6-7 Solving Radical Equations and Inequalities
Solve each equation.
4. 1. SOLUTION: SOLUTION: 5. 2. SOLUTION: SOLUTION: 6. SOLUTION: 3. SOLUTION: 7. 4. SOLUTION: SOLUTION: eSolutions Manual - Powered by Cognero
Page 1
6-7 Solving Radical Equations and Inequalities
7. 10. SOLUTION: SOLUTION: 8. Check:
SOLUTION: Therefore, the equation has no solution.
9. 11. SOLUTION: SOLUTION: 10. SOLUTION: 12. SOLUTION: eSolutions Manual - Powered by Cognero
Page 2
6-7 Solving Radical Equations and Inequalities
13. CCSS REASONING The time T in seconds that it
takes a pendulum to make a complete swing back
12. and forth is given by the formula
SOLUTION: , where
L is the length of the pendulum in feet and g is the
acceleration due to gravity, 32 feet per second
squared.
13. CCSS REASONING The time T in seconds that it
takes a pendulum to make a complete swing back
and forth is given by the formula
, where
L is the length of the pendulum in feet and g is the
acceleration due to gravity, 32 feet per second
squared.
a. In Tokyo, Japan, a huge pendulum in the Shinjuku
building measures 73 feet 9.75 inches. How long
does it take for the pendulum to make a complete
swing?
a. In Tokyo, Japan, a huge pendulum in the Shinjuku
building measures 73 feet 9.75 inches. How long
does it take for the pendulum to make a complete
swing?
b. A clockmaker wants to build a pendulum that
takes 20 seconds to swing back and forth. How long
should the pendulum be?
SOLUTION: a. Convert 73 feet 9.75 inches to feet.
73 feet 9.75 inches =
ft.
Substitute 73.8125 and 32 for L and g then simplify.
b. A clockmaker wants to build a pendulum that
takes 20 seconds to swing back and forth. How long
should the pendulum be?
Therefore, the pendulum takes about 9.5 seconds to
complete a swing.
SOLUTION: a. Convert 73 feet 9.75 inches to feet.
73 feet 9.75 inches =
b. Substitute 20 for T and 32 for g.
ft.
Substitute 73.8125 and 32 for L and g then simplify.
Therefore, the pendulum takes about 9.5 seconds to
complete a swing.
b. Substitute 20 for T and 32 for g.
The pendulum should be about 324 ft long.
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14. MULTIPLE CHOICE Solve
Page 3
.
The pendulum
should
be about
324Inequalities
ft long.
6-7 Solving
Radical
Equations
and
Option B is the correct answer.
14. MULTIPLE CHOICE Solve
Solve each inequality.
.
15. Ay =1
C y = 11
SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
B y =5
D y = 15
SOLUTION: Solve
.
Option B is the correct answer.
Solve each inequality.
The solution region is
15. .
SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
16. SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
Solve
.
Solve
.
eSolutions Manual - Powered by Cognero
Page 4
The solution region is
.
6-7 Solving
Radical Equations and Inequalities
The solution region is
.
17. 16. SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
Solve
.
.
Solve
The solution region is
.
17. The solution region is
.
SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
18. SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
Solve
.
Solve
.
The solution region is
eSolutions Manual - Powered by Cognero
18. .
The solution region is
.
Page 5
The solution
region
is
. Inequalities
6-7 Solving
Radical
Equations
and
The solution region is
.
18. 19. SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
Solve
.
Solve
.
The solution region is
.
The solution region is x > 1.
19. 20. SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
Solve
.
Solve
eSolutions Manual - Powered by Cognero
The solution region is x > 1.
The solution region is
.
.
Page 6
The solution
region
is x > 1. and Inequalities
6-7 Solving
Radical
Equations
The solution region is
.
20. 21. SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
Solve
.
.
Solve
The solution region is
.
The solution region is
.
21. 22. SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
Solve
.
Solve
.
eSolutions Manual - Powered by Cognero
The solution region is
.
Page 7
The solution region is
.
The solution region is
The solution
region
is
. Inequalities
6-7 Solving
Radical
Equations
and
.
Solve each equation. Confirm by using a
graphing calculator.
22. SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
23. SOLUTION: Solve
.
CHECK:
The solution region is
[-2, 28] scl: 2 by [-2, 8] scl: 1
.
Solve each equation. Confirm by using a
graphing calculator.
24. SOLUTION: 23. SOLUTION: CHECK:
CHECK:
[-2, 18] scl: 2 by [-2, 18] scl:2
eSolutions Manual - Powered by Cognero
[-2, 28] scl: 2 by [-2, 8] scl: 1
25. Page 8
[-2, 28] scl: 2 by [-2, 8] scl: 1
[-2, 18] scl: 2 by [-2, 18] scl:2
6-7 Solving
Radical Equations and Inequalities
24. 25. SOLUTION: SOLUTION: CHECK:
CHECK:
[-2, 18] scl: 2 by [-2, 18] scl:2
25. [-10, 10] scl:1 by [-10, 10] scl:1
SOLUTION: 26. SOLUTION: CHECK:
CHECK:
eSolutions Manual - Powered by Cognero
[-10, 10] scl:1 by [-10, 10] scl:1
Page 9
[-10, 10] scl:1
by [-10,
10] scl:1 and Inequalities
6-7 Solving
Radical
Equations
[-2, 18] scl: 2 by [-2, 8] scl: 1
26. 27. SOLUTION: SOLUTION: Check:
CHECK:
[-2, 18] scl: 2 by [-2, 8] scl: 1
[-2, 18] scl: 2 by [-10, 10] scl:1
27. There is no real solution for the equation.
SOLUTION: 28. SOLUTION: Check:
eSolutions Manual - Powered by Cognero
Check:
Page 10
[-2, 18] scl: 2 by [-10, 10] scl:1
[-2, 18] scl: 2 by [-10, 10] scl:1
There is Radical
no real solution
for the
equation.
6-7 Solving
Equations
and
Inequalities
There is no real solution for the equation.
28. 29. SOLUTION: SOLUTION: CHECK:
Check:
[-1, 4] scl: 1 by [-1, 14] scl: 1
30. SOLUTION: [-2, 18] scl: 2 by [-10, 10] scl:1
There is no real solution for the equation.
29. CHECK:
SOLUTION: [-5, 45] scl: 5 by [-5, 45] scl: 5
eSolutions
Manual - Powered by Cognero
CHECK:
Page 11
31. [-1, 4] scl: 1 by [-1, 4] scl: 1
6-7 Solving
Radical
[-5, 45] scl:
5 by [-5,Equations
45] scl: 5 and Inequalities
33. 31. SOLUTION: SOLUTION: CHECK:
CHECK:
[-2, 18] scl: 2 by [-2, 18] scl:2
32. SOLUTION: [-1, 9] scl: 1 by [-5, 5] scl: 1
34. SOLUTION: CHECK:
[-1, 4] scl: 1 by [-1, 4] scl: 1
33. SOLUTION: eSolutions Manual - Powered by Cognero
CHECK:
Page 12
[-1, 9] scl:Radical
1 by [-5, 5]
scl: 1
6-7 Solving
Equations
and Inequalities
[-1, 9] scl: 1 by [-5, 5] scl: 1
35. CCSS SENSE-MAKING Isabel accidentally
dropped her keys from the top of a Ferris wheel. The
34. formula
SOLUTION: describes the time t in seconds
at which the keys are h meters above the ground and
Isabel is d meters above the ground. If Isabel was 65
meters high when she dropped the keys, how many
meters above the ground will the keys be after 2
seconds?
SOLUTION: Substitute 2 for t and 65 d.
CHECK:
The keys will be 1 meter above the ground after 2
seconds.
Solve each equation.
[-1, 9] scl: 1 by [-5, 5] scl: 1
36. 35. CCSS SENSE-MAKING Isabel accidentally
dropped her keys from the top of a Ferris wheel. The
formula
SOLUTION: describes the time t in seconds
at which the keys are h meters above the ground and
Isabel is d meters above the ground. If Isabel was 65
meters high when she dropped the keys, how many
meters above the ground will the keys be after 2
seconds?
SOLUTION: Substitute 2 for t and 65 d.
37. eSolutions Manual - Powered by Cognero
Page 13
SOLUTION: 6-7 Solving
Radical Equations and Inequalities
37. 39. SOLUTION: SOLUTION: 40. 38. SOLUTION: SOLUTION: 41. 39. SOLUTION: SOLUTION: eSolutions Manual - Powered by Cognero
42. Page 14
40. 6-7 Solving Radical Equations and Inequalities
45. 42. SOLUTION: SOLUTION: 46. 43. SOLUTION: SOLUTION: 47. 44. SOLUTION: SOLUTION: 48. MULTIPLE CHOICE Solve
.
45. eSolutions
Manual - Powered by Cognero
SOLUTION: A 23
B 53
C 123
Page 15
Option D is the correct answer.
6-7 Solving Radical Equations and Inequalities
48. MULTIPLE CHOICE Solve
.
49. MULTIPLE CHOICE Solve
.
A 23
F 41
B 53
G 28
C 123
H 13
D 623
J1
SOLUTION: SOLUTION: Option D is the correct answer.
49. MULTIPLE CHOICE Solve
Option F is the correct answer.
.
F 41
Solve each inequality.
G 28
H 13
J1
SOLUTION: 50. SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
Solve
.
Option F is the correct answer.
eSolutions Manual - Powered by Cognero
Solve each inequality.
Page 16
The solution region is
Option FRadical
is the correct
answer.
6-7 Solving
Equations
and Inequalities
Solve each inequality.
.
51. 50. SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
Solve
.
Solve
.
The solution region is
.
52. The solution region is
.
SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
51. SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
Solve
.
Solve
.
eSolutions Manual - Powered by Cognero
Page 17
The solution region is
.
Since the value of radical is nonnegative, the
inequality has no real solution.
The solution
region
is
.and Inequalities
6-7 Solving
Radical
Equations
52. 54. SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
and
.
Solve
.
.
Solve
The solution region is
The solution region is
.
.
55. 53. SOLUTION: SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
and
.
Since the value of radical is nonnegative, the
inequality has no real solution.
Solve
.
54. SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
and
.
eSolutions Manual - Powered by Cognero
Page 18
The solution region is
The solution
region
is
. and Inequalities
6-7 Solving
Radical
Equations
.
55. 56. SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
and
.
SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
.
Solve
Solve
.
The solution region is
.
The solution region is
.
57. SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
56. SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
Solve
Solve
.
.
eSolutions Manual - Powered by Cognero
The solution region is
Page 19
.
The solution region is
The solution
region
is
.
6-7 Solving
Radical
Equations
and Inequalities
.
57. 58. SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
Solve
Solve
.
.
The solution region is
.
The solution region is
.
59. SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
58. SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
Solve
Solve
.
.
eSolutions Manual - Powered by Cognero
The solution region is
The solution region is
.
.
Page 20
The solution
region
is
. Inequalities
6-7 Solving
Radical
Equations
and
The solution region is
.
59. 60. SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
and .
Solve
Solve
.
The solution region is
.
60. SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
and The solution region is
.
61. Solve
.
SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
and Solve
.
eSolutions Manual - Powered by Cognero
Page 21
The solution
region
is
. Inequalities
6-7 Solving
Radical
Equations
and
.
61. 62. PENDULUMS The formula
SOLUTION: Since the radicand of a square root must be greater
than or equal to zero, first solve
.
and represents
the swing of a pendulum, where s is the time in
seconds to swing back and forth, and is the length of the pendulum in feet. Find the length of a
pendulum that makes one swing in 1.5 seconds.
SOLUTION: Substitute 1.5 for s and solve for l.
Solve
The solution region is
.
The solution region is
.
The length of the pendulum is about 1.82 ft.
62. PENDULUMS The formula
represents
the swing of a pendulum, where s is the time in
seconds to swing back and forth, and is the length of the pendulum in feet. Find the length of a
pendulum that makes one swing in 1.5 seconds.
63. FISH The relationship between the length and mass
of certain fish can be approximated by the equation
, where L is the length in meters and M
is the mass in kilograms. Solve this equation for M .
SOLUTION: SOLUTION: Substitute 1.5 for s and solve for l.
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64. HANG TIME Refer to the information at the
beginning of the lesson regarding hang time.
Describe how the height of a jump is related to the
amount of time in the air. Write a step-by-step
explanation of how to determine the height of Page 22
Jordan’s 0.98-second jump.
6-7 Solving Radical Equations and Inequalities
64. HANG TIME Refer to the information at the
beginning of the lesson regarding hang time.
Describe how the height of a jump is related to the
amount of time in the air. Write a step-by-step
explanation of how to determine the height of
Jordan’s 0.98-second jump.
SOLUTION: If the height of a person’s jump and the amount of
time he or she is in the air are related by an equation
involving radicals, then the hang time associated with
a given height can be found by solving a radical
equation.
The radius of the region is about 282 ft.
66. WEIGHTLIFTING The formula
can be used to estimate the
maximum total mass that a weightlifter of mass B
kilograms can lift using the snatch and the clean and
jerk. According to the formula, how much does a
person weigh who can lift at most 470 kilograms?
SOLUTION: Substitute 470 for M and solve for B.
65. CONCERTS The organizers of a concert are
preparing for the arrival of 50,000 people in the open
field where the concert will take place. Each person
is allotted 5 square feet of space, so the organizers
rope off a circular area of 250,000 square feet. Using
the formula
, where A represents the area of
the circular region and r represents the radius of the
region, find the radius of this region.
SOLUTION: Substitute 250,000 for A and solve for r.
The person weigh 163 kg can lift at most 470
kilograms.
67. CCSS ARGUMENTS Which equation does not
have a solution?
The radius of the region is about 282 ft.
66. WEIGHTLIFTING The formula
can be used to estimate the
maximum total mass that a weightlifter of mass B
kilograms can lift using the snatch and the clean and
jerk. According to the formula, how much does a
person weigh who can lift at most 470 kilograms?
SOLUTION: SOLUTION: Substitute 470 for M and solve for B.
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Since the value of the radical is negative, it doesPage
not 23
have real solution.
Yes; since
, the left side of the equation is
nonnegative. Therefore, the left side of the equation
cannot equal –4. Thus the equation has no solution.
The person weigh 163 kg can lift at most 470
kilograms.
6-7 Solving
Radical Equations and Inequalities
67. CCSS ARGUMENTS Which equation does not
have a solution?
69. REASONING Determine whether
is
sometimes, always, or never true when x is a real
number. Explain your reasoning.
SOLUTION: SOLUTION: Since the value of the radical is negative, it does not
have real solution.
But this is only true when x = 0. And in that case, we
have division by zero in the original equation.
So the equation is never true.
68. CHALLENGE Lola is working to
solve
. She said that she could tell
there was no real solution without even working the
problem. Is Lola correct? Explain your reasoning.
SOLUTION: Yes; since
, the left side of the equation is
nonnegative. Therefore, the left side of the equation
cannot equal –4. Thus the equation has no solution.
70. OPEN ENDED Select a whole number. Now work
backward to write two radical equations that have
that whole number as solutions. Write one square
root equation and one cube root equation. You may
need to experiment until you find a whole number
you can easily use.
SOLUTION: Sample answer using
69. REASONING Determine whether
is
sometimes, always, or never true when x is a real
number. Explain your reasoning.
SOLUTION: eSolutions Manual - Powered by Cognero
Page 24
But this is only true when x = 0. And in that case, we
have division by zero in the original equation.
So the equation
never true.and Inequalities
6-7 Solving
RadicalisEquations
They are the same number. For example,
.
70. OPEN ENDED Select a whole number. Now work
backward to write two radical equations that have
that whole number as solutions. Write one square
root equation and one cube root equation. You may
need to experiment until you find a whole number
you can easily use.
72. OPEN ENDED Write an equation that can be
solved by raising each side of the equation to the
given power.
a.
power
SOLUTION: Sample answer using
b.
power
c.
power
SOLUTION: a. Sample answer:
b. Sample answer:
c. Sample answer:
73. CHALLENGE Solve
y
= b if and only if x = y.)
for x. (Hint: b
x
SOLUTION: 71. WRITING IN MATH Explain the relationship
between the index of the root of a variable in an
equation and the power to which you raise each side
of the equation to solve the equation.
Equate the powers and solve for x.
SOLUTION: They are the same number. For example,
.
REASONING Determine whether the following
statements are sometimes, always, or never true
for
. Explain your reasoning.
72. OPEN ENDED Write an equation that can be
solved by raising each side of the equation to the
given power.
eSolutions Manual - Powered by Cognero
a.
power
74. If n is odd, there will be extraneous solutions.
SOLUTION: never;
Page 25
Sample answer: The radicand can be negative.
Equate the powers and solve for x.
6-7 Solving Radical Equations and Inequalities
REASONING Determine whether the following
statements are sometimes, always, or never true
for
SOLUTION: sometimes;
Sample answer: when the radicand is negative, then
there will be extraneous roots.
. Explain your reasoning.
74. If n is odd, there will be extraneous solutions.
76. What is an equivalent form of
A
SOLUTION: never;
Sample answer: The radicand can be negative.
B
C
75. If n is even, there will be extraneous solutions.
?
D
SOLUTION: sometimes;
Sample answer: when the radicand is negative, then
there will be extraneous roots.
SOLUTION: 76. What is an equivalent form of
?
A
B
C
D
SOLUTION: Option A is the correct answer.
77. Which set of points describes a function?
F {(3, 0), (–2, 5), (2, –1), (2, 9)}
G {(–3, 5), (–2, 3), (–1, 5), (0, 7)}
H {(2, 5), (2, 4), (2, 3), (2, 2)}
J {(3, 1), (–3, 2), (3, 3), (–3, 4)}
SOLUTION: In option F and H, the element 2 has more than one
image.
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eSolutions
In option J, the elements 3 and –3 have more than
one image. In option G, every element has a unique
image. So, it describes a function.
Page 26
Option A is the correct answer.
Therefore, option G is the correct answer.
Since the given triangle is an isosceles triangle, the
measure of another leg should be 20 inches.
Therefore, the measure of the base of the triangle is
(56 – 20 − 20) or 16 in.
Option A
is the correct
answer.
6-7 Solving
Radical
Equations
and Inequalities
77. Which set of points describes a function?
79. SAT/ACT If
, what is the value of x?
F {(3, 0), (–2, 5), (2, –1), (2, 9)}
A4
G {(–3, 5), (–2, 3), (–1, 5), (0, 7)}
B 10
H {(2, 5), (2, 4), (2, 3), (2, 2)}
C 11
J {(3, 1), (–3, 2), (3, 3), (–3, 4)}
D 12
E 20
SOLUTION: In option F and H, the element 2 has more than one
image.
SOLUTION: In option J, the elements 3 and –3 have more than
one image. In option G, every element has a unique
image. So, it describes a function.
Therefore, option G is the correct answer.
78. SHORT RESPONSE The perimeter of an isosceles
triangle is 56 inches. If one leg is 20 inches long,
what is the measure of the base of the triangle?
Option A is the correct answer.
Evaluate.
SOLUTION: Since the given triangle is an isosceles triangle, the
measure of another leg should be 20 inches.
Therefore, the measure of the base of the triangle is
(56 – 20 − 20) or 16 in.
80. SOLUTION: 79. SAT/ACT If
, what is the value of x?
A4
B 10
C 11
D 12
E 20
SOLUTION: 81. SOLUTION: eSolutions Manual - Powered by Cognero
Page 27
6-7 Solving
Radical Equations and Inequalities
83. GEOMETRY The measures of the legs of a right
81. 2 2
triangle can be represented by the expressions 4x y
2 2
and 8x y . Use the Pythagorean Theorem to find a
simplified expression for the measure of the
hypotenuse.
SOLUTION: SOLUTION: Substitute
82. and
for a and b and simplify.
SOLUTION: Therefore, the measure of the hypotenuse is
.
Find the inverse of each function.
84. 83. GEOMETRY The measures of the legs of a right
SOLUTION: 2 2
triangle can be represented by the expressions 4x y
2 2
and 8x y . Use the Pythagorean Theorem to find a
simplified expression for the measure of the
hypotenuse.
Interchange x and y , then solve for y
SOLUTION: Substitute
and
for a and b and simplify.
85. SOLUTION: Therefore, the measure of the hypotenuse is
.
Interchange x and y, then solve for y
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Page 28
6-7 Solving
Radical Equations and Inequalities
For each graph,
85. a. describe the end behavior,
SOLUTION: b. determine whether it represents an odddegree or an even-degree polynomial function,
and
Interchange x and y, then solve for y
c. state the number of real zeros.
86. 88. SOLUTION: SOLUTION: a. The function tends to +∞ as x tends to –∞.
The function tends to –∞ as x tends to +∞.
Interchange x and y, then solve for y
b. Since the end behaviors are in opposite directions,
the graph represents an odd-degree polynomial.
c. Since the graph intersects the x-axis at three
points, the number of real zeros is 3.
87. SOLUTION: Interchange x and y and solve for y.
89. SOLUTION: a. The function tends to +∞ as x tends to –∞ and +∞.
b. Since the end behaviors are in the same direction,
the graph represents an even-degree polynomial.
For each graph,
a. describe the end behavior,
c. Since the graph does not intersect the x-axis, the
Page 29
number of real zeros is 0.
eSolutions Manual - Powered by Cognero
b. determine whether it represents an odd-
the graph represents an odd-degree polynomial.
c. Since the graph intersects the x-axis at three
points, the number of real zeros is 3.
6-7 Solving
Radical Equations and Inequalities
c. Since the graph intersects the x-axis at one point,
the number of real zeros is 1.
Solve each equation. Write in simplest form.
91. SOLUTION: 89. SOLUTION: a. The function tends to +∞ as x tends to –∞ and +∞.
b. Since the end behaviors are in the same direction,
the graph represents an even-degree polynomial.
92. c. Since the graph does not intersect the x-axis, the
number of real zeros is 0.
SOLUTION: 90. 93. SOLUTION: a. The function tends to +∞ as x tends to +∞.
The function tends to –∞ as x tends to –∞.
SOLUTION: b. Since the end behaviors are in opposite directions,
the graph represents an odd-degree polynomial.
c. Since the graph intersects the x-axis at one point,
the number of real zeros is 1.
Solve each equation. Write in simplest form.
94. 91. SOLUTION: SOLUTION: eSolutions Manual - Powered by Cognero
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6-7 Solving Radical Equations and Inequalities
97. 94. SOLUTION: SOLUTION: 95. SOLUTION: 98. SOLUTION: 96. SOLUTION: 97. SOLUTION: eSolutions Manual - Powered by Cognero
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