NH 3626
YEAR 9.
1.
GEOMETRY. DRAWING.
Calculate the value of  in each diagram, and complete the geometrical reasons for each question.

(a)
35
 = ________________
because __________ angles on a line
add up to 180.
[2]
(b)

49
61
 = ________________
because interior angles of a triangle
add up to _________ .
[2]
(c)
110

 = ________________
because __________________ angles on
parallel lines are equal.
[2]
2.
Reflect the parallelogram ABCD in the
mirror line given.
A
D
m
B
C
[2]
3.
Make two statements about the symmetry on the diagram below.
4.
Translate the triangle ABC 3 units to the right and then 2 units down.
Label the result ABC.
B
C
A
[1]
5.
Below is the plan (top) view of 7 cubes
put together in stacks.
The numbers represent the height of each stack.
2
2
1
1
1
Plan view
Draw (a) the front view
(b) the right-hand view
6.
[1]
[1]
Draw the net of the square pyramid
shown below.
[1]
7.
Draw an isometric view of the stack of cubes shown in question 5, from the
direction indicated by the arrow.
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[2]
8.
Calculate the value of  in each diagram, and give the geometrical reasons for each question.
(a)

115
(b)
120

9.
Construct the perpendicular bisector of the line segment AB.
A
10.
B
Draw the reflection of the object in the given mirror line.
11.
Find the centre of rotation to rotate one smiley face onto the other. Label it O.
[1]
12.
A tessellation of a trapezium is shown below.
Fully describe the transformations of the trapezium shown in the tessellation above.
13.
Calculate the value of  and give geometric reasons.
32
71
14.

A regular octagon has 8 equal angles
of 135.
Explain why, when four regular pentagons meet neatly, that the shape formed in the gap is a square.
Year 9 2003 Exam Schedule – Geometry
Achievement
Criteria
No.
Evidence
Solve simple
angle problems
1(a)
1(b)
1(c)
 = 145, adjacent
 = 70, 180
 = 110, corresponding
Perform and
describe simple
isometric



2
Code
Judgement
A1
A1
A1
No alternative
No alternative
No alternative
A2
No alternative
Sufficiency
Achievement:
Two of
Code A1
plus
transformations
Two of
Code A2

plus
ACHIEVEMENT
3


A2

A2
No alternative
5(a)

A3
No alternative
5(b)

A3
No alternative
A3
No alternative
two lines at symmetry
order 2 rotational symmetry
4
Produce a
drawing
representing a
threedimensional
shape
Two of
Code A3
B’
B
A
Or equivalent
C A’
C’
6

x
x
MERIT
Produce a
representation
of a simple
threedimensional
shape
Solve simple
angle problems
and give reasons

A3
M1
Allow a minor
error
Merit:
Achievement
plus
8(a)
 = 65

co-interior angles on parallel lines 
A1
M1
No alternative
Or equivalent
8(b)
 = 150
angles at a point


A1
M1
No alternative
Or equivalent

M1

A2
M2
No alternative
Code
Judgement
A2
M2
No alternative
Three of
Code M1
plus
Carry out
simple
constructions
9
Perform and
describe
isometric
transformations
10
Achievement
Criteria
No.
Perform and
describe
isometric
transformations
MERIT
7
Evidence

11
Three of
Code M2
Sufficiency
Merit:
Achievement
plus
12
Rotate 180 about middle of
right-hand side.

Reflect in base of trapezium.

A2
M2
A2
M2
Or equivalent
Three of
Code M1
Or equivalent
plus
Three of
Code M2
EXCELLENCE
Calculate angles
giving reasons
Demonstrate an
understanding
of drawing
techniques
associated with
geometry
13
 = 103
angle sum in triangle
angles on a line
AM
E
No alternative

Two octagons meeting at an edge
form an angle of 270.
This leaves 90 to form the corner of
a square because angles at a point
sum to 360.

Excellence:
Merit
Or equivalent
AM
E
plus
Two of Code E