Algebra 3 Chapter 7: Powers, Roots, and Radicals Lesson 3: Power

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Warm Up
ο‚›Solve
3
ο‚›1. 5(π‘₯ − 1)
ο‚›2.
π‘₯ − 3 + (π‘₯ 2 − 1)
2
ο‚›3.
π‘₯ + 2 − (π‘₯ − 1)
ο‚›4.
π‘₯−3 π‘₯+2
2
ο‚›5.
(π‘₯ − 4)
Algebra 3
Chapter 7: Powers,
Roots, and Radicals
Lesson 3: Power
Functions and
Function Operations
VOCAB
ο‚›Power
Function – an equation in
𝑏
the form 𝑦 = π‘Žπ‘₯
ο‚›Composition – is when the domain
of the function H is the set of all x
values such that x is in the domain
of g and g(x) is in the domain of f.
β„Ž π‘₯ = 𝑓(𝑔 π‘₯ )
TODAY
ο‚›Today
we will learn how
to combine 2 or more
functions using basic
operations.
Directions (Operations on
Functions)
ο‚›Addition – Combine like terms
ο‚›Subtraction - Combine like terms
ο‚›Multiplication – Distribute / FOIL
ο‚›Division – Long / Synthetic
ο‚›+- Powers don’t change
ο‚›*
Powers add
ο‚›Division
Powers subtract
ο‚›Solve
I DO (Basic
operations)
2
𝑓 π‘₯ = 3π‘₯ 3
ο‚›1. 𝑓 π‘₯ + 𝑔(π‘₯)
ο‚›2. 𝑓 π‘₯ − 𝑔(π‘₯)
ο‚›Solve
𝑓 π‘₯ = 7π‘₯
ο‚›3. 𝑓 π‘₯ ∗ 𝑔(π‘₯)
ο‚›4.
𝑓 π‘₯
𝑔(π‘₯)
and 𝑔 π‘₯ = −5π‘₯
and 𝑔 π‘₯ = 2π‘₯
3
4
2
3
ο‚›Solve
WE DO (Basic
operations)
2
𝑓 π‘₯ = 2π‘₯ − 7π‘₯ + 13
𝑔 π‘₯ = π‘₯2 − 6
ο‚›1. 𝑓 π‘₯ + 𝑔(π‘₯)
ο‚›2. g π‘₯ − 𝑓(π‘₯)
ο‚›Solve
𝑓 π‘₯ = −3π‘₯
ο‚›3. 𝑓 π‘₯ ∗ 𝑔(π‘₯)
ο‚›4.
𝑓 π‘₯
𝑔(π‘₯)
1
4
and
and 𝑔 π‘₯ = 9π‘₯
1
2
YOU DO 2(Basic operations)
ο‚›Solve
π‘₯2 + 7
𝑓 π‘₯ = π‘₯ + 12π‘₯
and 𝑔 π‘₯ =
ο‚›1.
𝑓 π‘₯ + 𝑓(π‘₯)
ο‚›2. g π‘₯ − 𝑔(π‘₯)
ο‚›Solve
𝑓 π‘₯ = 5π‘₯
ο‚›3. 𝑓 π‘₯ ∗ 𝑓(π‘₯)
ο‚›4.
𝑔 π‘₯
𝑓(π‘₯)
4
5
and 𝑔 π‘₯ = 10π‘₯
1
3
Review
ο‚›Today
you learned
how to combine
more than one
equation
HOMEWORK
ο‚›Worksheet
ο‚›7.3B
(1 – 8)
ο‚›7 & 8 – do
division as well
Warm Up
ο‚›Solve
𝑓 π‘₯ = 2π‘₯ 2 + 2 and 𝑔 π‘₯ = π‘₯ 2 − 7π‘₯
ο‚›1. 𝑓 π‘₯ + 𝑓(π‘₯)
ο‚›2. g π‘₯ − 𝑓(π‘₯)
ο‚›Solve
𝑓 π‘₯ = −6π‘₯
ο‚›3. 𝑓 π‘₯ ∗ 𝑓(π‘₯)
ο‚›4.
𝑔 π‘₯
𝑓(π‘₯)
3
5
and 𝑔 π‘₯ = 24π‘₯
1
3
Algebra 3
Chapter 7: Powers,
Roots, and Radicals
Lesson 3: Power
Functions and
Function Operations
TODAY
ο‚›Today
we will review long
and synthetic division
(combining 2 equations)
Question
ο‚› When
can I use synthetic division?
Directions (Synthetic)
ο‚› THIS
IS EXACTLY LIKE SYNTHETIC SUBSTITUTION
ο‚› Write the problem in standard form including
the missing terms
ο‚› Only Write down the coefficients inside
ο‚› For the outside
ο‚› Remember to take the opposite of the
number
ο‚› ANSWER
ο‚› YOU
start with 1 power less than the original
Directions (Long Division)
ο‚› THIS
IS EXACTLY LIKE LONG DIVISION WITHOUT
A CALCULATOR
ο‚› Write the problem in standard form including
the missing terms
ο‚› Look at the first term in the divisor
ο‚› Find how many times that goes into the first
term of the polynomial
ο‚› Multiply that answer times the WHOLE divisor
ο‚› Subtract that from the polynomial
ο‚› Keep going until you can’t do anymore
ο‚› Remainder is then written over the divisor
STARTING POINT
ο‚› Lets
take a look at a basic division
problem without a calculator
2136
ο‚›
35
I DO (Division)
ο‚› Divide
ο‚› 1.
𝑓
ο‚› 2. 𝑓
ο‚› 3. 𝑓
ο‚› 4. 𝑓
π‘₯
π‘₯
π‘₯
π‘₯
the functions
= −π‘₯ 2 + 2π‘₯ + 2
= 2π‘₯
=π‘₯−2
=π‘₯+1
𝑓(π‘₯)
𝑔(π‘₯)
𝑔
𝑔
𝑔
𝑔
π‘₯
π‘₯
π‘₯
π‘₯
=π‘₯+3
=π‘₯+5
= π‘₯2 + π‘₯ − 4
= 3π‘₯ − 2
WE DO (Division)
ο‚› Divide
ο‚› 1.
the functions
𝑓(π‘₯)
𝑔(π‘₯)
𝑓 π‘₯ = π‘₯2 + 1
𝑔 π‘₯
ο‚› 2. 𝑓 π‘₯ = 2π‘₯ 3 − 3π‘₯ + 4
𝑔 π‘₯
ο‚› 3. 𝑓 π‘₯ = 2π‘₯ 4 + 3π‘₯ 3 + 5π‘₯ − 1
𝑔 π‘₯
ο‚› 4. 𝑓 π‘₯ = π‘₯ 3 − 3π‘₯ 2 + 2π‘₯ − 6
𝑔 π‘₯
=π‘₯−2
=π‘₯−1
= π‘₯ 2 − 2π‘₯ + 2
= π‘₯ 2 + 3π‘₯ − 1
YOU DO (Division)
ο‚› Divide
ο‚› 1.
the functions
𝑓(π‘₯)
𝑔(π‘₯)
𝑓 π‘₯ = −π‘₯ 2 + 2π‘₯ + 2
𝑔 π‘₯
ο‚› 2. 𝑓 π‘₯ = 4π‘₯ 3 − 2π‘₯ 2 + 1
𝑔 π‘₯
ο‚› 3. 𝑓 π‘₯ = 4π‘₯ 3 − 2π‘₯ 2 + 6π‘₯ − 1
𝑔 π‘₯
ο‚› 4. 𝑓 π‘₯ = 2π‘₯ 4 + 3π‘₯ − 1
𝑔 π‘₯
=π‘₯+3
=π‘₯+2
= 2π‘₯ + 3
= π‘₯ 2 + 2π‘₯ + 1
Review
ο‚› Today
you learned………
HOMEWORK
ο‚›Worksheet
ο‚›7.3B
(9-12)
Warm Up
ο‚›Solve
3
ο‚›1. 7(π‘₯ − 2)
ο‚›2.
π‘₯ + 3 + (π‘₯ 2 − 1)
2
ο‚›3.
π‘₯ + 3 − (π‘₯ − 1)
ο‚›4.
π‘₯+3 π‘₯−2
2
ο‚›5.
(π‘₯ − 3)
Algebra 3
Chapter 7: Powers,
Roots, and Radicals
Lesson 3: Power
Functions and
Function Operations
TODAY
ο‚›Today
we will learn how
to find a composite of 2
functions.
Directions (Compositions)
ο‚› Work
inside out
ο‚› Write
ο‚› This
ο‚› Write
down the inside function
is the X of the outside function
down the outside function (while using
what you wrote as x)
ο‚› Simplify
I DO (Composition)
ο‚› Find
the composite of the given functions
𝑓 π‘₯ = 10π‘₯
𝑔 π‘₯ =π‘₯+4
ο‚› 1.
ο‚› 2.
𝑓 𝑔 π‘₯
𝑔(𝑓 π‘₯ )
ο‚› 3. 𝑓(𝑓 π‘₯ )
ο‚› 4. 𝑔(𝑔 π‘₯ )
WE DO (Composition)
ο‚› Find
the composite of the given functions
𝑓 π‘₯ = 3π‘₯ 2 𝑔 π‘₯ = 2π‘₯ − 1
ο‚› 1.
ο‚› 2.
𝑓 𝑔 π‘₯
𝑔(𝑓 π‘₯ )
ο‚› 3. 𝑓(𝑓 π‘₯ )
ο‚› 4. 𝑔(𝑔 π‘₯ )
YOU DO (Composition)
ο‚› Find
the composite of the given functions
𝑓 π‘₯ = 2π‘₯ 2 + 1 𝑔 π‘₯ = 3π‘₯ + 4
ο‚› 1.
ο‚› 2.
𝑓 𝑔 π‘₯
𝑔(𝑓 π‘₯ )
ο‚› 3. 𝑓(𝑓 π‘₯ )
ο‚› 4. 𝑔(𝑔 π‘₯ )
Review
ο‚› Today
you learned………
HOMEWORK
ο‚›Worksheet
ο‚›7.3B
(13-16)
Warm Up
ο‚›Find the composite of the
given functions
2
𝑓 π‘₯ = 2π‘₯ − 4
𝑔 π‘₯ = 3π‘₯ − 2
ο‚›1.
𝑓 𝑔 π‘₯
ο‚›2.
𝑔(𝑓 π‘₯ )
Algebra 3
Chapter 7: Powers,
Roots, and Radicals
Lesson 3: Power
Functions and
Function Operations
TODAY
ο‚›Today
we will learn how
to find a composite of 2
functions with negative
and fraction exponents.
Directions (Compositions)
ο‚› Work
inside out
ο‚› Write
ο‚› This
ο‚› Write
down the inside function
is the X of the outside function
down the outside function (while using
what you wrote as x)
ο‚› Simplify
I DO (Composition)
ο‚› Find
the composite of the given functions
𝑓 π‘₯ = 3π‘₯
ο‚› 1.
ο‚› 2.
𝑓 𝑔 π‘₯
𝑔(𝑓 π‘₯ )
ο‚› 3. 𝑓(𝑓 π‘₯ )
ο‚› 4. 𝑔(𝑔 π‘₯ )
1
3
2
3
𝑔 π‘₯ =π‘₯ +1
WE DO (Composition)
ο‚› Find
the composite of the given functions
𝑓 π‘₯ = 3π‘₯ −1
𝑔 π‘₯ = 2π‘₯ − 1
ο‚› 1.
ο‚› 2.
𝑓 𝑔 π‘₯
𝑔(𝑓 π‘₯ )
ο‚› 3. 𝑓(𝑓 π‘₯ )
ο‚› 4. 𝑔(𝑔 π‘₯ )
YOU DO (Composition)
ο‚› Find
the composite of the given functions
1
4
𝑓 π‘₯ = 2π‘₯ − 1
ο‚› 1.
ο‚› 2.
𝑓 𝑔 π‘₯
𝑔(𝑓 π‘₯ )
ο‚› 3. 𝑓(𝑓 π‘₯ )
ο‚› 4. 𝑔(𝑔 π‘₯ )
2
3
𝑔 π‘₯ =π‘₯ +2
Review
ο‚› Today
you learned………
HOMEWORK
ο‚›Worksheet
ο‚›7.3B
(13-16)
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