Family of Quadratic Functions Lesson 5.5a General Form • Quadratic functions have the standard form y = ax2 + bx + c a, b, and c are constants a≠0 (why?) • Quadratic functions graph as a parabola Zeros of the Quadratic • Zeros are where the function crosses the xaxis Where y = 0 • Consider possible numbers of zeros None (or two complex) One Two Axis of Symmetry • Parabolas are symmetric about a vertical axis • For y = ax2 + bx + c the axis of symmetry is at b x 2a • Given y = 3x2 + 8x What is the axis of symmetry? Vertex of the Parabola • The vertex is the “point” of the parabola The minimum value Can also be a maximum • What is the x-value of the vertex? x b 2a • How can we find the y-value? b y f ( x) f 2a Vertex of the Parabola • Given f(x) = x2 + 2x – 8 • What is the x-value of the vertex? b 2 x 1 2a 2 1 • What is the y-value of the vertex? f (1) 1 2 9 9 • The vertex is at (-1, -9) Vertex of the Parabola • Given f(x) = x2 + 2x – 8 Graph shows vertex at (-1, -9) • Note calculator’s ability to find vertex (minimum or maximum) Shifting and Stretching • Start with f(x) = x2 • Determine the results of transformations ___ f(x + a) = x2 + 2ax + a2 ___ f(x) + a = x2 + a ___ a * f(x) = ax2 ___ f(a*x) = a2x2 a) horizontal shift b) vertical stretch or squeeze c) horizontal stretch or squeeze d) vertical shift e) none of these Other Quadratic Forms • Standard form y = ax2 + bx + c • Vertex form y = a (x – h)2 + k Experiment with Quadratic Function Spreadsheet Then (h,k) is the vertex • Given f(x) = x2 + 2x – 8 Change to vertex form Hint, use completing the square Vertex Form • Changing to vertex form Add something in to make a perfect square trinomial y x2 2x 8 y x 2x 8 2 y x 2 Now create a binomial squared Subtract the same amount to keep it even. This gives us the ordered pair (h,k) Assignment • Lesson 5.5a • Page 231 • Exercises 1 – 25 odd