 COOH 7.70352688 CH2-COOH 9.59715824 CH2-C6H4-OMe 6.1379112 C6H4-34OH 8.37323712 N-2CH3 8.9735112 2CH2-C6H4-OH 5.72024976 C6H5-OH 9.89372528 CH2-C10H8 6.89898896 CH2-C6H4-OH 6.30185104 br-C6H4 8.711011456 2C6H5-CH 6.52476048 CH2-C6H3-34OH 6.49713888 3CH2-C6H4-OH 6.3709472 3CH2-O-pH 6.93279584 COO-t-Bu 11.29505024 O-3CH2-OCH2pH 7.26343904 O-3CH2-OH 6.79831088 OCO-2CH2-COCH2Me 6.4562192 OCO-2CH2-COO-CHMePh 6.5978496 OCO-3CH2-CH2Me 6.60117072 OCO-N-Hex 6.64197888 R2 N H 4.0 O R1 3.5 3.0 2.5 2.5 3.0 3.5 4.0 4.5 5.0 Exp. Values (logIC50 nm)[Three Hidden Neurons] Prediction: Drug Leads O O NH NH NO 2 F HN O C6H5 HN O C6H5 NMe C6H5 N H NMe O C6H5 N H LogIC50: 0.6382,1.0 LogIC50: 0.6861,0.88 O Prediction Results using AutoDock LogIC50: 0.77,1.1 LogIC50: -1.87,4.05 LogIC50: -2.77,4.14 Hu & Chen, 2003 LogIC50: 0.68,0.88 Computer-aided drug design Chemical Synthesis Screening using in vitro assay Animal Tests Clinical Trials Bioinformatics • Improve content & utility of bio-databases • Develop tools for data generation, capture & annotation • Develop tools for comprehensive functional studies • Develop tools for representing & analyzing sequence similarity & variation Computational Chemistry • • • • Increasingly important field in chemistry Help to understand experimental results Provide guidelines to experimentists Application in Materials & Pharmaceutical industries • Future: simulate nano-size materials, bulk materials; replace experimental R&D Objective: More and more research & development to be performed on computers and Internet instead in the laboratories Quantum Chemistry G. H. Chen Department of Chemistry University of Hong Kong Contributors: Hartree, Fock, Slater, Hund, Mulliken, Lennard-Jones, Heitler, London, Brillouin, Koopmans, Pople, Kohn Application: Chemistry, Condensed Matter Physics, Molecular Biology, Materials Science, Drug Discovery Emphasis Hartree-Fock method Concepts Hands-on experience Text Book “Quantum Chemistry”, 4th Ed. Ira N. Levine http://yangtze.hku.hk/lecture/chem3504-3.ppt Contents 1. Variation Method 2. Hartree-Fock Self-Consistent Field Method 3. Perturbation Theory 4. Semiempirical Methods The Variation Method The variation theorem Consider a system whose Hamiltonian operator H is time independent and whose lowest-energy eigenvalue is E1. If f is any normalized, wellbehaved function that satisfies the boundary conditions of the problem, then f* H f dt > E1 Proof: Expand f in the basis set { yk} f = k kyk where {k} are coefficients Hyk = Ekyk then f* H f dt = k j k* j Ej dkj = k | k|2 Ek > E 1 k | k|2 = E1 Since is normalized, f*f dt = k | k|2 = 1 i. f : trial function is used to evaluate the upper limit of ground state energy E1 ii. f = ground state wave function, f* H f dt = E1 iii. optimize paramemters in f by minimizing f* H f dt / f* f dt Application to a particle in a box of infinite depth 0 l Requirements for the trial wave function: i. zero at boundary; ii. smoothness a maximum in the center. Trial wave function: f = x (l - x) f* H f dx = -(h2/82m) (lx-x2) d2(lx-x2)/dx2 dx = h2/(42m) (x2 - lx) dx = h2l3/(242m) f*f dx = x2 (l-x)2 dx = l5/30 Ef = 5h2/(42l2m) h2/(8ml2) = E1 Variational Method (1) Construct a wave function f(c1,c2,,cm) (2) Calculate the energy of f: Ef Ef(c1,c2,,cm) (3) Choose {cj*} (i=1,2,,m) so that Ef is minimum Example: one-dimensional harmonic oscillator Potential: V(x) = (1/2) kx2 = (1/2) m2x2 = 22m2x2 Trial wave function for the ground state: f(x) = exp(-cx2) f* H f dx = -(h2/82m) exp(-cx2) d2[exp(-cx2)]/dx2 dx + 22m2 x2 exp(-2cx2) dx = (h2/42m) (c/8)1/2 + 2m2 (/8c3)1/2 f*f dx = exp(-2cx2) dx = (/2)1/2 c-1/2 Ef = W = (h2/82m)c + (2/2)m2/c To minimize W, 0 = dW/dc = h2/82m - (2/2)m2c-2 c = 22m/h W = (1/2) h Extension of Variation Method . . . E3 y3 E2 y2 E1 y1 For a wave function f which is orthogonal to the ground state wave function y1, i.e. dt f*y1 = 0 Ef = dt f*Hf / dt f*f > E2 the first excited state energy The trial wave function f: dt f*y1 = 0 f = k=1 ak yk dt f*y1 = |a1|2 = 0 Ef = dt f*Hf / dt f*f = k=2|ak|2Ek / k=2|ak|2 > k=2|ak|2E2 / k=2|ak|2 = E2 Application to H2+ e f=c y +c y 1 1 2 2 + + y 1 y 2 W = f*H f dt / f*f dt = (c12 H11 + 2c1 c2 H12 + c22 H22 ) / (c12 + 2c1 c2 S + c22 ) W (c12 + 2c1 c2 S + c22) = c12 H11 + 2c1 c2 H12 + c22 H22 Partial derivative with respect to c1 (W/c1 = 0) : W (c1 + S c2) = c1H11 + c2H12 Partial derivative with respect to c2 (W/c2 = 0) : W (S c1 + c2) = c1H12 + c2H22 (H11 - W) c1 + (H12 - S W) c2 = 0 (H12 - S W) c1 + (H22 - W) c2 = 0 To have nontrivial solution: H11 - W H12 - S W H12 - S W = 0 H22 - W For H2+, H11 = H22; H12 < 0. Ground State: Eg = W1 = (H11+H12) / (1+S) f1 = (y1+y2) / 2(1+S)1/2 bonding orbital Excited State: Ee = W2 = (H11-H12) / (1-S) f2 = (y1-y2) / 2(1-S)1/2 Anti-bonding orbital Results: De = 1.76 eV, Re = 1.32 A Exact: De = 2.79 eV, Re = 1.06 A 1 eV = 23.0605 kcal / mol Further Improvements Optimization of 1s orbitals H -1/2 exp(-r) He+ 23/2 -1/2 exp(-2r) Trial wave function: k3/2 -1/2 exp(-kr) Eg = W1(k,R) at each R, choose k so that W1/k = 0 Results: De = 2.36 eV, Re = 1.06 A Inclusion of other atomic orbitals 1s 2p Resutls: De = 2.73 eV, Re = 1.06 A Linear Equations 1. two linear equations for two unknown, x1 and x2 a11x1 + a12x2 = b1 a21x1 + a22x2 = b2 (a11a22-a12a21) x1 = b1a22-b2a12 (a11a22-a12a21) x2 = b2a11-b1a21 Introducing determinant: a11 a12 = a11a22-a12a21 a21 a22 a11 a12 b1 a12 a21 a22 b2 a22 a11 a12 a11 b1 x1 = x2 = a21 a22 a21 b2 Our case: b1 = b2 = 0, homogeneous 1. trivial solution: x1 = x2 = 0 2. nontrivial solution: a11 a12 =0 a21 a22 n linear equations for n unknown variables a11x1 + a12x2 + ... + a1nxn= b1 a21x1 + a22x2 + ... + a2nxn= b2 a11 a12 a21 a22 det(aij) xk= . . an1 an2 ... ... ... ... a1,k-1 a2,k-1 . an,k-1 ... ... ... ... a1n a2n . ann where, det(aij) = a11 a12 a21 a22 . . an1 an2 b1 a1,k+1 b2 a2,k+1 . . b2 an,k+1 ... a1n ... a2n ... . ... ann inhomogeneous case: bk = 0 for at least one k a11 a12 a21 a22 . . an1 an2 ... ... ... ... a1,k-1 a2,k-1 . an,k-1 xk = det(aij) b1 b2 . b2 a1,k+1 ... a2,k+1 ... . ... an,k+1 ... a1n a2n . ann homogeneous case: bk = 0, k = 1, 2, ... , n (a) travial case: xk = 0, k = 1, 2, ... , n (b) nontravial case: det(aij) = 0 For a n-th order determinant, n det(aij) = alk Clk l=1 where, Clk is called cofactor Trial wave function f is a variation function which is a combination of n linear independent functions { f1 , f2 , ... fn}, f = c1f1 + c2f2 + ... + cnfn n [( Hik - SikW ) ck ] = 0 k=1 Sik dt fi fk Hik dt fi H fk W dt f H f / dt f f i=1,2,...,n Linear variational theorem (i) W1 W2 ... Wn are n roots of Eq.(1), (ii) E1 E2 ... En En+1 ... are energies of eigenstates; then, W1 E1, W2 E2, ..., Wn En Molecular Orbital (MO): f = c1y1 + c2y2 ( H11 - W ) c1 + ( H12 - SW ) c2 = 0 S11=1 ( H21 - SW ) c1 + ( H22 - W ) c2 = 0 S22=1 Generally : yi a set of atomic orbitals, basis set LCAO-MO f = c1y1 + c2y2 + ...... + cnfn linear combination of atomic orbitals n ( Hik - SikW ) ck = 0 k=1 Hik dt yi* H yk i = 1, 2, ......, n Sik dt yi*yk Skk = 1 The Born-Oppenheimer Approximation Hamiltonian H = (-h2/2m)2 - (h2/2me)ii2 + ZZe2/r - i Ze2/ri + i j e2/rij H y(ri;r) = E y(ri;r) The Born-Oppenheimer Approximation: (1) y(ri;r) = yel(ri;r) yN(r) (2) Hel(r )= - (h2/2me)ii2 - i Ze2/ri + ij e2/rij VNN = ZZe2/r Hel(r) yel(ri;r) = Eel(r) yel(ri;r) (3) HN = (-h2/2m)2 + U(r) U(r) = Eel(r) + VNN HN(r) yN(r) = E yN(r) Assignment Calculate the ground state energy and bond length of H2 using the HyperChem with the 6-31G (Hint: Born-Oppenheimer Approximation) Hydrogen Molecule H2 e + + e The Pauli principle two electrons cannot be in the same state. Wave function: f(1,2) = ja(1)jb(2) + c1 ja(2)jb(1) f(2,1) = ja(2)jb(1) + c1 ja(1)jb(2) Since two wave functions that correspond to the same state can differ at most by a constant factor f(1,2) = c2 f(2,1) ja(1)jb(2) + c1ja(2)jb(1) =c2ja(2)jb(1) +c2c1ja(1)jb(2) c1 = c2 Therefore: c1 = c2 = 1 c2c1 = 1 According to the Pauli principle, c1 = c2 =- 1 The Pauli principle (different version) the wave function of a system of electrons must be antisymmetric with respect to interchanging of any two electrons. Wave function f of H2 : Slater Determinant y(1,2) = 1/2! [f(1)(1)f(2)(2) - f(2)(2)f(1)(1)] = 1/2! f(1)(1) f(2)(2) f(1)(1) f(2)(2) Energy: Ey Ey=2 dt1 f*(1) (Te+VeN) f(1) + VNN + dt1 dt2 |f2(1)| e2/r12 |f2(2)| = i=1,2 fii + J12 + VNN To minimize Ey under the constraint dt |f2| = 1, use Lagrange’s method: L = Ey - 2 e [ dt1 |f2(1)| - 1] dL = dEy - 4 e dt1 f*(1)df(1) = 4 dt1 df*(1)(Te+VeN)f(1) +4 dt1 dt2 f*(1)f*(2) e2/r12 f(2)df(1) - 4 e dt1 f*(1)df(1) =0 [ Te+VeN + dt2 f*(2) e2/r12 f(2) ] f(1) = e f(1) Average Hamiltonian Hartree-Fock equation (f+J)f=ef f(1) = Te(1)+VeN(1) J(1) = dt2 f*(2) e2/r12 f(2) one electron operator two electron Coulomb operator f(1) is the Hamiltonian of electron 1 in the absence of electron 2; J(1) is the mean Coulomb repulsion exerted on electron 1 by 2; e is the energy of orbital f. LCAO-MO: f = c1y1 + c2y2 Multiple y1 from the left and then integrate : c1F11 + c2F12 = e (c1 + S c2) Multiple y2 from the left and then integrate : c1F12 + c2F22 = e (S c1 + c2) where, Fij = dt yi* ( f + J ) yj = Hij + dt yi* J yj S = dt y1 y2 (F11 - e) c1 + (F12 - S e) c2 = 0 (F12 - S e) c1 + (F22 - e) c2 = 0 Secular Equation: F11 - e F12 - S e F12 - Se F22 - e bonding orbital: = 0 e1 = (F11+F12) / (1+S) f1 = (y1+y2) / 2(1+S)1/2 antibonding orbital: e2 = (F11-F12) / (1-S ) f2 = (y1-y2) / 2(1-S)1/2 Molecular Orbital Configurations of Homo nuclear Diatomic Molecules H2, Li2, O, He2, etc Moecule H2+ H2 He2+ He2 Li2 Be2 C2 N2+ N2 O2+ O2 Bond order 1 0 1 0 2 3 2 2 De/eV 2.79 4.75 1.08 0.0009 1.07 0.10 6.3 8.85 9.91 6.78 5.21 The more the Bond Order is, the stronger the chemical bond is. Bond Order: one-half the difference between the number of bonding and antibonding electrons ---------------- f1 ---------------- f2 f1(1)(1) f2(1)(1) y(1,2) = 1 /2 f1(2)(2) f2(2)(2) = 1/2 [f1(1) f2(2) - f2(1) f1(2)] (1) (2) Ey = dt1dt2 y* H y = dt1dt2 y* (T1+V1N+T2+V2N+V12+VNN) y = <f1(1)| T1+V1N|f1(1)> + <f2(2)| T2+V2N|f2(2)> + <f1(1) f2(2)| V12 | f1(1) f2(2)> - <f1(2) f2(1)| V12 | f1(1) f2(2)> + VNN = i <fi(1)| T1+V1N |fi(1)> + <f1(1) f2(2)| V12 | f1(1) f2(2)> - <f1(2) f2(1)| V12 | f1(1) f2(2)> + VNN = i=1,2 fii + J12 - K12 + VNN Average Hamiltonian Particle One: Particle Two: f(1) + J2(1) - K2(1) f(2) + J1(2) - K1(2) f(j) -(h2/2me)j2 - Z/rj Jj(1) q(1) q(1) dr2 fj*(2) e2/r12 fj(2) Kj(1) q(1) fj(1) dr2 fj*(2) e2/r12 q(2) Hartree-Fock Equation: [ f(1)+ J2(1) - K2(1)] f1(1) = e1 f1(1) [ f(2)+ J1(2) - K1(2)] f2(2) = e2 f2(2) Fock Operator: F(1) f(1)+ J2(1) - K2(1) F(2) f(2)+ J1(2) - K1(2) Fock operator for 1 Fock operator for 2 Summary 1. At the Hartree-Fock Level there are two possible Coulomb integrals contributing the energy between two electrons i and j: Coulomb integrals Jij and exchange integral Kij; 2. For two electrons with different spins, there is only Coulomb integral Jij; 3. For two electrons with the same spins, both Coulomb and exchange integrals exist. 4. Total Hartree-Fock energy consists of the contributions from one-electron integrals fii and two-electron Coulomb integrals Jij and exchange integrals Kij; 5. At the Hartree-Fock Level there are two possible Coulomb potentials (or operators) between two electrons i and j: Coulomb operator and exchange operator; Jj(i) is the Coulomb potential (operator) that i feels from j, and Kj(i) is the exchange potential (operator) that that i feels from j. 6. Fock operator (or, average Hamiltonian) consists of one-electron operators f(i) and Coulomb operators Jj(i) and exchange operators Kj(i) N electrons spin up and N electrons spin down. Fock matrix for an electron 1 with spin up: F(1) = f (1) + j [ Jj(1) - Kj(1) ] + j Jj(1) j=1,N j=1,N Fock matrix for an electron 1 with spin down: F(1) = f (1) + j [ Jj(1) - Kj(1) ] + j Jj(1) j=1,N j=1,N f(1) -(h2/2me)12 - N ZN/r1N Jj(1) dr2 fj*(2) e2/r12 fj(2) Kj(1) q(1) fj(1) dr2 fj*(2) e2/r12 q(2) Energy = j fjj+j fjj+(1/2) i j ( Jij - Kij ) + (1/2) i j ( Jij - Kij ) + i j Jij + VNN i=1,N j=1,N fjj fjj <fj| f |fj> Jij Jij <fj(2)| Ji(1) |fj(2)> Kij Kij <fj(2)| Ki(1) |fj(2)> Jij Jij <fj(2)| Ji(1) |fj(2)> Close subshell case: ( N= N= n/2 ) F(1) = f (1) + j=1,n/2 [ 2Jj(1) - Kj(1) ] Energy = 2 j=1,n/2 fjj + i=1,n/2 j=1,n/2 ( 2Jij - Kij ) +VNN Hartree-Fock Method 1. Many-Body Wave Function is approximated by Slater Determinant 2. Hartree-Fock Equation F fi = ei fi F Fock operator fi the i-th Hartree-Fock orbital ei the energy of the i-th Hartree-Fock orbital 3. Roothaan Method (introduction of Basis functions) fi = k cki yk LCAO-MO { yk } is a set of atomic orbitals (or basis functions) 4. Hartree-Fock-Roothaan equation j ( Fij - ei Sij ) cji = 0 Fij < yi| F | yj > Sij < yi| yj > 5. Solve the Hartree-Fock-Roothaan equation self-consistently The Condon-Slater Rules <fa(1)fb(2)fc(3)...fd(n) | f(1) | fe(1)ff(2)fg(3)...fh(n)> = <fa(1) | f(1) | fe(1)> < fb(2)fc(3)...fd(n) | ff(2)fg(3)...fh(n)> = <fa(1) | f(1) | fe(1)> if b=f, c=g, ..., d=h; 0, otherwise <fa(1)fb(2)fc(3)...fd(n) | V12 | fe(1)ff(2)fg(3)...fh(n)> = <fa(1) fb(2) | V12 | fe(1) ff(2)> < fc(3)...fd(n) | fg(3)...fh(n)> = <fa(1) fb(2) | V12 | fe(1) ff(2)> if c=g, ..., d=h; 0, otherwise LUMO ------the lowest unoccupied molecular orbital ------- HOMO the highest occupied molecular orbital ------------Koopman’s Theorem The energy required to remove an electron from a closed-shell atom or molecules is well approximated by minus the orbital energy e of the AO or MO from which the electron is removed. # HF/6-31G(d) Route section water energy Title 0 O H H Molecule Specification (in Cartesian coordinates 1 -0.464 0.177 0.0 -0.464 1.137 0.0 0.441 -0.143 0.0 Basis Set fi = p cip p Slater-type orbitals (STO) nlm = N rn-1exp(-r/a0) Ylm(q,f) the orbital exponent * is used instead of y in the textbook Gaussian type functions gijk = N xi yj zk exp(-r2) (primitive Gaussian function) p = u dup gu (contracted Gaussian-type function, CGTF) u = {ijk} p = {nlm} Basis set of GTFs STO-3G, 3-21G, 4-31G, 6-31G, 6-31G*, 6-31G** ------------------------------------------------------------------------------------- complexity & accuracy Minimal basis set: one STO for each atomic orbital (AO) STO-3G: 3 GTFs for each atomic orbital 3-21G: 3 GTFs for each inner shell AO 2 CGTFs (w/ 2 & 1 GTFs) for each valence AO 6-31G: 6 GTFs for each inner shell AO 2 CGTFs (w/ 3 & 1 GTFs) for each valence AO 6-31G*: adds a set of d orbitals to atoms in 2nd & 3rd rows 6-31G**: adds a set of d orbitals to atoms in 2nd & 3rd rows Polarization and a set of p functions to hydrogen Function Diffuse Basis Sets: For excited states and in anions where electronic density is more spread out, additional basis functions are needed. Diffuse functions to 6-31G basis set as follows: 6-31G* - adds a set of diffuse s & p orbitals to atoms in 1st & 2nd rows (Li - Cl). 6-31G** - adds a set of diffuse s and p orbitals to atoms in 1st & 2nd rows (Li- Cl) and a set of diffuse s functions to H Diffuse functions + polarisation functions: 6-31+G*, 6-31++G*, 6-31+G** and 6-31++G** basis sets. Double-zeta (DZ) basis set: two STO for each AO (10s4p) [3s2p] 6-31G for a carbon atom: 1s 2s 2pi (i=x,y,z) 6GTFs 3GTFs 1GTF 3GTFs 1GTF 1CGTF (s) 1CGTF (s) 1CGTF (s) 1CGTF (p) 1CGTF (p) Minimal basis set: One STO for each inner-shell and valence-shell AO of each atom example: C2H2 (2S1P/1S) C: 1S, 2S, 2Px,2Py,2Pz H: 1S total 12 STOs as Basis set Double-Zeta (DZ) basis set: two STOs for each and valence-shell AO of each atom example: C2H2 (4S2P/2S) C: two 1S, two 2S, two 2Px, two 2Py,two 2Pz H: two 1S (STOs) total 24 STOs as Basis set Split -Valence (SV) basis set Two STOs for each inner-shell and valence-shell AO One STO for each inner-shell AO Double-zeta plus polarization set(DZ+P, or DZP) Additional STO w/l quantum number larger than the lmax of the valence - shell ( 2Px, 2Py ,2Pz ) to H Five 3d Aos to Li - Ne , Na -Ar C2H5 O Si H3 : (6s4p1d/4s2p1d/2s1p) Si C,O H Assignment: Calculate the structure, ground state energy, molecular orbital energies, and vibrational modes and frequencies of a water molecule using Hartree-Fock method with 3-21G basis set. (due 30/10) Ab Initio Molecular Orbital Calculation: H2O (using HyperChem) 1. L-Click on (click on left button of Mouse) “Startup”, and select and L-Click on “Program/Hyperchem”. 2. Select “Build’’ and turn on “Explicit Hydrogens”. 3. Select “Display” and make sure that “Show Hydrogens” is on; L-Click on “Rendering” and double L-Click “Spheres”. 4. Double L-Click on “Draw” tool box and double L-Click on “O”. 5. Move the cursor to the workspace, and L-Click & release. 6. L-Click on “Magnify/Shrink” tool box, move the cursor to the workspace; L-press and move the cursor inward to reduce the size of oxygen atom. 7. Double L-Click on “Draw” tool box, and double L-Click on “H”; Move the cursor close to oxygen atom and L-Click & release. A hydrogen atom appears. Draw second hydrogen atom using the same procedure. 8. L-Click on “Setup” & select “Ab Initio”; double L-Click on 3-21G; then L-Click on “Option”, select “UHF”, and set “Charge” to 0 and “Multiplicity” to 1. 9. L-Click “Compute”, and select “Geometry Optimization”, and L-Click on “OK”; repeat the step till “Conv=YES” appears in the bottom bar. Record the energy. 10.L-Click “Compute” and L-Click “Orbitals”; select a energy level, record the energy of each molecular orbitals (MO), and L-Click “OK” to observe the contour plots of the orbitals. 11.L-Click “Compute” and select “Vibrations”. 12.Make sure that “Rendering/Sphere” is on; L-Click “Compute” and select “Vibrational Spectrum”. Note that frequencies of different vibrational modes. 13.Turn on “Animate vibrations”, select one of the three modes, and L-Click “OK”. Water molecule begins to vibrate. To suspend the animation, L-Click on “Cancel”. The Hartree-Fock treatment of H2 e+ e+ The Valence-Bond Treatment of H2 f1 = y1(1) y2(2) f2 = y1(2) y2(1) f = c1 f1 + c2 f2 H11 - W H21 - S W H12 - S W H22 - W =0 H11 = H22 = <y1(1) y2(2)|H|y1(1) y2(2)> H12 = H21 = <y1(1) y2(2)|H|y1(2) y2(1)> S = <y1(1) y2(2)|y1(2) y2(1)> [ = S2 ] The Heitler-London ground-state wave function {[y1(1) y2(2) + y1(2) y2(1)]/2(1+S)1/2} [(1)(2)-(2)(1)]/2 Comparison of the HF and VB Treatments HF LCAO-MO wave function for H2 [y1(1) + y2(1)] [y1(2) + y2(2)] = y1(1) y1(2) + y1(1) y2(2) + y2(1) y1(2) + y2(1) y2(2) H- H+ H H VB wave function for H2 y1(1) y2(2) + y2(1) y1(2) H H H H H H H+ H- At large distance, the system becomes H ............ H MO: 50% H ............ H 50% H+............ HVB: 100% H ............ H The VB is computationally expensive and requires chemical intuition in implementation. The Generalized valence-bond (GVB) method is a variational method, and thus computationally feasible. (William A. Goddard III) f1 = y (1)y (2) f 2 = y (2)y (1) = c1 f1 + c2 f 2 R R H 11 = H 22 = y 1 (1)y 2 (2) H y 1 (1)y 2 (2) H 11 - W H 12 - SW H 21 - SW H 22 - W =0 H 12 = H 21 = y 1 (1)y 2 (2) H y 1 (2)y 2 (1) [ S = y 1 (1)y 2 (2) y 1 (2)y 2 (1) = S 2 ] The Heitler-London ground-state wave function [y (1)y 1 2 (2) + y 1 (2)y 2 (1)]/ 2(1 + S ) [ (1) (2) - (2) (1)]/ 2 Assignment 8.4, 8.10, 8.12b, 8.40, 10.5, 10.6, 10.7, 10.8, 11.37, 13.37 Electron Correlation Human Repulsive Correlation Electron Correlation: avoiding each other Two reasons of the instantaneous correlation: (1) Pauli Exclusion Principle (HF includes the effect) (2) Coulomb repulsion (not included in the HF) Beyond the Hartree-Fock Configuration Interaction (CI)* Perturbation theory* Coupled Cluster Method Density functional theory -e -e r12 r2 r1 +2e H = - (h2/2me)12 - 2e2/r1 - (h2/2me)22 - 2e2/r2 + e2/r12 H10 H20 H’ H 0 = H 10 + H 2 0 y(0)(1,2) = F1(1) F2(2) H10 F1(1) = E1 F1(1) H20 F2(1) = E2 F2(1) E1 = -2e2/n12a0 n1 = 1, 2, 3, ... E2 = -2e2/n22a0 n2 = 1, 2, 3, ... Ground state wave function y(0)(1,2) = (1/1/2)(2/a0)3/2exp(-2r1/a0) * (1/1/2)(2/a0)3/2exp(-2r1/a0) E(0) = - 4e2/a0 E(1) = <y(0)(1,2)| H’ |y(0)(1,2)> = 5e2/4a0 E E(0) + E(1) = -108.8 + 34.0 = -74.8 (eV) [compared with exp. -79.0 eV] Nondegenerate Perturbation Theory (for Non-Degenerate Energy Levels) H = H0 + H’ H0yn(0) = En(0) yn(0) yn(0) is an eigenstate for unperturbed system H’ is small compared with H0 Introducing a parameter l H(l) = H0 + lH’ H(l) yn(l) = En(l) yn(l) yn(l) = yn(0) + l yn(1) + l2 yn(2) + ... + lk yn(k) + ... En(l) = En(0) + l En(1) + l2 En(2) + ... + lk En(k) + ... l = 1, the original Hamiltonian yn = yn(0) + yn(1) + yn(2) + ... + yn(k) + ... En = En(0) + En(1) + En(2) + ... + En(k) + ... Where, < yn(0) | yn(j) > = 0, j=1,2,...,k,... H0yn(0) = En(0) yn(0) solving for En(0), yn(0) H0yn(1) + H’ yn(0) = En(0) yn(1) + En(1)yn(0) solving for En(1), yn(1) H0yn(2) + H’ yn(1) = En(0) yn(2) + En(1)yn(1) + En(2)yn(0) solving for En(2),yn(2) The first order: Multiplied ym(0) from the left and integrate, <ym(0) | H0 | yn(1) > + < ym(0) | H' | yn(0) > = < ym(0)|yn(1) >En(0) + En(1) dmn <ym(0)|yn(1) > [Em(0)- En(0)] + < ym(0) | H' | yn(0) > = En(1) dmn For m = n, En(1) = < yn(0) | H' | yn(0) > Eq.(1) For m n, <ym(0)|yn(1) > = < ym(0) | H' | yn(0) > / [En(0)- Em(0)] If we expand yn(1) = cnm ym(0), cnm = < ym(0) | H' | yn(0) > / [En(0)- Em(0)] for m n; (1) (0) | H' | y (0) > / [E (0)- E (0)] y (0) cynn = 0. = < y n m m n n m m Eq.(2) The second order: <ym(0)|H0|yn(2) > + < ym(0)|H'|yn(1) > = < ym(0)|yn(2) >En(0) + < ym(0)|yn(1) >En(1) + En(1) dmn Set m = n, we have En(2) = m n |<ym(0) | H' | yn(0) >|2 / [En(0)- Em(0)] Eq.(3) Discussion: (Text Book: page 522-527) a. Eq.(2) shows that the effect of the perturbation on the wave function yn(0) is to mix in contributions from the other zero-th order states ym(0) mn. Because of the factor 1/(En(0)-Em(0)), the most important contributions to the yn(1) come from the states nearest in energy to state n. b. To evaluate the first-order correction in energy, we need only to evaluate a single integral H’nn; to evaluate the second-order energy correction, we must evalute the matrix elements H’ between the n-th and all other states m. c. The summation in Eq.(2), (3) is over all the states, not the energy levels. Moller-Plesset (MP) Perturbation Theory The MP unperturbed Hamiltonian H0 H0 = m F(m) where F(m) is the Fock operator for electron m. And thus, the perturbation H’ H’ = H - H0 Therefore, the unperturbed wave function is simply the Hartree-Fock wave function . Ab initio methods: MP2, MP4 Example One: Consider the one-particle, one-dimensional system with potential-energy function V=b for L/4 < x < 3L/4, V=0 for 0 < x L/4 & 3L/4 x < L and V = elsewhere. Assume that the magnitude of b is small, and can be treated as a perturbation. Find the first-order energy correction for the ground and first excited states. The unperturbed wave functions of the ground and first excited states are y1 = (2/L)1/2 sin(x/L) and y2 = (2/L)1/2 sin(2x/L), respectively. Example Two: As the first step of the Moller-Plesset perturbation theory, Hartree-Fock method gives the zeroth-order energy. Is the above statement correct? Example Three: Show that, for any perturbation H’, E1(0) + E1(1) E1 where E1(0) and E1(1) are the zero-th order energy and the first order energy correction, and E1 is the ground state energy of the full Hamiltonian H0 + H’. Example Four: Calculate the bond orders of Li2 and Li2+. Perturbation Theory for a Degenerate Energy Level Hydrogen Atom n=3 n=2 n=1 3s, 3px , 3py , 3pz , 3d1-5 2s, 2px , 2py , 2pz 1s B/e H = H0 + H’ H0yn(0) = Ed(0) yn(0) H’ is small compared with H0 n=1,2,...,d (1)Apply the results of nondegenerate perturbation theory cnm = < ym(0) | H' | yn(0) > / [En(0)- Em(0)] for 1 m, n d WRONG ! something very different ! (2) What happened ? c1 y1(0) + c2 y2(0) + ... + cd yd(0) is an eigenstate for H0 There are infinite number of such states that are degenerate. When H’is switched on, these states are no longer degenerate, and nondegenerate eigenstates of H0 + H’ appear ! Therefore, even for zero-th order of eigenstates, there are sudden changes ! (3) Introducing a parameter l H(l) = H0 + lH’ H(l) yn(l) = En(l) yn(l) l = 1, the original Hamiltonian yn(l) = fn(0) + l yn(1) + l2 yn(2) + ... + lk yn(k) + ... En(l) = Ed(0) + l En(1) + l2 En(2) + ... + lk En(k) + ... fn(0) = k ck yk(0) H0yn(1) + H’ fn(0) = Ed(0) yn(1) + En(1)fn(0) solving for En(1), fn(0) , yn(1) Multiplied ym(0) from the left and integrate, <ym(0) | H0 | yn(1) > + < ym(0) | H' | fn(0) > = < ym(0)|yn(1) >Ed(0) + En(1) <ym(0)| fn(0) > <ym(0)|yn(1) > [Em(0)- Ed(0)] + < ym(0) | H' | fn(0) > = En(1) < ym(0)| fn(0) > For 1 m d, n [< ym(0) | H' | yn(0) > - Em(1)dmn] cn = 0 Em(1) = < fm(0) | H' | fm(0) > Assignment 2: 9.2, 9.4a, 9.9, 9.18, 9.24 Configuration Interaction (CI) + + … Single Electron Excitation or Singly Excited Double Electrons Excitation or Doubly Excited Singly Excited Configuration Interaction (CIS): Changes only the excited states + Doubly Excited CI (CID): Changes ground & excited states + Singly & Doubly Excited CI (CISD): Most Used CI Method Full CI (FCI): Changes ground & excited states + + ... + Coupled-Cluster Method y = eT y(0) y(0): Hartree-Fock ground state wave function y: Ground state wave function T = T1 + T2 + T3 + T4 + T5 + … Tn : n electron excitation operator T1 = Coupled-Cluster Doubles (CCD) Method yCCD = eT y(0) 2 y(0): Hartree-Fock ground state wave function yCCD: Ground state wave function T2 : two electron excitation operator T2 = Complete Active Space SCF (CASSCF) Active space All possible configurations Density-Functional Theory (DFT) Hohenberg-Kohn Theorem: The ground state electronic density (r) determines uniquely all possible properties of an electronic system (r) Properties P (e.g. conductance), i.e. P P[(r)] Density-Functional Theory (DFT) E0 = - (h2/2me)i <yi |i2 |yi >- dr Ze2(r) / r1 + (1/2) dr1 dr2 e2/r12 + Exc[(r)] Kohn-Sham Equation: FKS yi = ei yi FKS - (h2/2me)ii2 - Ze2 / r1 + j Jj + Vxc Vxc dExc[(r)] / d(r) Ground State Excited State CPU Time Correlation Geometry Size Consistent (CHNH,6-31G*) HFSCF 1 0 OK DFT ~1 CIS <10 OK CISD 17 CISDTQ MP2 1.5 MP4 CCD CCSDT 80-90% (20 electrons) very large 98-99% 5.8 85-95% (DZ+P) >90% large >90% very large ~100% Relativistic Effects Speed of 1s electron: Zc / 137 Heavy elements have large Z, thus relativistic effects are important. Dirac Equation: Relativistic Hartree-Fock w/ Dirac-Fock operator; or Relativistic Kohn-Sham calculation; or Relativistic effective core potential (ECP). Four Sources of error in ab initio Calculation (1) Neglect or incomplete treatment of electron correlation (2) Incompleteness of the Basis set (3) Relativistic effects (4) Deviation from the Born-Oppenheimer approximation Semiempirical Molecular Orbital Calculation Extended Huckel MO Method (Wolfsberg, Helmholz, Hoffman) Independent electron approximation Hval = i Heff(i) Heff(i) = -(h2/2m) i2 + Veff(i) Schrodinger equation for electron i Heff(i) fi = ei fi LCAO-MO: fi = r cri yr s ( Heffrs - ei Srs ) csi = 0 Heffrs < yr| Heff | ys > Srs < yr| ys > Parametrization: Heffrr < yr| Heff | yr > = minus the valence-state ionization potential (VISP) ----------------------------------------------------------------------- Atomic Orbital Energy e5 e4 e3 e2 e1 Heffrs = ½ K (Heffrr + Heffss) Srs VISP -e5 -e4 -e3 -e2 -e1 K: 13 CNDO, INDO, NDDO (Pople and co-workers) Hamiltonian with effective potentials Hval = i [ -(h2/2m) i2 + Veff(i) ] + ij>i e2 / rij two-electron integral: (rs|tu) = <yr(1) yt(2)| 1/r12 | ys(1) yu(2)> CNDO: complete neglect of differential overlap (rs|tu) = drs dtu (rr|tt) drs dtu rt INDO: intermediate neglect of differential overlap (rs|tu) = drs dtu (rr|tt) when r, s, t & u not on same atom; (rs|tu) 0 when r, s, t and u are on the same atom. NDDO: neglect of diatomic differential overlap (rs|tu) = 0 if r and s (or t and u) are not on the same atom. CNDO, INDO are parametrized so that the overall results fit well with the results of minimal basis ab initio Hartree-Fock calculation. CNDO/S, INDO/S are parametrized to predict optical spectra. PRDDO H = i [ -(h2/2m) i2 + Veff(i) ] + ij>i e2 / rij Basis set: the minimum basis set (STO-3G) PRDDO: partial retention of diatomic differential overlap (rs|tu) = 0 if r and s (and t and u) are different basis functions. MINDO, MNDO, AM1, PM3 (Dewar and co-workers, University of Texas, Austin) MINDO: modified INDO MNDO: modified neglect of diatomic overlap AM1: Austin Model 1 PM3: MNDO parametric method 3 MINDO, MNDO, AM1 & PM3: *based on INDO & NDDO *reproduce the binding energy Semiempirical M.O. Method Fock Matrix 1 core F = H + P - 2 Key: How to approximate ? MNDO-PM3 a b c d = d abd cd (using NDDO) F = V + U b, a b a F = U b , a ba F = b 1 + P - + P 2 b a , a b 1 + P [3 - ] + P 2 b a , b 1 - P 2 b a , = S ( + ) / 2 Where, V = - I - (Z a * a ) -1 aa I a : the ionization potential One centre integrals: (given) G ss = ss ss , G sp = ss pp , G p 2 = pp p' p' G pp = pp pp , hsp = sp sp Core-electron attraction: (given) [ = M m , M m l l l l m U b , , U b , 1 [M ] , = lm Ml m A B 1 2 l2 2 l1 + l2 f (R ) 2l1 2l 2 i =1 j =1 1 ij f (R ) 1 ij A 1 B 2 ] 2 A B 2 = R 2 + + ij l2 l1 1 2 l :characteristic of monopole, dipole, quadrupole Dl :charge separations Molecular Mechanics (MM) Method F = Ma F : Force Field Molecular Mechanics Force Field • • • • Bond Stretching Term Bond Angle Term Torsional Term Non-Bonding Terms: Electrostatic Interaction & van der Waals Interaction Bond Stretching Potential Eb = 1/2 kb (Dl)2 where, kb : stretch force constant Dl : difference between equilibrium & actual bond length Two-body interaction Bond Angle Deformation Potential Ea = 1/2 ka (D)2 where, ka : angle force constant D : difference between equilibrium & actual bond angle Three-body interaction Periodic Torsional Barrier Potential Et = (V/2) (1+ cosnt ) where, V : rotational barrier t : torsion angle n : rotational degeneracy Four-body interaction Non-bonding interaction van der Waals interaction for pairs of non-bonded atoms Coulomb potential for all pairs of charged atoms MM Force Field Types • • • • • MM2 AMBER CHAMM BIO OPLS Small molecules Polymers Polymers Polymers Solvent Effects Summary Hamiltonian H = (-h2/2m)2 - (h2/2me)ii2 + ZZe2/r - i Ze2/ri + i j e2/rij The variation theorem Consider a system whose Hamiltonian operator H is time independent and whose lowest-energy eigenvalue is E1. If f is any well-behaved function that satisfies the boundary conditions of the problem, then f* H f dt / f* f dt > E1 Variational Method (1) Construct a wave function f(c1,c2,,cm) (2) Calculate the energy of f: Ef Ef(c1,c2,,cm) (3) Choose {cj*} (i=1,2,,m) so that Ef is minimum Extension of Variation Method For a wave function f which is orthogonal to the ground state wave function y1, i.e. dt f*y1 = 0 Ef = dt f*Hf / dt f*f > E2 the first excited state energy The Pauli principle two electrons cannot be in the same state the wave function of a system of electrons must be antisymmetric with respect to interchanging of any two electrons. Slater determinant of H2 : y(1,2) = 1/2! [f(1)(1)f(2)(2) - f(2)(2)f(1)(1)] f(1)(1) f(2)(2) = 1/2! f(1)(1) f(2)(2) Hartree-Fock Equation: [ f(1)+ J2(1) - K2(1)] f1(1) = e1 f1(1) [ f(2)+ J1(2) - K1(2)] f2(2) = e2 f2(2) Fock Operator: F(1) f(1)+ J2(1) - K2(1) F(2) f(2)+ J1(2) - K1(2) LCAO-MO: Fock operator for 1 Fock operator for 2 f = c1y1 + c2y2 Express Hartree-Fock energy in terms of fi, Jij & Kij Molecule H2+ H2 He2+ He2 Li2 Be2 C2 N2+ N2 O2 Bond order 1/2 1 1/2 0 1 0 2 1/2 3 2 De/eV 2.79 4.75 1.08 0.0009 1.07 0.10 6.3 8.85 9.91 5.21 Basis set of GTFs STO-3G, 3-21G, 4-31G, 6-31G, 6-31G*, 6-31G** ------------------------------------------------------------------------------------- complexity & accuracy Gaussian 98 Input file # HF/6-31G(d) Route section water energy Title 0 O H H Molecule Specification (in Cartesian coordinates 1 -0.464 0.177 0.0 -0.464 1.137 0.0 0.441 -0.143 0.0 Comparison of the HF and VB Treatments Electron Correlation Beyond the Hartree-Fock Configuration Interaction (CI)* Perturbation theory* En(1) = < yn(0) | H' | yn(0) > Coupled Cluster Method Density functional theory Moller-Plesset (MP) Perturbation Theory The MP unperturbed Hamiltonian H0 H0 = m F(m) where F(m) is the Fock operator for electron m. And thus, the perturbation H’ H ’ = H - H0 Ground State Excited State CPU Time Correlation Geometry Size Consistent (CH3NH2,6-31G*) HFSCF 1 0 OK DFT ~1 CIS <10 OK CISD 17 CISDTQ MP2 1.5 MP4 CCD CCSDT 80-90% (20 electrons) very large 98-99% 5.8 85-95% (DZ+P) >90% large >90% very large ~100%