Integration and Differentiation- Core 2 Revision

advertisement

Integration and Differentiation- Core 2 Revision

1.

Given that y = x

(a) express y as a single power of x x ,

(1) d y

(b) find , d x

(2)

(c) find

 y x

(2)

(d) evaluate

4

0 y d x .

(2)

(Total 7 marks)

2.

(a) Write x

2 x in the form x k

, where k is a fraction.

(1)

(b) The gradient of a curve at the point ( x , y ) is given by d y d x

7 x

2 x

Use integration to find the equation of the curve, given that the curve passes through the point (1,1).

(3)

(Total 4 marks)

3.

Given that y =

5 x 2 ,

(a) write down an expression for d y d x

,

(1) d y

(b) show that, when x = 2, the value of d x integer to be determined.

can be written in the form p

2, where p is an

(3)

(Total 4 marks)

South Wolds Comprehensive School 1

4.

A curve is defined for x > 0 by the equation y = x +

2

. x d y

(a) (i) Find d x

. (3)

1

(ii) Hence show that the gradient of the curve at the point P where x = 2 is

2

.

(b) Find an equation of the normal to the curve at this point P .

(1)

(4)

(Total 8 marks)

5.

Find the equation of the tangent to the curve with equation y

 x

2

2

x at the point P (1, –1). (3)

Determine the coordinates of the point where the tangent at P intersects the curve again. (5)

(Total 8 marks)

6.

A curve has equation y = 12 x 2

1

(a) Evaluate

0

2 determined. y d x , giving your answer in the form p 2 , where p is an integer to be

(3)

(b) Find the value of dy dx to be determined.

at x = 2, giving your answer in the form q 2 , where q is an integer

(3)

(Total 6 marks)

7.

A curve is defined for x > 0 by the equation y

  2 x

2

The point P lies on the curve where x = 2.

(a) Find the y -coordinate of P .

(b) Expand

  2 x 

2

.

(1)

(2)

(c) Find d y d x

(d) Hence show that the gradient of the curve at P is

2.

(3)

(2)

(e) Find the equation of the normal to the curve at P , giving your answer in the form x + by + c = 0, where b and c are integers. (4)

(Total 12 marks)

South Wolds Comprehensive School 2

8.

Given that y = x

2

– x

–2

, d y

(a) find the value of d x

at the point where x = 2,

(3)

(b) find

 y d x.

(2)

(Total 5 marks)

9.

Use the trapezium rule with four ordinates (three strips) to find an approximate value for

0

3

2 x d x giving your answer to three decimal places.

(Total 4 marks)

10.

At the point ( x , y), where x > 0, the gradient of a curve is given by d y d x

3 x

1

2

 16 x

2

7 d y

(a) (i) Verify that d x

= 0 when x = 4.

(1)

(ii) Write

16 x

2 in the form 16 x k

, where k is an integer.

(1)

(iii) Find d

2 y d x

2

.

(3)

(iv) Hence determine whether the point where x = 4 is a maximum or a minimum, giving a reason for your answer.

(2)

(b) The point P (1, 8) lies on the curve.

(i) Show that the gradient of the curve at the point P is 12.

(1)

(ii) Find an equation of the normal to the curve at P.

(3)

(c) (i) Find

( 3 x

1

2

 16 x

2

7 ) d x

(ii) Hence find the equation of the curve which passes through the point P (l, 8).

(3)

(Total 17 marks)

South Wolds Comprehensive School 3

11.

(a) Show that the equation

3

2 x 2 – 9 x + 6 = 0 has a root between 0 and 1.

(3)

(b) A curve has equation

3 y = 2 x 2 – 9 x . d y

(i) Find d x

and d

2 y d x

2

.

(5)

(ii) Calculate the coordinates of the stationary point on the curve.

(3) d

2 y

(iii) Find the value of at the stationary point and hence determine whether this d x

2 point is a maximum or a minimum.

(2)

(Total 13 marks)

12.

Use the trapezium rule with four ordinates (three strips) to find an approximation to

1

2 .

5

( 2 x 

1 ) d x giving your answer to 3 significant figures.

(Total 4 marks)

13.

(a) Find

 1 x 2 d x

(2)

(b) Hence find the value of

0

2

1 x 2 d x , giving your answer in the form p 2 , where p is a rational number.

(3)

(Total 5 marks)

South Wolds Comprehensive School 4

14.

The diagram shows the graph of

3 y = x 2 , 0

 x

4, and a straight line joining the origin to the point P which has coordinates (4, 8). y

8 P

O 4 x

(a) (i) Find

2 x 3 d x .

(2)

(ii) Hence find the value of

 4

0 x

3

2 d x.

(2)

(b) Calculate the area of the shaded region.

(2)

(Total 6 marks)

15.

The graph of y = x + 4 x

–2 has one stationary point. d y

(a) Find d x

.

(2)

(b) Find the coordinates of the stationary point.

(3)

(c) Find the value of d

2 y d x

2

at the stationary point, and hence determine whether the stationary point is a maximum or a minimum.

(4)

(Total 9 marks)

South Wolds Comprehensive School 5

1

16. It is given that y = x 3 . d y

(a) Find d x

(b) (i) Find

 y d x .

(ii) Hence evaluate

 8

0 y d x .

17.

(a) Express x

2 x in the form x p

.

(b) Given that y

 x

2 x , d y find the value of d x

at the point where x = 9.

18.

Calculate the gradient of the curve y

 x

4

3 at the point where x = 8. d y find the value of d x

19.

(a) Expand

1 x 

 2

(b) Hence find

1 x 

2 d x

South Wolds Comprehensive School

(2)

(Total 6 marks)

(1)

(2)

(2)

(3)

(Total 4 marks)

(Total 3 marks)

(1)

(3)

(Total 4 marks)

6

y

20.

0 x

1

The diagram shows a part of the curve y = x – x

3/2

(a) Show by differentiation that the curve is steeper at the point where x = 0 than it is at the point where x = 1.

(4)

(b) (i) Find

 y x

(2)

(ii) Hence find the area of the shaded region.

(2)

(Total 8 marks)

21.

A wire of length 10 cm is cut into two pieces. One of these pieces is bent to form an equilateral triangle of side x cm and the other piece is bent to form a sector of a circle of angle

radians and radius x cm as shown below. x cm

(a) Show that 5 x + x

= 10.

 x cm

(2)

(b) The sum of the areas of the triangle and sector is denoted by A cm

2

.

(i) Show that A

4

3 x

2 –

5

2 x

2 

5 x . (5)

(ii) Find d A d x

and hence find the value of x for which A has a stationary value. (3)

(iii) Find d

2

A

and hence determine whether this stationary value is a maximum or a d x

2 minimum. (2)

(Total 12 marks)

South Wolds Comprehensive School 7

y

5

22.

O

The diagram shows a sketch of the curve. y

 x ²

4 x ²

and the line y = 5.

(a) Find the coordinates of the two stationary points on the curve x

(6)

(b) (i) Show that the curve intersects the line when x

4

– 5 x

2

+ 4 = 0

(2)

(ii) By writing u = x ² in the equation x

4

– 5 x

2

+ 4 = 0 form an equation for u . Solve this equation for u and hence find the corresponding values for x .

(3)

(iii) Show that the shaded region has area

2

3

.

(6)

(Total 17 marks)

South Wolds Comprehensive School 8

Download