15.7 Probability Day 3 There are 2 nickels, 3 dimes, and 5 quarters 1.) Find the probability of selecting 1 nickel, 1 dime, and 1 quarter in that order without replacement. Total = 10 P(N, D, Q) = 2 3 10 9 5 8 30 720 1 24 There are 2 nickels, 3 dimes, and 5 quarters 2.) Find the probability of selecting 1 nickel, 1 dime, and 1 quarter in any order without replacement. Total = 10 1 (From #1): P(N, D, Q) 24 How many ways? 3 coins, arranging 3 = 3! = 6 1 1 6 4 24 There are 2 nickels, 3 dimes, and 5 quarters 3.) Find the probability of selecting 1 nickel, 1 dime, and 1 quarter in any order WITH replacement. Total = 10 2 3 5 P(N, D, Q) = 1 0 10 10 30 1000 Still 6 arrangements: 18 9 3 6 50 100 100 3 100 A red, green, and yellow die are tossed. Find the probability: 1.) All 3 dice show a six. P(6, 6, 6) = I know, it’s creepy!! 1 1 1 1 6 6 6 216 A red, green, and yellow die are tossed. Find the probability: 2.) The green die shows an odd number and the other 2 show different even numbers. Odd #s: 1, 3, 5 Even #s: 2, 4, 6 G R Y reen 3 6 ed 3 6 there are 3! there are 3! ellow 1 1 1 1 2 2 3 12 6 2 A red, green, and yellow die are tossed. Find the probability: 3.) All 3 dice show the same number. or or or or or 111 222 333 444 555 666 1 1 1 1 6 6 6 216 Same probability for each There are 6 ways! 1 1 6 36 216 Standard Deck of Cards Clubs Hearts Diamonds Spades (Black) (Red) (Red) (Black) 52 cards in the deck 26 black, 26 red 4 suits: hearts, diamonds, clubs, spades 13 of each suit Homework #7 12-5 Practice WS

Download
# Homework

homework writing help

for a fair price!

check it here!