ALGEBRA 1
LESSON 4.03
SLOPE-INTERCEPT FORM
Part A:
• 1. I chose Group 1.
• 2. y = negative three over 2 x + 4
The slope of this equation is -3 over 2. The y intercept is
4.
• 3. You would graph this line, by first graphing the y
intercept.
You can look at 4 as (0, 4). Looking at your graph, the x
intercept is 0 so you start at the middle point on your
graph and count up 4 spaces.
From there, remember to use rise over run. You will start
at 4, and count down 3 spaces(-3). Next, you go to the left
2 spaces(-2).
Part A:
• 4. –3x + 2y = 8 to change this equation into slope-intercept
form, subtract -3x from both sides. 2y = 3x + 8. Next, divide
both sides by 2. y = 3x over 2 + 4. The equation is now in
slope-intercept form.
• 5. To graph this equation, the first step would be to graph the y
intercept. (0, 4). You since the x intercept is 0, you just move up
4 spaces. Next, you follow rise over run. You would move up 3
spaces from 4, then go to the right 2 spaces.
• 6. The graphs of the two equations are similar because; they
are both written out as y = 3x over 2 + 4. At a first quick glance,
you would think that they were the same. If you look closer
though, you see that one in y = - 3x over 2 + 4, and one is y =
3x over 2 + 4.