Physics 12 Vectors of Kinematics WS#1

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Physics 12 Vectors of Kinematics WS#1.
Name:_____Key_______
1. What is the opposite of the following directions?
A. [S 46º W]
B. [ E 60º N]
[N 46º E]
[W 60º S]
2. What is another way of expressing the following directions?
A. [N 35º E]
B. N 75º W
[E 55º N]
3. Using a scale diagram, add the following vectors to determine the resultant
displacement.
A. 3.0 m [E] and 5.0 m [N]
C. 8.0 m [S] and 4.0 m [E]
B. 15.0 m [S] and 20.0 m [W]
D. 3.5 m [E] and 6.5 m [N] and 2.0 m [S]
4. A person walks 5.8 km [N], 4.0 km [E] and finally 3.0 km [S] in 2.8 hours. Find the
person’s resultant displacement and average velocity. (Use Pythagorean Theorem
and Trigonometry)
Vectors
5.8 km [N]
4.0 km [E]
3.0 km [S]
x component
0
+ 4.0
0
sum of x = 4.0
Resultant Displacement =
y component
+ 5.8
0
– 3.0
sum of y = 2.8
= 4.9 km @ 35° N of E
5. a) Find the displacement of an airplane that flies 340 km [W[], then 120 km [S] and
then 220 km [E] in 3.00 hours. Then find the plane’s average speed and average
velocity. (Use Pythagorean Theorem and Trigonometry)
Vectors
340 km [W]
120 km [S]
220 km [E]
y component
0
– 120
0
sum of y = – 120
2
2
Resultant Displacement = (120 )  (120 )  170 km @ 45° W of S or 45° S of W
Average speed =
x component
– 340
0
+220
sum of x = – 120
340  120  220
 227 km/h
3
Average velocity =
170km
 57 km/h @ 45° W of S or 45° S of W
3h
b) What direction and distance would they have to fly in order to return where they
started?
They would have to fly 170 km @ 45° E of N or 45° N of E
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