Clear and Concise

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CHEG 200 Project Memo

In your team’s project memos, you are to provide a purpose statement, solution method, major results, and major conclusions for each problem. Below are two examples of what those should look like. In each example, the “ red version ” contains too much verbiage.

The “black version” is clear and concise, and it was developed using the guidelines presented on Pages D-5 to D-8 in Appendix D of the pink Provisional Engineer

Handbook, particularly those for expletives and vague pronouns.

Example 1

Problem Statement:

The purpose of Problem P0.A1 was to calculate the reactor heating or cooling requirement for the production of ethanol from ethylene and water with a side reaction that produces diethyl ether.

In Problem P0.A1, the reactor heating or cooling requirement was determined for the production of ethanol from ethylene and water with a side reaction that produces diethyl ether.

Solution Method:

For this problem, it was assumed that the pressure is constant at 3 atm. A basis of 1 kg-mole/hr for the feed was used. It was given that there was a 4% conversion of ethylene and the ethanol yield was 0.15. In addition the Cp value and the heat of fusion and vaporization were specified for diethyl ether. To solve this problem, a mathematical model and algorithm were created based on a mole balance and an energy balance.

The pressure was assumed constant at 3 atm, and a basis of 1 kg-mole/h for the feed was used. For a 4% molar conversion of ethylene and an ethanol yield of 0.15, a mathematical model was created based on mole and energy balances to solve this problem.

Major Results:

A numerical solution was calculated and the cooling requirement was determined to be +2.96 kJ/mole. HYSYS was used to verify this answer and the check equation was balanced when this answer was used, therefore it is a reasonable value.

As calculated by E-Z Solve, the heating requirement was 2.96 kJ/mol, and it compares favorably with a HYSYS-determined value of 2.93 kJ/mol.

Major Conclusions:

In conclusion, it was determined that a reactor needs to be heated, as opposed to being cooled, when ethanol and diethyl ether are being produced from ethylene and water.

In conclusion, the reactor needs to be heated, as opposed to being cooled, when ethanol and diethyl ether are being produced from ethylene and water.

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CHEG 200 Project Memo

Example 1 in Paragraph Form:

Verbose Version

The purpose of Problem P0.A1 was to calculate the reactor heating or cooling requirement for the production of ethanol from ethylene and water with a side reaction that produces diethyl ether. For this problem, it was assumed that the pressure is constant at 3 atm. A basis of 1 kg-mole/hr for the feed was used. It was given that there was a 4% conversion of ethylene and the ethanol yield was 0.15. In addition the Cp value and the heat of fusion and vaporization were specified for diethyl ether. To solve this problem, a mathematical model and algorithm were created based on a mole balance and an energy balance. A numerical solution was calculated and the cooling requirement was determined to be +2.96 kJ/mole. HYSYS was used to verify this answer and the check equation was balanced when this answer was used, therefore it is a reasonable value. In conclusion, it was determined that a reactor needs to be heated, as opposed to being cooled, when ethanol and diethyl ether are being produced from ethylene and water.

Clear and Concise Version

In Problem P0.A1, the reactor heating or cooling requirement was determined for the production of ethanol from ethylene and water with a side reaction that produces diethyl ether. The pressure was assumed constant at 3 atm, and a basis of 1 kg-mole/h for the feed was used. For a 4% molar conversion of ethylene and an ethanol yield of 0.15, a mathematical model was created based on mole and energy balances to solve this problem. As calculated by E-Z Solve, the heating requirement was 2.96 kJ/mol, and it compares favorably with a HYSYS-determined value of 2.93 kJ/mol. In conclusion, the reactor needs to be heated, as opposed to being cooled, when ethanol and diethyl ether are being produced from ethylene and water.

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CHEG 200 Project Memo

Example 2

Problem Statement:

The purpose of Problem P0.A2 was to calculate the adiabatic flame temperature of a furnace that is burning natural gas with air. It was given that there is 20% excess air and the Cp values for the components were specified.

In Problem P0.A2, the adiabatic flame temperature of a furnace burning natural gas with 20% excess air was determined.

Solution Method:

For this problem, it was assumed that the system is continuous, operating at steady state, adiabatic, there is complete combustion, changes in potential and kinetic energy can be neglected, there is no shaft work, and the gases are ideal. To solve this problem, a mathematical model and algorithm were created based on a mole balance and an energy balance.

Assumptions of continuous, steady state, adiabatic, complete combustion, negligible potential and kinetic energy effects, no shaft work, and ideal gas behavior were used to develop a mathematical model based on mole and energy balances.

Major Results:

A numerical solution was calculated and the temperature was determined to be

1610.00°F using the Cp values given and the temperature was determined to be

800.00°F using iterations. These values are reasonable because when they were used in the check equation it was balanced.

As calculated by E-Z Solve, an adiabatic flame temperature was determined to be

800°F, and this value compares favorably with 950°F approximated by using constant heat capacities.

Major Conclusions:

In conclusion, it was determined that if the percent excess air was decreased, the flame temperature would remain the same. If the percent methane increased, the amount of air would also be the increased and the flame temperature would remain the same. This would happen because when there is more air available, the required amount to cause combustion is still the same.

In conclusion, increasing the percent excess air decreases the flame temperature because the additional air dissipates the energy within the system.

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CHEG 200 Project Memo

Example 2 in Paragraph Form:

Verbose Version

The purpose of Problem P0.A2 was to calculate the adiabatic flame temperature of a furnace that is burning natural gas with air. It was given that there is 20% excess air and the Cp values for the components were specified. For this problem, it was assumed that the system is continuous, operating at steady state, adiabatic, there is complete combustion, changes in potential and kinetic energy can be neglected, there is no shaft work, and the gases are ideal. To solve this problem, a mathematical model and algorithm were created based on a mole balance and an energy balance. A numerical solution was calculated and the temperature was determined to be 1610.00°F using the Cp values given and the temperature was determined to be 800.00°F using iterations. These values are reasonable because when they were used in the check equation it was balanced. In conclusion, it was determined that if the percent excess air was decreased, the flame temperature would remain the same. If the percent methane increased, the amount of air would also be the increased and the flame temperature would remain the same. This would happen because when there is more air available, the required amount to cause combustion is still the same.

Clear and Concise Version

In Problem P0.A2, the adiabatic flame temperature of a furnace burning natural gas with

20% excess air was determined. Assumptions of continuous, steady state, adiabatic, complete combustion, negligible potential and kinetic energy effects, no shaft work, and ideal gas behavior were used to develop a mathematical model based on mole and energy balances. As calculated by E-Z Solve, an adiabatic flame temperature was determined to be 800°F, and this value compares favorably with 950°F approximated by using constant heat capacities. In conclusion, increasing the percent excess air decreases the flame temperature because the additional air dissipates the energy within the system.

Be aware that these examples were sectioned to show what each part looks like. Do not label each section as the problem statement, solution method, etc. See Pages D-

5 to D-8 in Appendix D of the pink Provisional Engineer Handbook to write a clear and concise project memo.

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