4-34. Review what you have learned in the previous lessons by factoring the following expressions, if possible. 81m2 – 1 • (9m + 1)(9m − 1) 3n2 + 9n + 6 • (3n + 3)(n + 2) or (n + 1)(3n + 6) 4.1.4 FACTORING COMPLETELY November 18, 2015 Objectives • CO: SWBAT factor first a common factor and then use the quadratic factoring method. • LO: SWBAT explain to a partner how to factor completely. 4-35. Compare your factored expressions for problem 4-34 with the rest of your class. a. Is there more than one factored form of 3n2 + 9n + 6? Why or why not? Yes, because you can build two different rectangles with algebra tiles. b. Why does 3n2 + 9n + 6 have more than one factored form while the other quadratics in problem 4-34 only have one possible factored form? Look for clues in the original expression and in the different factored forms. Because it has a common 3 to be factored out of the expression. c. Without factoring, predict which quadratic expressions below may have more than one factored form. Be prepared to defend your choice to the rest of the class. i. 12t2 – 10t + 2 ii. 5p2 – 23p + 10 i & iii; they have common factors. iii. 10x2 + 25x − 15 iv. 3k2 + 7k – 6 4-36. FACTORING COMPLETELY In part (c) of problem 4-35, you should have noticed that each term in 12t2 – 10t + 2 is divisible by 2. That is, each term in the expression has a common factor of 2. a. An expression is considered completely factored if none of the factors can be factored further. Often it is easiest to remove common factors first, before factoring with an area model. Rewrite the expression 10x2 + 25x − 15 with the common factor factored out. 5(2x2 + 5x − 3) b. Your result in part (a) is not completely factored because the trinomial factor can still be written as a product of two factors. Factor 10x2 + 25x − 15 completely. 5(2x – 1)(x + 3) 6x -3 2x2 -1x -6x2 6x -1x 5x 4-37. Factor each of the following expressions completely. a. 5x2 + 15x − 20 5(x2 + 3x − 4) 4x + -1x 5(x + 4)(x − 1) b. 3x3 − 6x2 – 45x 3x(x2 − 2x – 15) -5x + 3x 3x(x + 3)(x − 5) 4-38. CLOSED SETS Whole numbers (positive integers and zero) are said to be a closed set under addition: if you add two whole numbers, you always get a whole number. Whole numbers are not a closed set under subtraction: if you subtract two whole numbers, you do not always get a whole number. For example, 2 – 5 = –3, and –3 is not a whole number. a. Investigate whether the integers are a closed set under addition, and whether the integers are a closed set under subtraction. That is, will adding two integers always give you an integer? Will subtracting two integers always give you an integer? Give examples. Integers are closed under addition: 1 + (-2) = -1 Integers are closed under subtraction: 3 – 4 = -1 b. If you decided that integers are closed under either addition or subtraction, can you explain how you know they are closed for all integers? Use mathematical reasoning, not just examples, to justify your answer. If you start at an integer on the number line and add or subtract an integer, you will always step to the left or right along the integers; you never end up between integers. c. Now consider multiplication and division. Are integers a closed set under multiplication? Are integers a closed set under division? Use examples and reasoning to justify your answer. Integers are closed under multiplication because if you multiply two integers you will never get a fraction or decimal. (1 ∙ 3 = 3) Integers are not closed under division, for example, 1 ÷ 2 = 1/2