Uploaded by Auston Ng

Math 10C notable stuff

advertisement
LCM
The least common multiple is the smallest number that is a multiple of both numbers. (not zero!)
Prime factorization can be used to determine the least common multiple.
Prime factorize all numbers
Take all factors and multiply them together to get LCM
(If you have a duplicates of factors you just take the one with the bigger power Ex. you have
one 2^2 and one 2^4, take 2^4)
GCF
The least common multiple is the smallest number that is a multiple of both numbers. (not zero!)
Prime factorization can be used to determine the least common multiple.
Prime factorize all numbers
Take all factors and multiply them together to get LCM
(If you have a duplicates of factors you just take the one with the bigger power Ex. you have
one 2^2 and one 2^4, take 2^4)
Prime factorization
Prime factorization is the process of finding which prime numbers multiply to the original
number.
Square & cube roots
How to check if something is a perfect root of x:
1. Prime factorize the radicand and write it out
2. If all the exponents match the index of the radical then it's a perfect root for that
index,x
3. Cancel out the powers and remove the radical then multiply what you have left to
find the answer
Ex. Check if ∛5832
1. Prime factorize: 5832 = 2^3 x 3^6
2. Check if exponents of factors in prime factorization are multiplies of the index:
yes
3. That means this 5832 is a perfect cube, now to find the answer just simplify:
∛2^3x3^6 = 2 x 3^2 = 18
Prime numbers - A number that has only two factors, 1, and itself
Note* - 1 is not a prime number
Composite numbers - A number greater than 1 that’s NOT prime. All composite numbers can
be written as a product of primes.
Divisibility rules
0
0 is divisible by everything, nothing is divisible by 0.
1
Everything is divisible by one
2
All even numbers are divisible by 2
3
If the sum of all digits is divisible by 3
4
If the last two digits as a number divisible by 4
5
Last digit is 0 or 5
6
If the number is divisible by 2 and 3
7
If the difference of the last digit doubled minus the rest of the digits as a number is
divisible by 7
8
If the last three digits as a number is divisible by 8
If the number is a three or less digit number then if it’s divisible by 4 it’s also divisible by
8 (except 4)
9
If the sum of the digits is divisible by 9
10
If the number ends in 0
11
If the alternating difference of the digits is divisible by 11
12
If the number is also divisible by 3 & 4
Exponent laws
http://people.sunyulster.edu/nicholsm/webct/WebCT2/laws_of_exponents.htm
Absolute Value
The distance of a number from zero
Lesson 4 - Intro to factoring
ax^2+bx+c
Lesson 5 -Factoring quadratics & factoring by grouping
Lesson 6 - Factoring through decomposition
Decomposition - a way to factor, when used the answer will always be true
I use it when ‘a’ and ‘c’ are both greater than 1
Steps when factoring through decomposition:
1. Take out GCF (if possible)
2. Multiply ‘a’ & ‘c
3. Find two numbers that will multiply into ac, and have a sum of b
4. Rewrite ‘bx’ as a sum
5. Factor through grouping
6. Double check to see if anything is still factorable
Ex. Factor 6x^2+3x-4
6x-4=-24, 3 & -8 multiply to -24, and have a sum of 3, rewrite: 6x^2+3x-8x-4, factor through
grouping: 3x(2x+1)-4(3x+1) = (3x-4)(2x+1)
Lesson 7 - factoring difference of squares
Factoring difference of squares using conjugates
When you encounter something in the form of ax-by & all of them are perfect squares, then you
can factor it by multiplying it with its conjugate
Ex. x^2-4 = (x-2)(x+2), x^2y^2=(x-y)(x+y)
You cannot factor a sum of squares
Factoring with fractions
Factor 4a^2+2a+⅖
1. Undistribute ⅖ , to do so divide all terms by numerator, and divide by the denominator:
⅖(10a^2+5a+1)
2. If possible factor more
Factor x^3+⅕x^2-⅓x
1. Undistribute the LCM of the fractions, in this case the LCM of ⅕ & ⅓ is 1/15
2. Divide by numerator and multiply by denominator: 1/15x(15x^2+3x-5)
3. Factor more in possible
Lesson 8 - Factoring special cases
Perfect square trinomials
(a+b)^2 = a^2+2ab+b^2
(a-b)^2= a^2-ab+b^2
Factoring a[f(x)]^2=bf(x)+c
Can only use if the exponents are going down in a geometric sequence between each
monomial
Factor x^4-5x^2-14
Check if the powers are greater than 2, then assign a variable to the high power Let A=x^2
Replace & factor: A^2-5A-14 = (A-7)(A+2)
Substitute values: (x^2-7)(x^2+2)
Lesson 9 - Factoring a sum & difference of cubes
Sum of cubes
a^3+b^3 = (a+b)(a^2-ab+b^2)
Difference of cubes
a^3-b^3= (a-b)(a^2+ab+b^2)
How to determine what method to use when factoring?
1. Take out a GCF (If possible)
2. Two terms?
perfect square trinomials (a^2-b^2), or
sum/difference of cubes (a^3±b^3)
Three terms?
Inspection if a is 1, or
Decomposition if a & c are > than 1, or
Perfect square trinomial (a+b)^2 = a^2+2ab+b^2 (a-b)^2= a^2-ab+b^2, or
a[f(x)]^2=bf(x)+c if the exponents are big & are a geometric sequence
Four or more terms?
Grouping
Check if there’s a perfect square trinomial w/3 of the terms?
3. Double check, check for more GCF’s or if you can further factor
Polynomials
Degree of polynomials - the monomial which has the biggest degree of the polynomial is the
polynomials degree
Q. Determine the degree:
7x^2+5x-6: degree 2 polynomial
3xy^2+16x^3y^3+17x^3y^4: degree 4 polynomial (quadratic)
When dividing polynomials if you aren’t dividing by a monomial you can use long division
Long division https://www.youtube.com/watch?v=_FSXJmESFmQ
Synthetic division https://www.youtube.com/watch?v=FxHWoUOq2iQ
●
Word Problems (LCM/GCF)
Download