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Feedback — Vectors in 1D: Symbolic and Arrow
Representations v2Help
You submitted this quiz on Sat 10 May 2014 11:24 PM CDT. You got a score
of 2.80 out of 4.00
Some questions provided by Matter and Interactions (3rd. Ed.), R. Chabay & B. Sherwood.
Copyright (2010, John Wiley & Sons). This material is used by permission of John Wiley & Sons, Inc.
Question 1
In the diagram, several vectors are represented by arrows in the xy-plane (with the positive x-axis
pointing right and the positive y-axis pointing up).
Which of the arrows shown represents the vector < 0, -6, 0 >?
Your Answer
Score
Ex
--
a
b
c
d
e
Total
Question Explanation
Answer : c
Question 2
Inorrect
0.00
0.00 / 1.00
Read these questions carefully. They are not the same. (Select all that apply for each.)
Which of the vectors in the diagram have magnitudes equal to the magnitude of a⃗ ?
Your Answer
Score
f⃗
Correct
0.20
d⃗
Correct
0.20
b⃗
Correct
0.20
c⃗
Correct
0.20
e⃗
Correct
0.20
Total
Question Explanation
1.00 / 1.00
Ex
Answer :
b⃗ ,d⃗ ,f⃗
Question 3
Read these questions carefully. They are not the same. (Select all that apply for each.)
Which of the vectors in the diagram are equal to a⃗
Your Answer
Score
c⃗
Correct
0.20
f⃗
Correct
0.20
b⃗
Inorrect
0.00
e⃗
Correct
0.20
Ex
d⃗
Correct
Total
0.20
0.80 / 1.00
Question Explanation
Answer : e
f⃗
Question 4
Which of the following statements about the three vectors shown are correct?
Your Answer
Score
s⃗ =t⃗ −r⃗
Correct
0.20
s⃗ +t⃗ =r⃗
Correct
0.20
r⃗ +t⃗ =s⃗
Correct
0.20
r⃗ +s⃗ =t⃗
Correct
0.20
r⃗ =t⃗ −s⃗
Correct
0.20
Total
1.00 / 1.00
Question Explanation
The difference between two vector can be found by reversing the negative vector. place the vectors
tip-to-tip. Next reverse the negative vector. Finally, starting at the tail of the first vector, draw an
arrow towards the tip of the newly reversed (second) vector.
Ex
To add two vectors geometrically, place them tip-to-tail. Then, starting at the tail of the first draw an
arrow pointing towards the tip of the second vector.
Answer :
s⃗ =t⃗ −r⃗
r⃗ =t⃗ −s⃗
r⃗ +s⃗ =t⃗
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