INC341
Root Locus
Lecture 7
INC 341
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Rectangular vs. polar
jω
s = 4 + j3
3
σ
4
Rectangular form:
Polar form
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4 + j3
magnitude=5, angle = 37
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Rectangular form
Add, Subtraction
(4 j3) (1 j ) 5 j 4
Polar form
Multiplication
537 2 12
5 2(37 12 ) 1025
Division
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537 2 12
5
49
2
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a jb
r
2
b
arct an
a
a r cos
b
r
θ
a
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r a b
2
b r sin
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Vector representation of a transfer function
m
F (s)
( s zi )
i 1
n
( s pi )
i 1
m
s zi
zerolengths i
M
n1
polelengths
s pi
i 1
zeroangles poleangles
m
(s z ) (s p )
i
i 1
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n
i
i 1
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Vector s
(s+a)
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(s+a)
(s+7)
s = 5+j2
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Example
( s 1)
F ( s)
s( s 2)
Find F(s) at s = -3+j4
F ( s)
( s 1)
s( s 2)
2 j4
(3 j 4)(1 j 4)
20116.57
5126.87 17104.04
0.217 114.34
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What is root locus and why is it needed?
• Fact I: poles of closed-loop system are an
important key to describe a performance of the
system (transient response, i.e. peak time,
%overshoot, rise time), and stability of the
system.
• Fact II: closed-loop poles are changed when
varying gain.
• Implication: Root locus = paths of closed-loop
poles as gain is varied.
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Cameraman
Object Tracking
using infrared
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Varying gain (K)
Varying K, closed-loop poles are moving!!!
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Transient:
• K<25 overdamped
• K=25 critically damped
• K>25 underdamped
• Settling time remains the
same under underdamped
responses.
Stability:
• Root locus never crosses
over into the RHP, system is
always stable.
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Concept of Root Locus
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Closed-loop transfer function
KG ( s)
T ( s)
1 KG ( s) H ( s)
Characteristic equation
KG(s) H (s) 1 1180
magnitude
phase
INC 341
KG(s) H (s) 1
KG( s) H (s) (2k 1)180
k 1,2,3,...
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If there is any point on the root locus,
its magnitude and phase will be
consistant with the follows:
magnitude
phase
KG(s) H (s) 1
KG( s) H (s) (2k 1)180
k 1,2,3,...
Note that: phase is an odd multiple of
180
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Example
Is the point -2+3j a closed-loop pole for some value
of gain? Or is the point on the root locus?
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KG ( s) H ( s)
K ( s 3)(s 4)
( s 1)(s 2)
1 2 3 4 56.31 71.57 90 108.43 70.55
-2+3j is not on the root locus!!!
What about 2 j( 2 / 2) ?
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The angles do add up to 180!!!
2 j ( 2 / 2) is a point on the root locus
What is the corresponding K?
KG ( s ) H ( s ) 1
1
K
G ( s) H ( s)
K
L3 L4
L1 L2
0.7 0 7 1.2 2
2 .1 2 1 .2 2
0 .3 3
L1L2
G( s)
L3 L4
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Sketching Root Locus
1. Number of branches
2. Symmetry
3. Real-axis segment
4. Starting and ending points
5. Behavior at infinity
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1. Number of branches
Number of branches = number of closed-loop poles
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2. Symmetry
Root locus is symmetrical about the real axis
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3. Real-axis segment
On the real axis, the root locus exists to
the left of an odd number of real-axis
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KG(s) H (s) (2k 1)180
• Sum of angles on the real axis is either 0 or
180 (complex poles and zeroes give a zero
contribution).
• Left hand side of even number of poles/zeros
on the real axis give 180 (path of root locus)
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Example
root locus on the real axis
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4. Starting and ending points
Root locus starts at finite/infinite poles of G(s)H(s)
And ends at finite/infinite zeros of G(s)H(s)
closed-loop transfer function
KG ( s)
T ( s)
1 KG ( s) H ( s)
N G ( s)
G(s)
DG ( s )
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N H ( s)
H ( s)
DH ( s)
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T ( s)
KN G ( s) DH ( s)
DG ( s) DH ( s) KN G ( s) N H ( s)
K=0 (beginning) poles of T(s) are DG ( s) DH ( s)
K=∞ (ending) poles of T(s) are KNG (s) N H (s)
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Example
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5. Behavior at infinity
Root locus approaches asymptote as the
Locus approaches ∞, the asymptotes is given by
a
finite poles finite zeros
# finite poles# finite zeros
(2k 1)
# finite poles# finite zeros
k 0, 1, 2, ...
a
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Rule of thumb
# of poles = # of zeroes
K
KG ( s) H ( s)
s( s 1)(s 2)
has 3 finite poles at 0 -1 -2, and 3
infinite zeroes at infinity
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Example
Sketch root locus
0
(1 2 4) (3)
4
4 1
3
(2k 1)
# finitepoles# finitezeros
/ 3 , for k 0
,
for k 1
5 / 3 , for k 2
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INC 341
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