Linear inequalities 1

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Today’s daily 5-minute quiz will
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Weekly Quiz 2 Results:
• Average class score after partial credit: _______
(_____ raw score)
• Commonly missed questions: #_______________
Grade Scale
Grade
A
A-
B+
B
B-
C+
C
C-
F
Points
≥ 920 ≥ 890 ≥ 860
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% Score
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≥ 80
≥ 75
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≥ 89
≥ 86
≥ 67
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Why you should keep taking the practice
quiz until you can score at least 90%:
(B+)
(almost a C-)
(low F)
(A)
REMINDERS for the upcoming Test 1:
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• You have unlimited attempts, so retake the
practice test until you score at least 90%.
• If you score < 90%, come into the open lab
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(Or just take the practice test in the open lab to start with …)
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Quiz question # ____ (xx%)
Section 2.8
Linear Inequalities 1
Linear Inequalities
An inequality is a statement that contains one of
the symbols: < , >, ≤ or ≥.
Linear equations:
Linear inequalities:
x=3
x>3
12 = 7 – 3y
12 ≤ 7 – 3y
Graphing solutions to linear inequalities
in one variable
• Use a number line.
• Use a square bracket at the endpoint of an interval if you
want to include the point.
• Use a parenthesis at the endpoint if you DO NOT want to
include the point.
Graph the inequality x  7:
Graph the inequality x > – 4:
Using graphs to figure out how to write
a solution in interval notation:
]
-∞
7
-∞
∞ The inequality x  7
is expressed in interval
notation as (-, 7]
(
∞ The inequality x > -4 is
-4
expressed in interval
notation as (-4, )
IMPORTANT:
In interval notation, ∞ and -∞
ALWAYS are enclosed by
a (round bracket)
NEVER by a [ square bracket].
Example from today’s homework:
x  9}
[9, )
Addition property of inequality
• a< b and a + c < b + c are equivalent inequalities.
Example: 2 ≤ 4
and 2 + (-3) ≤ 4 + (-3)
are equivalent
Multiplication property of inequality
• if c is positive, then:
a< b and ac < bc are equivalent inequalities,
Example: 3 ≥ 1 (multiply both sides by 2); so 6 ≥ 2 is equivalent.
• if c is negative, then:
a< b and ac > bc are equivalent inequalities,
Example: 3 ≥ 1 (multiply both sides by -2); so -6 ≤ -2 is equivalent.
.
Solving linear inequalities in one variable
1)
2)
3)
4)
Multiply to clear fractions.
Use the distributive property (parentheses).
Simplify each side of the inequality.
Get all variable terms on one side and
numbers on the other side of inequality
(addition property of inequality).
5) Isolate variable by dividing both sides by the
number in front of the variable (multiplication
property of inequality).
6) Do not forget to change the direction of the
inequality sign if you multiply or divide
both sides by a negative number.
Don’t forget that if both sides of an
inequality are multiplied or divided
by a negative number, the direction
of the inequality sign MUST BE
REVERSED.
Example 1:
-7(x – 2) - x < 4(5 – x) + 12
-7x + 14 - x < 20 - 4x + 12
(use distributive property)
- 8x + 14 < - 4x + 32
(simplify both sides)
- 8x + 4x + 14 < - 4x + 4x + 32
- 4x + 14 < 32
- 4x + 14 - 14 < 32 - 14
- 4x < 18
 18
x
4
Graph of solution ( -9
,)
2
(add 4x to both sides)
(simplify both sides)
(subtract 14 from both sides)
(simplify both sides)
(divide both sides by -4)
(
-9
2
9
x
(simplify)
2
Example 2:
 x  2 1  5x

 1
2
8
  x  2   1  5x 
8
  8
  8(1)
 2   8 
4( x  2)  1(1  5 x)  8
 4 x  8  1  5 x  8
x  7  8
x  15
(,15)
Example from today’s homework:
Something to think about:
• How would you graph the inequality 2 > x?
• What would this look like in interval notation?
Note that 2 > x is equivalent to x < 2.
Writing the inequality with the variable term on the
left makes it easier to “see” what the graph and
the interval notation should look like.
Interval notation: (-∞, 2)
This is an argument for working to put/keep your variables on the
left side of the expression as you solve linear inequalities.
Inequality Applications
Example: Six times a number, decreased by 2, is at
least 10. Find the number.
1.) UNDERSTAND
Let x = the unknown number.
“Six times a number” translates to 6x,
“decreased by 2” translates to 6x – 2,
“is at least 10” translates ≥ 10.
Example continued:
2.) TRANSLATE
Six times
a number
decreased
by 2
is at least
10
6x
–
2
≥
10
Example continued:
3.) SOLVE
6x – 2 ≥ 10
6x ≥ 12
x≥2
Add 2 to both sides.
Divide both sides by 6.
4.) INTERPRET
Check: Replace “number” in the original statement of the
problem with a number that is 2 or greater.
Six times 2, decreased by 2, is at least 10
6(2) – 2 ≥ 10
10 ≥ 10
State: The number is 2.
REMINDER:
In interval notation, ∞ and -∞
ALWAYS are enclosed by
a (round bracket)
NEVER by a [ square bracket].
The assignment on this material (HW 9) is due at the
start of the next class session.
Lab hours in 203:
Mondays through Thursdays
8:00 a.m. to 7:30 p.m.
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