Significant digits

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Significant digits

Objectives:

State the purpose of significant digits

State and apply the rules for counting and doing calculations with significant digits

One way engineers use significant digits….

Significant digits

Measurements that indicate the precision of the tool used

Important—we want to let other scientists and engineers know how

“good” our measurements are!

3.42 cm

This means:

◦ My tool had markings to the tenths place (I can

COUNT them)

◦ I estimated the hundredths place (the object was between 3.4 and 3.5 but closer to 3.4)

◦  3 significant digits

3900 cm

This means:

◦ My tool had markings to the thousands place

(I could COUNT them)

◦ I estimated the hundreds place (the object was between 3000 and 4000 but much closer to 4000 )

◦  2 significant digits

3900. cm

This means:

◦ My tool had markings to the tens place (I could COUNT them)

◦ I estimated the ones place (the object appeared to be right at 3900)

◦  4 significant digits

Clues: How to know when a number is significant

It is a non-zero ( 1, 2, 3, 4, 5, 6, 7, 8, 9 )

It is a zero at the END of a decimal

AFTER a decimal point (4.5

00 )

It is a zero between non-zeros (5, 00 5)

It is a zero at the end of a whole number

AND there is a decimal (5 0 .)

Examples of Sig zeros

Examples of NONsig zeros

5, 00 2

56 00 .

.3

0

0.00

5

0.0

3

3 0

5 0,000,000

This number has a mix of significant and insignificant zeros:

0.00

3 00

Rules for counting significant digits:

2300

23 00  Non-zeros are significant

23 00  zeros are at the end of a number without a decimal = insignificant

23 00 = 2 s.f.

This means the tool allowed us to

COUNT the thousands place, and

estimate the hundreds place (we counted to 2000 and we estimated the value was between 2000 and 3000, but closer to

2000.)

Counting significant digits:

230.

23 0.

 Non-zeros = significant

230.

 zero here is at the end of a number WITH a decimal = significant

230. = 3 s.f

This means the tool allowed us to

COUNT to the ones place 230 and we estimated that the value was exactly at

230.

Counting significant digits:

2.300 x 10 -3

BIG IDEA: count the digits of the coefficient only

2 .

3 00 x 10 -3  Non-zeros = significant

2.300

x10 -3  zeros here are at the end of a number and AFTER a decimal = significant

2.300 x 10 -3 = 4 s.f.

This means the tool allowed us to measure

.00230, and we estimated it was exactly at

.002300

Counting significant digits - Practice

0.00400

0.00

4 00  Non-zeros = significant !

0.

00 400  zeros here are at the beginning of a number = insignificant

0.004

00  zeros here are at the end of a number and AFTER a decimal = significant

0.00

400 = 3 s.f.

This means the tool allowed us to measure

0.0040, and we estimated it was exactly at

0.00400.

Practice

Problems 1-10 on your notes

Compare numbers – which is more precise and how do you know. Game – cc. add this to prac probs

Give practical example – ie 2 diff thermoms to meas the same temp

Practice - Answers

State the number of significant digits.

1) 1234  4

2) 0.023  2

3) 890  2

4) 91010  4

5) 9010.0  5

6) 1090.0010  8

7) 0.00120  3

8) 3.4 x 10 4  2

9) 9.0 x 10 -3  2

10) 9.010 x 10 -2  4

Calculations:

Addition and subtraction: USE lowest number of decimal places as the # of decimal places for your answer. Just do add probs in class maybe 1 subt. Prep to not have add and subt, and have it just in case

Another day multiplying and dividing USE least number of total sig figs as the # of sig figs for your answer.

Example:

350.83 kg +

400.0 kg

350.83  2decimal places

400.0  1 decimal place

750.83 kg

Lowest # of decimal places

= 1

I need to round this to only one decimal place

750.8 kg

Example:

2.0 x 8000 2.0  2 significant figures

8000  1 significant figure

16,000

LEAST? = 1

I need to round this to only one significant digit1

20,000

Practice

Problems 11-20 in your notes

Practice - Answers

5.33 + 6.020 = 11.350  11.35

5.0 x 8 = 40.0  40

81÷ 9.0 = 9.0  9.0

3.456 – 2.455= 1.001

 1.001

5.5 – 2.500 =3.000  3.0

7.0 x 200 =1400.0  1000

300. ÷ 10.0 = 3.0  3

(3.0 x 10 4 )x (2.0 x 10 1 ) = 6.0 x 10 5  6.0 x 10 5

(9.000 x 10 -2 )÷ (3.00 x 10 1 ) = 3.000 x 10 -3  3.00 x 10 -3

(3.0 x 10 4 ) - (2.0 x 10 1 ) = 2.998 x 10 4  3.0 x

10 4

Exit Ticket

2300

Counting significant digits:

450.0

◦ What do we know about the measurement made?

◦ How many significant digits are in the answer?

◦ Is this number more less precise than the previous answer?

Counting significant digits:

20

◦ What do we know about the measurement made?

◦ How many significant digits are in the answer?

◦ Is this number more less precise than the previous answer?

Counting significant digits:

0.000450

◦ What do we know about the measurement made?

◦ How many significant digits are in the answer?

◦ Is this number more less precise than the previous answer?

Counting significant digits:

3,006

◦ What do we know about the measurement made?

◦ How many significant digits are in the answer?

◦ Is this number more less precise than the previous answer?

Counting significant digits:

23.00

23 .00  Non-zeros = significant !

23.00

 zeros here are at the end of a number and AFTER a decimal = significant

23.00 = 4 s.f.

This means the tool allowed us to measure 23.0, and we estimated it was exactly at 23.0.

Example:

10.75 – 0.411

10.75  2 decimal places

0.411

 3 decimal places

10.339

LEAST? = 2

I need to round this to only two decimal place!

10.34

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