Exam Review 10am - Iowa State University

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Exam 1 Review 10am Section
Supplemental Instruction
Iowa State University
Tess
Math 267
Basnet
2/9/2016
Exam 1 Information:
Molecular Biology 1414 10-10:50am.
Sections Covered: 1.1-1.3, 2.1-2.5, 3.1-3.
Integral Review
Integral
Solution
Integral
1
∫ 2
𝑑𝑒
𝑒 + π‘Ž2
Solution
1
π‘‘π‘Žπ‘›−1 𝑒 + 𝐢
π‘Ž
∫ 𝑒 𝑒 𝑑𝑒
𝑒𝑒 + 𝐢
1
∫ 𝑑𝑒
𝑒
ln⁑|𝑒| + 𝐢
∫ π‘π‘ π‘π‘’β‘π‘π‘œπ‘‘π‘’β‘π‘‘π‘’
−cscu + 𝐢
∫ 𝑙𝑛𝑒⁑𝑑𝑒
𝑒⁑𝑙𝑛𝑒 − 𝑒 + 𝐢
∫ 𝑠𝑒𝑐𝑒⁑𝑑𝑒
ln(𝑠𝑒𝑐𝑒 + π‘‘π‘Žπ‘›π‘’) + 𝐢
∫ π‘Žπ‘’ 𝑑𝑒
1 𝑒
π‘Ž +𝐢
π‘™π‘›π‘Ž
∫ 𝑠𝑖𝑛𝑒⁑𝑑𝑒
−π‘π‘œπ‘ π‘’ + 𝐢
∫ 𝑠𝑒𝑐 2 𝑒⁑𝑑𝑒
π‘‘π‘Žπ‘›π‘’ + 𝐢
∫
1
√π‘Ž2 − 𝑒2
𝑑𝑒
∫ 𝑠𝑖𝑛𝑒⁑𝑑𝑒
∫ 𝑒𝑛 𝑑𝑒
𝑒
+𝐢
π‘Ž
−π‘π‘œπ‘ π‘’ + 𝐢
𝑠𝑖𝑛−1
𝑒𝑛+1
+𝐢
𝑛+1
Additional Methods:
2π‘₯
ο‚· U-Substitution → find u and du and sub into equation Ex) ∫ π‘₯ 2 +1 𝑑π‘₯
ο‚·
Integration by Parts → ∫ 𝑒𝑑𝑣 = 𝑒𝑣 − ⁑ ∫ 𝑣𝑑𝑒 Ex) ∫ π‘₯𝑒 π‘₯ 𝑑π‘₯
Method Review
Method
Separable 2.2
Linear (Standard) 2.3
Exact 2.4
Integration Factor 2.4
Bernoulli’s 2.5
General Form
𝑑𝑦
= 𝑔(π‘₯)β„Ž(𝑦)
𝑑π‘₯
𝑑𝑦
+ 𝑃(π‘₯)𝑦 = 𝑓(π‘₯)
𝑑π‘₯
𝑀(π‘₯, 𝑦)𝑑π‘₯ + 𝑁(π‘₯, 𝑦)𝑑𝑦 = 0
𝑀𝑦 − 𝑁π‘₯
𝑁π‘₯ − 𝑀𝑦
β‘π‘œπ‘Ÿβ‘
𝑁
𝑀
𝑑𝑦
+ 𝑃(π‘₯)𝑦 = 𝑓(π‘₯)𝑦 𝑛
𝑑π‘₯
Example DE
𝑑𝑦
𝑦𝑒 π‘₯
= 𝑒 −𝑦 + 𝑒 −2π‘₯−𝑦
𝑑π‘₯
𝑑𝑦
(π‘₯ + 1)
= 𝑒 π‘₯ (1 + 𝑦)
𝑑π‘₯
3
𝑑𝑦
3
(1 + + π‘₯)
+𝑦 = −1
𝑦
𝑑π‘₯
π‘₯
𝑦(π‘₯ + 𝑦 + 1)𝑑π‘₯ + (π‘₯ + 2𝑦)𝑑𝑦 = 0
𝑑𝑦
− 𝑦 = 𝑒 π‘₯𝑦2
𝑑π‘₯
1060 Hixson-Lied Student Success Center  515-294-6624  sistaff@iastate.edu  http://www.si.iastate.edu
1. Solve the following IVP:
π‘₯
𝑑𝑦
+ 𝑦 = 𝑦 2 π‘₯ 2 𝑙𝑛π‘₯; ⁑⁑⁑⁑⁑𝑦(1) = 4
𝑑π‘₯
2. Determine if the following DE is exact, if not determine the integrating factor and solve
for general solution:
π‘₯ 2 𝑦⁑𝑑π‘₯ + 𝑦(π‘₯ 3 + 𝑒 3𝑦 )𝑑𝑦 = 0
3. Consider the following autonomous DE:
a. Determine the critical Points
𝑑𝑃
𝑑π‘₯
= −10 + 𝑃2 + 3𝑃
b. Create a phase porrate and classify points as stable, unstable or semi-stable
4. A small metal bar, whose initial tempeature was 20℃, is dropped into a large container
of boiling water.
a. How long will is take the bar to reach 90℃ if it is known that its temperature
increases 2℃ in 1 second?
5. Solve the following DE and give the general solution:
𝑑𝑦
3𝑦π‘₯ 2
(1 + 3𝑦𝑠𝑒𝑐 2 𝑦 + 4𝑦 4 )
+ 3
= 0⁑
𝑑π‘₯ (π‘₯ + 2)
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