Fisher, Section 7.4 Algebra 2 7.4 Properties of Logarithms Name:______________________________ Date:_______________Pd:_____________ Teacher Do 7.4 – Properties of Logarithms I. Properties of Logarithms (similar to exponent properties) Product: log b mn log b m log b n Quotient: log b Power: log b m p p log b m m log b m log b n n II. Simplifying Logarithms Write each expression into a single logarithm. Simplify when possible. coefficients_______________ as exponents inside the log Rewrite ____ Rewrite addition/subtraction of logs as multiplication/division of bases. TEACHER DO: Write as a single logarithm Example 1: 3log520 - 2log510 log520³- log510² Step #1: Write coefficient as an exponent log58000 - log5100 ** Remember need to have same base 8000 log5 100 = Step #2: Rewrite subtraction of log as division of bases log5 80 1 Fisher, Section 7.4 Example #2: log 2 + log 4 – log 7 log b mn log b m log b n log (2·4) = 8 log 8 log b 7 m log b m log b n n 8 7 Answer: log Students Do: Write as a single logarithm 1. log 7 + log 2 2. log 6 − log 3 log (7·2)= log 14 3. log 6 log 3 log35=log 243 2 1 = log4 3 6 log4 =2.38 5. 2log26 – log29 6. 6 log 2 𝑥 + 5 log 2 𝑥 = log262 – log29 = = log236– log29 = = log2 36 = log24 9 2 log42 - log46 4. 5 log 3 = log log2x6 + log2x5 log2 (x6 · x5) = log2 x 11 2 Fisher, Section 7.4 7. log 4 5 + log 4 3 8. log 3 𝑦 + log 3 8𝑥 − log 3 4 log4 (5· 3) log3 (y· 8x) log4 15 log3 8xy 4 log3 2xy III. Expanding Logarithms Rewrite multiplication/division of bases as addition and subtraction of logs. Bring exponents down in front of the logarithm as a coefficient Teacher Do Expand each logarithm 1. log3 12 5 = log3 12 - log3 5 2. log5 7³= 3log57 3. log4 (4·3)= log4 4 + log4 3 3 Fisher, Section 7.4 Students Do Expand each logarithm. 4𝑥 1. log 𝑦 2. log 3 log 4x – log y log3 250 - log3 37 250 37 3. log 3 9𝑥 5 log b m p p log b m 5 log39x IV. Change of Base formula We can evaluate log 53 » 1.724276 and ln 75 » 4.317488 in our calculator because calculators can evaluate two types of logarithms, common logarithms (base 10) and natural logarithms (base e). What if we need to evaluate log3 89 or log7215? Neither of these problems can simply get typed into the calculator because calculators do not have log base 3 or log base 7 buttons. In order to evaluate logarithms with ANY base, we can use the following formula: log b x log a x log a b Teacher Do Evaluate log389 log389=x 89= 3x log (89)= log (3x) log 89=x log (3) log 89 log 3 =x 4.085 =x 4 Fisher, Section 7.4 STUDENTS DO: Use the Change of Base formula to evaluate the expression. 1. log 81 27 log8127=x 27=81x log (27)= log (81x) log 27=x log (81) log 27 = x log 81 x=.75 2. log 5 36 log536=x 36=5x log (36)= log (5x) log 36= xlog (5) log 36 log 5 =x x=2.22 3. log 2 50 log (50) = log (2x ) log 50= x log 2 log 50 log 2 =x 5 Fisher, Section 7.4 Students-EXTRA Practice- end of class independent work V. Use properties of logarithms to evaluate each expression. 1. log 2 4 − log 2 16 2. log 6 12 − log 6 2 1 3. log 4 48 − 2 log 4 9 You Try Write each expression into a single logarithm. Simplify when possible. 1. log 2 9 + log 2 3 2. log 6 12 + log 6 𝑥 3. log 6 5 − log 6 𝑥 4. log 4 32 − log 4 2 5. 4log 3 2 6. 2 log 7 6 − log 7 9 7. 4 log 𝑚 − 3log 𝑛 8. Log 3 𝑥 + 2log 3 𝑦 − log 3 𝑧 Expand each logarithm. 1. log 7𝑥 𝑟 4. log 5 𝑠 2. log14 𝑥 3 𝑦 5 3. log 7 49𝑥𝑦𝑧 5. log 4 5√𝑥 6. Use the Change of Base formula to evaluate the expression. 1. log 2 9 2. log12 20 6