Uploaded by Atika Al-hmoud

Inheritance of Sex linked traits lab

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Names: _____________________________________________________________________________
Inheritance of Sex-Linked Traits
Pre-Lab Questions
Sex-linked genes are genes on the X and Y chromosomes. Traits controlled by these genes are called
sex-linked traits. Two sex-linked traits include hemophilia and colorblindness. Hemophilia is a genetic
disorder in which a person’s blood clots slowly or not at all. If a person has the dominant allele XH, he or
she will have normal blood. If a person has only the recessive allele Xh, he or she will have hemophilia.
Red-green colorblindness is also a genetic disorder. In this disorder, the person does not see red and
green properly. This person will see green as gray and red as yellow. If a person has at least one dominant
allele XC, he or she will not have colorblindness. If a person has only the recessive allele Xc, he or she will
have colorblindness.
A carrier is a person who has one dominant allele and one recessive allele for a trait. The person will
have the dominant trait, but could pass the recessive allele to her offspring. For sex-linked traits, ONLY
females can be carriers.
In this investigation, you will see how hemophilia and colorblindness are inherited.
1. How are the alleles for sex-linked genes passed from parents to child?
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2. Write the sex chromosomes for each gender:
Male – ______________
Female – _______________
3. Write what each allele represents:
XH – ______________________________
Xh – ______________________________
XC – ______________________________
Xc – ______________________________
4. What is a carrier?
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Problem: How are hemophilia and red-green colorblindness inherited?
Directions:
1. Decide who will be the mom and who will be the dad. Give one penny to each person.
2. Take turns flipping your coins and recording the alleles. Record your allele combinations on a
separate sheet of paper.
3. Complete 20 trials of flipping your coins, and recording the alleles.
4. After you have completed the 20 trials, use tally marks to record how many of each allele
combination you created.
5. Complete the Punnett square for each family.
6. Answer the Post-Lab questions.
Part A: Hemophilia
Family 1. Parents do not have hemophilia; mother is a carrier of hemophilia (XHXh).
Mom:
heads – XH
tails – Xh
Allele Combination
Dad:
heads – XH
tails – Y
Children of Family 1
XHXh Mother and XHY Father
Children Observed
Total
Percent (Total /
20)
XHXH
XHXh
XhXh
XHY
XhY
Punnett Square Predicted Probabilities:
XHXH _______________%
XHXh________________%
XhXh________________%
XHY________________%
XhY________________%
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Family 2. Father has hemophilia; mother is a carrier of hemophilia (XHXh).
Mom:
heads – XH
tails – Xh
Dad:
heads – Xh
tails – Y
Children of Family 2
X Xh Mother and XhY Father
Children Observed
H
Allele Combination
XHXH
XHXh
XhXh
XHY
XhY
Total
Percent (Total /
20)
Punnett Square Predicted Probabilities:
XHXH _______________%
XHXh________________%
XhXh________________%
XHY________________%
XhY________________%
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Part B: Colorblindness
Family 3. Father is colorblind, mother has 2 dominant alleles.
Mom:
heads – XC
tails – XC
Dad:
heads – Xc
tails – Y
Children of Family 3
X XC Mother and XcY Father
Children Observed
C
Allele Combination
Total
Percent (Total /
20)
XCXC
XCXc
XcXc
XCY
XcY
Punnett Square Predicted Probabilities:
XCXC _______________%
XCXc________________%
XcXc________________%
XCY________________%
XcY________________%
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Family 4. Parents are not colorblind, mother is heterozygous.
Mom:
heads – XC
tails – Xc
Dad:
heads – XC
tails – Y
Children of Family 4
X Xc Mother and XCY Father
Children Observed
C
Allele Combination
Total
Percent (Total /
20)
XCXC
XCXc
XcXc
XCY
XcY
Punnett Square Predicted Probabilities:
XCXC _______________%
XCXc________________%
XcXc________________%
XCY________________%
XcY________________%
Post-Lab Questions: Analyze and Conclude
1. a. How many alleles for hemophilia do females have? ______________________
b. How many alleles for red-green colorblindness do females have? ______________________
c. How many alleles for hemophilia do males have? ______________________
d. How many alleles for red-green colorblindness do males have? ______________________
2. Why is there a difference in the number of alleles for hemophilia and red-green colorblindness between
males and females?
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3. Why are only females carries for sex-linked traits?
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4. Which of the parents can pass the allele for hemophilia to a son? Explain.
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5. Which of the parents can pass the allele for hemophilia to a daughter? Explain.
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6. In Family 3, why are there no colorblind children even though one of the parents is colorblind?
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7. Does your data from the lab support the predicted results from the Punnett squares? Give an example to
support your answer.
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Extension: Extra Credit
Answer each question below, creating a Punnett square to help you.
1. The brother of a woman’s father has hemophilia. Her father does not have hemophilia, but she is
concerned that her son might. Could she have passed the allele for hemophilia to her son? Explain.
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2. A woman’s father is colorblind. She marries a colorblind man. Could their son be colorblind? Could
their daughter be colorblind? Explain.
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3. What is the possibility that a carrier and a person who has a sex-linked genetic disorder will have a son
with the disorder? A daughter?
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4. What is the probability that a carrier and a person who does not have a sex-linked genetic disorder will
have a son with the disorder? A daughter?
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