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12.1-12.4 Review

1.

A landscape architect represents a flower bed by a polygon with vertices (1, 0) , (4, 0) ,(4, 2) , and (1, 2) . She decides to move the flower bed to a new location by translating it along the vector

-4,

-3

. Determine the flower beds final position.

2.

ABC with vertices A (1, 0) , B (1, 3) , and C (2, 3) is reflected across the y-axis, and then its image is reflected across the xaxis. Describe a single transformation that moves the triangle from its starting position to its final position.

3.

What happens to the point (3,4) when it is reflected across the x-axis?

4.

Determine the coordinates of the image when the point P(-5, -3) is reflected across the line x = -2.

5.

The point Q(-5, 2) is reflected across the line y = 1 and then rotated 90°about the origin. Determine the final coordinates of the image after the composition of transformations.

6.

The vertices of rectangle ABCD are A(1,1) B (3,1) C (1, 4) D (3,4).

The rectangle is translated along a vector. What vector would make the figure by completely in the third quadrant? a.

< -5 , - 4 > b.

< -4 , -4 > c.

< -5 , -5 > d.

< -6 , -4 >

7.

Which shows the image of after an 180˚ rotation about the point given? a.

b.

c.

d.

8.

A (-4, 14) is translated so that the image of A is A’(-4,8). A composition of reflections across the lines of which equations creates the same image. a.

y= 2 ; y= -1 b.

y= 4 ; y= -4 c.

y= 7 ; y= 3 d.

y= 3 ; y= 7

9.

The composition of two reflections across two parallel lines is equivalent to which isometry? a.

Rotation b.

Glide rotation c.

Translation d.

Reflection

Rotate the figure with the given vertices about the origin using the given angle of rotation.

10.

A (1, 0) , B (4, 1) , C (3, 2) ; 180°

11.

R (-2, 0) , S (-2, 4) , T (-3, 4) , U (-3, 0) ; 90°

12.

W(4, 5)X (3, 4)Y(-2,7); 270˚

Answer Sheet

1.

(-3,-3); (0,-3); (0,-1); (-3, -1)

2.

Rotation of 180

3.

(3, -4)

4.

P’(1, -3)

5.

Q”(0, -5)

6.

C

7.

C

8.

A

9.

C

10.

A’(-1,0); B’(-4,-1); C’(-3,-2)

11.

R’(0,-2); S’(-4, -2); T’(-4,-3); U’(0,-3)

12.

W’(5,-4); X’(4,-3); Y’(7,2)

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