P3 Modulus Function

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Eze 1 A
OI
1
2n
-111
IN
=
squaring
Reference
't
÷t÷ ÷ t÷ f÷ ÷ ÷ ÷
pone
Katy E
1-
to
Yz
na
-
a-
4h41 then = U2
42
Zntl =
in
-
W
22+1=2
32742+1=0
:
is a solution
south on
k= - l
Ans 8-
n=
CHI
Yy
-
g
-
Yz , -1
:
12×-3+11=1-431
13=1/3 I
'
1-21-11
=
I
-
l
l
l :F=±EX
on
-
-
-
-
-
-
13 al
when
method
Bet
:
Nde
I 3- 2mL
031
=
-
-
-
-
-
-
=
modulus
his ear function is
answer
both
sides
asking
severing
is mandatory in squaring born
both
sides in
.
sides
@a)
-
E 's:* : :
5×2+15 n
⇐
n-
÷ihj¥¥÷÷
They
-
& 2247
5mL a -13 )
chkoo
13
-
-
3M
-
L
.
-
9=0
3 Cn -133=0
3)be -13)
2×351=13×33)
*
31553
I
eo
.
n =
is
31g
g -3
asocuhcn
.
'
Oda
Note
In
21
-
=
7
E£-e
Ice
-
E) Get E)
/
function
modules
7
=
1-
Tz
I
k€2
n'
2=7
-
-
NZ 9
n
I
I 3
=
52
n2=
n.in?OEm1
No
-
W)
=
22--9
g
I :÷:
solution
=
-13
is
me
Somnath
That's how you
I 5
-
n
please cheek me
041
/a7I
NI 2=7
a
correct
need to
method
solve
.
.
3- N
TE
÷÷¥÷:
MIN
Ez
Ge 2)
x=
-
I e
-
=
se
=
-1
I
533
-
( Ntl )=0
t
Both
/n=€¥qt§
sombre
I
2=0
possible
solution
MIN
N
)
=
I
-
four
-
8=0
-1533
possible
answers
.
AS
a)
set
s
2y=
Int 21 ty
6
=
→
from er ①
I 8- Zyt 21
110 Zyl
110 Zyl
-
x
t
+
-
y
y
=
E¥
y
-
Y
-
=
4
=
-
=
IN
-
.
2g
6-y
.
a
I
.io:5#5
3.
y
=
16
16/3 is a
solution
possible
Y
)
O
=
u
=
8
-
2×16
3
224-3-32
2=-873
(-813g
0,4) and
'
%)
32
-
3M
method
chscct
6
4
(
check the
6
=
is
solution :
y
=
8
8-2×4
=
n=
051
=
Please
②
somehow
possible
a
①
→
=
-
I
22cL
%)
=
-
51
Zzse
1-
5512
+
↳
z
EEIzafIEE.IF.se/aIEEEaZn~-l3n
F.
-5=0
-
222+5
=
-
zag
22--5-13220
when n c
Zn't 3N
222-1
-
-
5512
when
5=0
222-32-5=0
-
fJ7z
22h52
Jn -2N -5=0
(2N -153=0
NC 2n -15) -1
-
C
U
-12k
em
-
5=0
5) tl ( 2K 8) zo
NC 2n
-
-
'
'
'
is
when
Erny soms.my
're
5512
a>
2n2t3n
get
is
-
2=-1
5=0
somethin
,
Possible soruh
y
=
-
3C
-
⇐ 3)
Of
5
l
)
In-11
5yZt9y
5541 Oy
5.
-
y Cy -12)
LEY
a
-
-
( -512 )
-5/2
=
by
is the solution
2=0
-
Yg
-
y
-
I
220
Cy-12320
-123=0
Cy
D
=
=-3
n
.
-11=2
-
ly
-
In 1)
-
-
y
g
(-5/2,172)
and
In -112+91
Put
's 2=-1
,
-5/2 is the
range
one
=3
smarm
but both not
nine
%
any
,
y
=
Yg
,
-2
In -11=1-2
nor possible
I
when nd
N = I
-
n
II
5 felt 6=0
-
IN
Put
a
YZ
=
45
It 1/5
solutions
fumble
"
n
=
/n=4sI
M€-415
are
I
a >
a-I
45
Yg
I
Ntl
-
when
,
=L
Z
y
-
Sgt
-
2
6=0
Ly 2) Cy 33=0
-
-
y
y =3
=3
,
I ul
Inl =3
2
=
1n=t3T
-
-
0£
12Mt
when
a L
-
l
l
Yz
t
l
2n
t
-11
=
3
n=±qfz
is
somehow
a
En le
OED In -141 I
FEI
u
<
a
4
sowhcsi is
southern
12N
32
c
n
e
)
laced
b)
ET
is
-
-
Infirm
1n>4J
y
Ub
I
isabembe
sum
is the schism
1nc-4↳orn#
-
51713 al
-
-
#
%
.at?sFsfsaE
) tn#qisme
apm.4sowhms.
N>3
±: :S's
2
3778
72
fact
igniting
InZ93J
.
prhuhcn
is
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