Word Problem Clue Words

advertisement
MCC9-12.A.CED.1 Create equations and inequalities in
one variable and use them to solve problems.
We will
“translate” a
word
problem into
an equation
that
represents it.
But first, we need
to understand
some clues to
help us translate
the word
problems into
algebraic
equations.
ADDED TO
ADDITIONAL
ALL
ALTOGETHER
BOTH
COMBINED
IN ALL
INCREASED BY
MORE THAN
SUM
PLUS
RAISE
TOGETHER
TOTAL
CHANGED
DECREASED BY
DIFFERENCE
DROPPED
EXCEEDED
FEWER
HAVE LEFT
LESS
LOST
MORE
REDUCED
REMAIN
SUBTRACT
TAKE AWAY
MINUS
AT
MULTIPLIED BY
**OF**
PRODUCT OF
TIMES
TWICE
CUT
DIVIDED
DIVISOR
EACH
EQUAL PARTS
EVERY
RATIO OF
AVERAGE
OUT OF
QUOTIENT
SEPARATE
SHARED
SPLIT
PER
ARE
EQUALS
GIVES
IS
IS THE SAME AS
LEAVES
MAKES
RESULTS
WAS
WILL BE
WERE
YIELDS
AT MOST
NOT MORE THAN
IS SMALLER THAN
IS LESS THAN
BELOW
MAXIMUM
IS NOT GREATER THAN
IS MORE THAN
IS GREATER THAN
IS LARGER THAN
ABOVE
AT LEAST
MINIMUM
IS NOT LESS THAN
NOT SMALLER THAN
~NUMBER (X)
~INTEGER (X)
~CONSECUTIVE
INTEGER (X + 1)
•
•
•
•
•
•
•
Read through the entire problem.
Highlight the important information and
key words that you need to solve the
problem.
Identify and define your variables.
Write the equation or inequality.
Solve.
Write your answer in a complete sentence.
Check or justify your answer (optional).
 Two
more than a number
 Five
less than three times a number
 Seven
times a number, increased by four
 The
minimum value of a number is 65
 Twenty
is more than a number
 The
difference of a number and three is not
more than two.
 Thirty
times a number is at most 90

The sum of 38 and twice a number is 124.
Find the number.
 The
sum of two consecutive integers is less
than 83. Find the pair of integers with the
greatest sum.
A
rectangle is 12m longer than it is wide. Its
perimeter is 68m. Find its length and width.
 The
length of a rectangle is 4 cm more than
the width and the perimeter is at least 48
cm. What are the smallest possible
dimensions for the rectangle?
Download