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Unit 28

Vibrationdata

Multi-degree-of-freedom System

Shock Response Spectrum

1

Introduction

Vibrationdata

• The SRS can be extended to multi-degree-of-freedom systems

• There are two options

1.

Modal transient analysis using synthesized waveform

2.

Approximation techniques using participation factors and normal modes

2

Two-dof System Subjected to Base Excitation

Vibrationdata

Damping will be applied as modal damping

3

Free-Body Diagrams k

2

( x

2

x

1

) m

1 x

1 k

1

( x

1

y )

F

 m

1

 x 

1 m

1

 x 

1

 k

1

 k

2

 x

1

 k

2 x

2

 k

1 y m

2

Vibrationdata x

2 k

2

(x

2

-x

1

)

F

 m

2

 x 

2 m

2

 x 

2

 k

2 x

2

 k

2 x

1

0

4

Equation of Motion

Assemble the equations in matrix form

The equations are coupled via the stiffness matrix

 m

1

0

0 m

2

 x x 

1

2

 k

1

 k k

2

2

 k k

2

2

 x x

1

2

 k

1

0 y

Vibrationdata

5

Relative Displacement Substitution

Vibrationdata

Define relative displacement terms as follows x

1 x

2

 z

1 z

2

 y y

This works for some simple systems.

Enforced acceleration method is required for other systems.

The resulting equation of motion is

 m

1

0

0 m

2

 z z 

1

2

 k

1

 k k

2

2

 k k

2

2

 z z

1

2

 m

1

 y  m

2

 y 

6

General Form

M  z  

K z

F where

M

 m

1

0

0 m

2

 , K

 k

1

 k k

2

2

 k

2 k

2

 , F

 m m

1

2

 y 

 y 

Vibrationdata

7

Decoupling

Vibrationdata

• Decouple equation of motion using eigenvalues and eigenvectors

• The natural frequencies are calculated from the eigenvalues

• The eigenvectors are the “normal modes”

• Details given in accompanying reference papers

8

Proposed Solution

Vibrationdata

Seek a harmonic solution for the homogeneous problem of the form z

 q exp where j

 

1

= the natural frequency (rad/sec) q

= modal coordinate vector or eigenvector

9

Solution Development

The solution and its derivatives are z

 q exp

 z

 j

 q exp

 j

 t

 z     2 q exp

 j

 t

Substitute into the homogeneous equation of motion

  2

M q exp

 j

 t

K q exp

 j

 t

0

 2

M

K

 q exp

 j

 t

0

Vibrationdata

10

Generalized Eigenvalue Problem

Eigenvalues

 2 are calculated via det

K

  2

M

0 where

K is the stiffness matrix

M is the mass matrix

 is the natural frequency (rad/sec)

Vibrationdata

There is a natural frequency for each degree-of-freedom

11

Generalized Eigenvalue Problem (cont)

Vibrationdata

Calculate eigenvectors q

K

  2

M

 q

0

• The eigenvectors describe the relative displacement of the degrees-offreedom for each mode

• The overall motion of the system is a superposition of the individual modes for the case of free vibration

• There is a corresponding mode shape for each natural frequency

12

Eigenvector Relationships

Vibrationdata

Form matrix from eigenvectors

 qˆ qˆ

11

21 qˆ

12 qˆ

22

Mass-normalize the eigenvectors such that

Q

T

M

I (identity matrix)

Then

Q

T

K

 

(diagonal matrix of eigenvalues)

13

Decouple Equation of Motion

Define a modal displacement coordinate

 z

Q

Substitute into the equation of motion

M

K

 

F

Premultiply by T

T

M

 T

K

  T

F

Orthogonality relationships yields

I

    T

F

Vibrationdata

14

Modified Equation of Motion

• The equation of motion becomes

1

0

0

1

 

1

2

 

1

2

0

0

2

2

1

2

 qˆ

11 qˆ

12 qˆ

21 qˆ

22

 m

1

  m

2

 

Vibrationdata

• Now add damping matrix

1

0

0

1

 

1

2

2

1

0

1

2

2

0

2

1

2

 

1

2

0

0

2

2

1

2

 qˆ

11 qˆ

12 qˆ

21 qˆ

22

 m

1

  m

2

 

 i is the modal damping for mode i

15

Candidate Solution Methods, Time Domain

Vibrationdata

1.

Runge-Kutta - becomes numerically unstable for “stiff” systems

2.

Newmark-Beta - reasonably good – favorite of Structural

Dynamics textbooks

3.

Digital recursive filtering relationship - best choice but requires constant time step

16

Digital Recursive Filtering Relationship

Vibrationdata

• The digital recursive filtering relationship is the same as that given in Webinar 17, SDOF Response to Applied Force - please review

• The solution in physical coordinates is then z

Q

17

Participation Factors

Vibrationdata

• Participation factors and effective modal mass values can be calculated from the eigenvectors and mass matrix

• These factors represent how “excitable” each mode is

• Might cover in a future Webinar, but for now please read:

T. Irvine, Effective Modal Mass & Modal Participation

Factors, Revision F, Vibrationdata, 2012

18

Participation Factors

Vibrationdata

• Participation factors and effective modal mass values can be calculated from the eigenvectors and mass matrix

• These factors represent how “excitable” each mode is

• Might cover in a future Webinar, but for now please read:

T. Irvine, Effective Modal Mass & Modal Participation

Factors, Revision F, Vibrationdata, 2012

19

Participation Factors

 i is the participation factor for mode i i

2

 i

 i i

  i

2  i

   i

 y 

For the two-dof example in this unit

1

2

 qˆ

11 qˆ

12 qˆ

21 qˆ

22

 m

1 m

2

Vibrationdata

20

MDOF Estimation for SRS

• ABSSUM – absolute sum method

• SRSS – square-root-of-the-sum-of-the-squares

• NRL – Naval Research Laboratory method

Vibrationdata

21

ABSSUM Method

Vibrationdata

• Conservative assumption that all modal peaks occur simultaneously

  max

 j

N

1 qˆ i j

 j max max

 j

N

1

 j qˆ i j

D j , max

Pick D values directly off of

Relative Displacement SRS curve qˆ i i and mode j

These equations are valid for both relative displacement and absolute acceleration.

22

SRSS Method

Vibrationdata

  max

N

 j

1

 qˆ i j

 j , max

2

  max

N

 j

1

 j qˆ i j

D j , max

2

Pick D values directly off of

Relative Displacement SRS curve

These equations are valid for both relative displacement and absolute acceleration.

23

Example: Avionics Component & Base Plate

Vibrationdata m

2

= 5 lbm k

2

= 4.6e+04 lbf/in m

1

= 2 lbm k

1

= 4.6e+04 lbf/in

Q=10 for both modes

Perform

1.

normal modes

2.

Transmissibility analysis

24

Vibrationdata vibrationdata > Structural Dynamics > Spring-Mass Systems > Two-DOF System Base Excitation

25

Normal Modes Results

>> vibrationdata

Natural Participation Effective

Mode Frequency Factor Modal Mass

1 201.3 Hz 0.1311 0.0172

2 706.5 Hz 0.03063 0.0009382

modal mass sum = 0.01813 lbf sec^2/in (7.0 lbm) mass matrix

0.0052 0

0 0.0130

stiffness matrix

92000 -46000

-46000 46000

ModeShapes =

4.5606 13.1225

8.2994 -2.8844

Vibrationdata

26

Enter Damping

Vibrationdata

27

Transmissibility Analysis

Vibrationdata

28

Acceleration Transmissibility

Vibrationdata

29

Relative Displacement Transmissibility

Vibrationdata

Relative displacement response is dominated by first mode.

30

SRS Base Input to Two-dof System

Vibrationdata

SRS Q=10

Natural

Frequency

(Hz)

10

2000

10,000

Peak

Accel (G)

10

2000

2000 srs_spec =[10 10; 2000 2000; 10000 2000]

Perform:

1.

Modal Transient using

Synthesized Time History

2.

SRS Approximation

31

Modal Transient Method, Synthesis

Vibrationdata

File: srs2000G_accel.txt

32

Modal Transient Method, Synthesis (cont)

Vibrationdata

33

Vibrationdata

External File: srs2000G_accel.txt

34

Modal Transient Response Mass 1

Vibrationdata

35

Modal Transient Response Mass 2

Vibrationdata

36

SRS Approximation for Two-dof Example

Vibrationdata

37

Comparison

Peak Accel (G )

Mass

1

2

Modal

Transient

365

241

SRSS

309

228

Vibrationdata

ABSSUM

404

282

Both modes participate in acceleration response.

38

Comparison (cont)

Peak Rel Disp (in)

Mass

1

2

Modal

Transient

0.029

0.055

SRSS

0.030

0.053

Vibrationdata

ABSSUM

0.034

0.054

Relative displacement results are closer because response is dominated by first mode.

39

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