Ch 36-37 Magnetism & EMI - SchoolWorld an Edline Solution

advertisement
Magnetism
Magnetism:
Permanent and Temporary
See FSU’s site for much more information!!
http://micro.magnet.fsu.edu/electromag/index.
html
1
1
Magnetic Topics
• Magnetism, B
• Electromagnetic Induction
2
Assignments
• Read and write reflections on Ch 36&37 in
Conceptual Physics
Complete Summaries for 36&37
3
General Properties of Magnets
• Like magnetic poles repel; unlike magnetic
poles attract
• Magnetic field lines are directed from north
to south
• Magnetic field lines always form close
loops http://www.walterfendt.de/ph11e/mfbar.htm
• A magnetic field exists around any wire
that carries current
4
Gen’l Properties cont.
• Spinning electrons are small magnets.
• A current-carrying wire experiences a
force when the wire is perpendicular to a
magnetic field. A coil of wire that carries a
current has a magnetic field about a
permanent magnet
• http://micro.magnet.fsu.edu/electromag/jav
a/faraday/index.html
5
Magnetic Facts
The source of all magnetism is moving electric
charges.
Surrounding every moving electron is both an electric
field and a magnetic field.
Even in a broken magnet, there is N and S.
A small compass in a magnetic field will line up
parallel with the magnetic field lines.
Magnetic domains are regions of aligned atoms.
Magnets can attract unmagnetized objects by
temporarily producing magnetism in the object.
Magnetic fields are always produced by current
carrying wires.
6
The magnetic pole in the N Hemisphere is in
Canada.
The Earth’s magnetic field is probably due to
convection currents in Earth’s molten interior.
Magnetic deflection is the discrepancy between
magnetic and true norths.
The greatest force on an electron moving in a
magnetic field is when the angle of motion is 90o.
Cosmic rays are most intense at Earth’s poles
producing aurorae.
Earth’s geographic South pole is nearest its N pole.
Electric fields can increase a moving electron’s
speed.
7
• A magnetic force field can accelerate an
electron by changing its direction, not its
speed.
• If a current carrying wire in magnetic field
is caused to move down, current flowing in
the opposite direction will cause the wire
to move up.
8
Forces Caused by Magnetic
Fields
• When a current-carrying wire is placed in a
magnetic field, a force acts on the wire
that is perpendicular to both the field and
the wire. Meters operate on this principle.
• Magnetic field strength is measured in
tesla, T (one newton per ampere per
meter).
 b is the symbol for magnetic field
9
Forces cont.
• An electric motor consists of a coil of wire
(armature) placed in a magnetic field.
When current flows in the coil, the coil
rotates as a result of the force on the wire
in the magnetic field.
10
Forces cont.
• The force a magnetic field exerts on a
charged particle depends on the velocity
and charge of the particle and the strength
of the magnetic field. The direction of the
force is perpendicular to both the field and
particle’s velocity.
11
Key Equations
• F = BIL  Force on a current carrying
wire in a magnetic field. Force = magnetic
field strength x current x length of wire.
Newton = tesla x amp x meter
• F = BqV  Force of a magnetic field on a
single charged particle. Force = magnetic
field strength x charge x velocity of the
charge. Newton = tesla x coulomb x m/s
12
• E = - N DF / D t
• Ampere’s Rule for parallel, straight
conductors: F = 2k l I1 I2 / d
• Transformer Equations
• Pp = Ps  VpIp = VsIs
• Is = Vp = Np
• Ip Vs
Ns
• Induction
• M = -Es / D Ip/ D t
• L = -E / D I / D t
13
14
The small picture – how
magnetism occurs
Domain theory – when enough atoms of a
substance line up in the same direction
Strong magnets – iron and steel
Very strong – Alnico alloy
Weak – aluminum, platinum
Natural – magnetite or lodestodes formed
when rock was molten
15
Magnetic field lines
Magnetic flux, (F) – number of field lines
passing through a surface
Unit: weber = 1 nm/amp
Magnetic flux density, B = F /A
Unit: wb/m2 = nm/a m2 = n/am
1 wb/m2 = 1 Tesla
Earth, 10–4 T
Humans, 10–11 T
16
Hand Rule #1- B field direction
around a current carrying wire
• Point thumb in direction of current in the
wire
• Fingers of your hand circle the wire and
show the direction of the magnetic field
– Knuckles, N
– Finger tips, S
– http://www.walter-fendt.de/ph11e/mfwire.htm
17
18
Hand Rule #2 – Determine the
polarity of an electromagnet
• Wrap the fingers of your right hand around
the loops in the direction of the current
• Extended thumb points toward the N pole
of the electromagnet
19
Solenoid – conducting linear coil
which acts like a bar magnet
Increase B, magnetic flux density by
Increasing the current
Adding loops of wire
Inserting an iron core into solenoid – now it is
an electromagnet
20
Hand rule #3 – shows force
acting on wire in B field
•
•
•
•
•
Lay right hand flat, palm up
Extend thumb 90 degrees to rest of fingers
Fingers point in direction of B field
Thumb points in direction of current, I
Imaginary vector coming up perpendicular
out of the palm points in the direction of
force acting on current carrying wire.
21
Fingers point
in direction
of b field
Thumb direction of
current flow
Imaginary
vector
coming from
palm is
direction that
conductor is
forced out of
the field
22
23
Sample Problems
• A straight wire that carries a 5.0 amp
current is in a uniform magnetic field
oriented at right angles to the wire. When
0.10 m of the wire is in the field, the force
on the wire is 0.20 n. What is the strength
of the magnetic field, B?
24
Solution
Known:
I = 5.0 amp
L = 0.10m
F = 0.20 N
F=BIL  B = F/IL
= 0.20N/5.0 amp(0.10m)
= 0.40 T
Unknown:
B =?
25
Sample Problem
A beam of electrons travels at 3.0 x 106
m/s through a uniform magnetic field of
4.0 x 10–1 T at right angles to the field.
How strong is the force that acts on
each electron?
Known
Unknown
V = 3.0 x 106 m/s
F =?
B = 4.0 x 10–1 T
Q = - 1.6 x 10–19 c
26
Solution
F = BqV
= 4.0 x 10–1 T (-1.6 x 10–19c)(3.0 x 106 m/s)
= -1.9 x 10–13 Tcm/s
= -1.9 x 10 -13 n
27
Moving Charges in a Magnetic Field
Right-Hand Rule for Moving Charges
28
Sources
• http://www.walterfendt.de/ph11e/electricmotor.htm
• http://www.walterfendt.de/ph11e/lorentzforce.htm
• Other physics information: http://www.walterfendt.de/ph11e/
• Great diagrams of magnetic rules:
http://sol.sci.uop.edu/~jfalward/magneticforcesfie
lds/magneticforcesfields.html
29
Electromagnetic Induction (EMI)
•Relative motion between a conductor and a
magnetic produces both current and a magnetic
field
•Electric current can be induced in a wire by
moving a magnet up and down near the wire
•More loops in a coil of wire (solenoid) increases
the voltage produced
•Placing an iron rod in a current-carrying wire,
yields a greater magnetic field
30
•A generator changes mechanical energy to
electrical energy. A motor does opposite
•An e-m wave contains perpendicular electric
and magnetic fields
•E-M waves travel at the speed of light
31
Michael Faraday and Joseph
Henry around the same time…
• Discovered that when there is relative
motion between a magnetic field and a
complete circuit (and the conductor cuts
across the magnetic field), that electricity
will flow!!! An induced EMF causes
electricity to flow.
32
If current flows, there must be
an EMF – this is EM induction
Faraday’s Law of Induction:
E = - N DF / D t
E, emf, volts
-N, # of turns of wire (- means the current opposes
the change that induced it)
DF, change in flux in weber, wb
D t, change in time, sec
This essentially says that the induced voltage in a
coil is proportional to the product of the number of
loops and the rate at which the magnetic field
changes within those loops.
33
Sample Problem
If a coil of 200 turns is moved
perpendicularly in a magnetic field at a
constant rate, find the induced emf. The
flux linkage change ( DF / D t)
is 4.00 x 10-6 wb in 0.0100 sec.
34
If a coil of 200 turns is moved perpendicularly in a
magnetic field at a constant rate, find the induced
emf. The flux linkage change ( DF / D t)
is 4.00 x 10-6 wb in 0.0100 sec.
E = - N DF
Dt
E = (-200)(4.00 x 10 –6 wb)
1.00 x 10 –2 s
E = -8.00 x 10 –2 v
Imagine what thousands of turns would
produce!
35
Electric Generators
• Convert mechanical energy into electrical
energy by rotating a looped conductor
(armature) in a magnetic field
• Alternating-Current electricity produced is
conducted by slip rings and brushes to be
used
*
• Direct current can be produced by using
split rings
*
36
A coil with a wire is wound around a 2.0 m2 hollow
tube 35 times. A uniform magnetic field is applied
perpendicular to the plane of the coil. If the field
changes uniformly from 0.00 T to 0.55 T in 0.85 s,
what is the induced emf in the coil?
A = 2.0 m2
N = 35
B = .55 T
Dt = 0.85 s
E = -N D F / D t = - NBA / D t
E = 35 (0.55 T) (2 m 2)
0.85s
E = 45.3 v
37
Generator Output
Rectifier changes AC to DC
Inverter changes DC to AC
38
Lenz’s Law • The direction of an induced current is such
that the magnetic field resulting from the
induced current opposes the change in he
field that caused the induced current.
• When the N pole of a magnet is moved
toward the left end of a coil, that end of the
coil must become a N, causing induced
current flow in opposition.
39
Inductance
• The property of an electric circuit by which
a varying current induces a back emf in
that circuit or a neighboring circuit.
• Mutual Inductance, M
• Self Inductance, L
http://www.powertransformer.us/prima
ryvoltage.png
40
Mutual Inductance, M
• Effect that occurs in a transformer when a
varying magnetic field created in the
primary coil is carried through the iron core
to the secondary coil, where the varying
field induces a varying emf.
• M = -Es / D Ip/ D t
41
M
=
-Es
D Ip/ D t
Shows the ratio of induced emf in one circuit
to the rate of change of current in the other
circuit.
M, inductance, Henry
Es, average induced emf across secondary
D Ip/ D t, time rate of change in current in
primary coil
- sign, induced v opposes D I (Lenz’s law)
42
Two coils have a mutual inductance of 1.25 henrys. Find
the average emf induced in the secondary if the current in
the primary builds up to 10.0 amp in 0.0250 sec after the
switch is closed.
M = - Es
So, Es = -M DIp
DIp/D t
Dt
Es = -1.25 h (10.0 a)
0.0250 s
Es = -500. v or 5.00 x 102 v
43
Self Inductance
Ratio of induced emf across a coil to the rate
of change of current in the coil
L = -E / D I / D t
L, henry
I, current, amp
t, time, sec
44
Transformer
• Two separate coils of wire placed near one
another that are used to increase or decrease
AC voltages with little loss of energy.
• It contains a Primary coil and a Secondary coil
• When the primary is connected to AC voltage,
the changing current creates a varying magnetic
field that is carried through the core to the
45
secondary coil.
Transformer, cont.
In the secondary coil, the varying field
induces a varying emf. This is called
mutual inductance
Secondary voltage = secondary #turns
Primary voltage
primary # turns
Power = Voltage x Current
46
Transformers lose no power
•
•
•
•
Pp = Ps  Vp Ip = Vs Is
Transformer Equation:
Is = Vp = Np
Ip Vs
Ns
47
Transformer Problem
A step-up transformer has a primary coil consisting of
200 turns and a secondary coil that has 3000 turns.
The primary coil is supplied with an effective AC
voltage of 90.0v. A) What is the Vs? B) If Is = 2.00a,
find Ip. C) What is the power in the primary circuit?
A. Vs = NsVp/Np = 3000(90.0V) / 200 = 1.35 kV
B. Pp = Ps, VpIp = VsIs  Ip = VsIs/Vp =
Ip =1350v(2.00a) / 90.0v = 30.0a
C. Pp = Vp Ip = 90.0v(30.0a) = 2.70 kW
48
Download