Uploaded by Harry Robertson

Practical Assignment - Econometrics

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ECON4003: Practical Assignment
Part I
(a) π‘₯𝑖 − πœ€ = π›Όπ‘Œπ‘– E
π‘₯𝑖 − πœ€
π‘Œπ‘– =
𝛼
π‘₯𝑖 πœ€π‘–
π‘Œπ‘– = −
𝛼 𝛼
π‘₯𝑖 πœ€π‘–
− = π›½π‘œ + 𝛽1 π‘₯𝑖 + 𝑒𝑖
𝛼 𝛼
π‘₯𝑖 πœ€π‘–
𝑒𝑖 = − − 𝛽0 − 𝛽1 π‘₯𝑖
𝛼 𝛼
1
πœ€π‘–
= ( − 𝛽1 ) π‘₯𝑖 − − 𝛽0
𝛼
𝛼
1 − 𝛼𝛽1
πœ€π‘–
=(
) π‘₯𝑖 − − 𝛽0
𝛼
𝛼
1 − 𝛼𝛽1
πœ€π‘–
=
π‘₯𝑖 − 𝛽0 −
𝛼
𝛼
1−𝛼𝛽1
(b) 𝐸(𝑒𝑖 |𝑋) = 𝐸 (
𝛼
πœ€
𝑋𝑖 − 𝛽0 − 𝛼𝑖 |𝑋)
1 − 𝛼𝛽
πœ–
= 𝐸 ( 𝛼 1 𝑋𝑖 |𝑋) − 𝐸(𝛽0|𝑋) − 𝐸 ( 𝛼𝑖 |𝑋)
1 − 𝛼𝛽1
1
(𝐸(𝑋𝑖 |𝑋)) − 𝐸(𝛽0 |𝑋) − 𝐸(πœ€π‘– |𝑋)
𝛼
𝛼
1 − 𝛼𝛽1
1
=
𝑋𝑖 − 𝛽0 − × 0
𝛼
𝛼
1 − 𝛼𝛽1
=
𝑋𝑖 − 𝛽0
𝛼
=
1
(c) Assumption SR.3 confirms that the sample outcomes of 𝑋𝑖 , 𝑖 = 1, … , 𝑛 , must take at
least two different values
𝑛
Μ‚1 = ∑ 𝑀𝑖 π‘Œπ‘–
𝛽
𝑖=1
𝑛
= ∑ 𝑀𝑖 (𝛽0 + 𝛽1 𝑋𝑖 + 𝑒𝑖 )
𝑖=1
This substitution is possible by inputting the true model expression derived from the
linearity assumption
𝑛
𝑛
𝑛
𝛽̂1 = 𝛽0 ∑ 𝑀𝑖 + 𝛽1 ∑ 𝑀𝑖 𝑋𝑖 + ∑ 𝑀𝑖 𝑒𝑖
𝑖=1
𝑖=1
𝑖=1
𝑛
= 𝛽1 + ∑ 𝑀𝑖 𝑒𝑖
𝑖=1
since
𝑛
∑ 𝑀 = 0,
𝑖=1
𝑛
∑ 𝑀𝑋𝑖 = 1
𝑖=1
Taking the expectations of 𝛽̂1 conditional on the sample values of regressor X, where
𝑀𝑖 is treated as non-random in this case since it is a function only of X
𝑛
𝐸(𝛽̂1|𝑋) = 𝐸(𝛽1 + ∑ 𝑀𝑖 𝑒𝑖 |𝑋)
𝑖=1
𝑛
= 𝐸(𝛽1 |𝑋) + 𝐸(∑ 𝑀𝑖 𝑒𝑖 |𝑋)
𝑖=1
𝑛
= 𝛽1 + ∑ 𝑀𝑖 𝐸(𝑒𝑖 |𝑋)
𝑖=1
2
𝛽1 is a constant and thus is its own
expected value and 𝑀𝑖 can be
removed from the conditional
expectation expression as it is non
random
3
(d)
4
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