Topic
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
Displacement
Vectors
Kinematics
Graphs
Energy
Power
Springs
Shadows
Field of Vision
Colors
Concave mirrors
Convex mirrors
Refraction
Lenses
Optical Power
Slides Minutes
9
27
13
39
13
39
10
30
10
30
5
15
4
12
3
9
7
21
3
9
7
21
4
12
5
15
10
30
6
18
The word “component” means a “part” of a system.
When dealing with vectors, the word “components” refers
to the vector parts that “add up” or constitute a vector.
Note well that while any vector may have many component
vectors, there are two “special” vectors that that when added
together result in the given vector.
Horizontal Component The horizontal component of a given
vector is that part which acts along the horizontal axis (x-axis).
FH
FH
Vertical Component The vertical component of a given vector
is that part which acts along the vertical axis (y-axis).
FV
FV
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Together, the horizontal and vertical components make up a vector.
Vertical axis
REMEMBER
All vectors can be
represented by their
Horizontal and Vertical
components.
Vertical component
Horizontal component
Horizontal axis
Vector = Horizontal component + Vertical component
Click
“North” is “Up”
“South” is “Down”
“East” is “Right”
“West” is “Left”
N (Up)
(Left) W
E (Right)
S (Down)
Next
Vectors Slide: 2. 1
Calculate and sketch the horizontal and vertical components
for each of the given forces:
200 N [West]
N (or Up)
W (or Left)
E (or Right)
S (or Down)
200 N [West]
FH = ____________________
0
FV = ____________________
Vectors Slide: 2. 2
Calculate and sketch the horizontal and vertical components
for each of the given forces:
500 N [North]
N
W
E
S
0
FH = ____________________
500 N [North]
FV = ____________________
Vectors Slide: 2. 3
Calculate and sketch the horizontal and vertical components
for the following force:
500 N [Southeast]
REMINDER
Southeast means at 45o
between South and East.
NOTE
Round off your Fanswers
too
H = 500 N Cos 45 = 354 N
the nearest whole
number.
o
45
FV = 500 N Sin 45o = 354 N
354 N [East]
FH = ____________________
354 N [South]
FV = ____________________
Click
Vectors Slide: 2. 4
Calculate and sketch the horizontal and vertical components
for the following force:
400 N [25o from the horizontal]
FV = 400 N Sin 25o =169 N
25o
FH = 400 N Cos 25o = 363 N
363 N [East]
FH = ____________________
169 N [North]
FV = ____________________
Click
Vectors Slide: 2. 5
Calculate and sketch the horizontal and vertical components
for the following force:
290 N [S 60o E]
This means “from the South , 60o East”
FH = 290 N Sin 60o = 251 N
FV = 290 N Cos 60o = 145 N
251 N [East]
FH = ____________________
60o
145 N [South]
FV = ____________________
Click
Vectors Slide: 2. 6
Calculate and sketch the horizontal and vertical components
for the following force:
600 N [W 60o S]
This means “from the West , 60o South”
FH = 600 N Cos 60o = 300 N
60o
FV = 600 N Sin 60o = 520 N
300 N [West]
FH = ____________________
520 N [South]
FV = ____________________
Click
Vectors Slide: 2. 7
Calculate and sketch the horizontal and vertical components
for the following force:
400 N [E 35o N]
This means “from the East , 35o North”
FV = 400 N Sin 35o = 229 N
35o
FH = 400 N Cos 35o = 328 N
328 N [East]
FH = ____________________
229 N [North]
FV = ____________________
Click
Vectors Slide: 2. 8
Calculate and sketch the horizontal and vertical components
for the following force:
500 N [S 20o W]
This means “from the South , 20o West”
FH = 500 N Sin 20o = 171 N
FV = 500 N Cos 20o = 470 N
20o
171 N [West]
FH = ____________________
470 N [South]
FV = ____________________
Click
Vectors Slide: 2. 9
The diagram on the right illustrates four
forces acting on a cart that is free to
move in any direction.
Which of the following forces will
place the system in equilibrium?
A) 3.00 N at 0o from horizontal
B) 12.2 N at 180o from horizontal
C) 12.2 N at 0o from horizontal
D) 3.00 N at
180o
from horizontal
E) 22.4 N at 0o from horizontal
FE
FR
Vectors Slide: 2. 10
Vectors Slide: 2. 11
An electron is subjected to a magnetic force of 2.6 x 10-24 N acting
horizontally and an electric force of 3.0 x 10-24 N acting vertically.
Determine the equilibrant force.
Vectors Slide: 2. 12
An object is suspended by a cord which is 5.2 m long. As shown
in the diagram, the horizontal force, F, is 75 N East. Calculate
the mass of the object.
A) 18 kg
Next
Finally
First we
we
we
find
find
find
the
the
the
weight
angle
mass
B) 1.8 kg
C) 39 kg
D) 28 kg
Ao
11
E) 46.5 kg
FH = 75 N
386 w
N
11o
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Vectors Slide: 2. 13
When a weight is hung in the middle of a 20 m long wire,
the wire sags 3 m. If the tension in the wire is 270 N,
determine the weight.
A) 155 N
B) 102 N
w/2
3m
C) 78 N
10 m
w/2
73.3o
73.3o
D) 48 N
Step-3 Find the weight.
E) 26 N
With reference to the shaded triangle:
w
Step-1 DrawStep-2
all the Find
forces
acting
on the system.
the
angle.
Click
… and good luck!