Algebra 2 8.8 Practice A 5.17.12 alg_2_8.8_practice_a

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Name _______________________________________ Date __________________ Class __________________
LESSON
Practice A Algebra 2 May 17, 2012
8-8
Solving Radical Equations and Inequalities
Rewrite each equation to isolate the radical.
1.
x 60
2. 8  3 x  x  0
________________________
2 x  1  17  3 x
3.
________________________
________________________
Identify to what power each equation must be raised in order to solve.
Then solve.
4.
x 4
5.
________________________
4
3x  12
6.
________________________
3
x 1 4
________________________
Solve the equation. Then identify any extraneous solutions.
7. 2 x  2  4
8.
________________________________________
x 3 x 3
________________________________________
Solve each equation or inequality.
9.
1
10.  4x  2  6
x 2 5
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11.
 x  1
1
3
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12. 2 x  3  10
3
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13.
2x  6  0
________________________________________
14.
________________________________________
3x  1  8
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Solve.
15. Ainsley and Ben each solve the inequality
x  3  5  10 . Ainsley’s solution
is x  22. Ben’s solution is 3  x  22. Why are their solutions different?
Which is correct?
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Original content Copyright © by Holt McDougal. Additions and changes to the original content are the responsibility of the instructor.
8-59
Holt Algebra 2
Reading Strategies
2.k  3: Shifts f(x) 3 units up
1. a. 1
b. 1
c. 0
d. 3
e. Translated 3 units down
2. a. 1
b. 1
c. 1
d. 2
3. Reflects f(x) across the x-axis
e. Translated 2 units up, 1 unit right, and
reflected across the x-axis
3. a. 1
b. 1
c. 4
d. 5
e. Translated 5 units down, 4 units left,
and reflected across the y-axis
4. a. 1
b. 1
c. 3
Challenge
1. y  3  x  1  4
d. 2
2. y  4 3 x  2  3
e. Translated 2 units up, 3 units left, and
reflected across the x-axis
LESSON 8-8
3. y  0.5  x  5  2 4. y  5 3  x  1  4
Problem Solving
1. a. d (a)  3.56
Practice A
5
a
9
b.
1.
x 6
2.
3.
2 x  1  3x  17
4. 2; x  16
5. 4; x 
69
2
3x  x  8
6. 3; x  63
7. x  2; no extraneous solutions
8. x  1, x  6; x  1 is an extraneous
solution.
c. 36 km; 27 km
2. B
3. C
4. D
5. A
9. x  23
10. x  9
11. x  26
12. x  28
13. 0  x  18
14. x  21
15. Ben’s solution is correct. Ainsley forgot
that the radicand cannot be negative.
6. D
Original content Copyright © by Holt McDougal. Additions and changes to the original content are the responsibility of the instructor.
A12
Holt Algebra 2
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