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Math 9 Q3 Week 3

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MATH 9
QUARTER 3 Week 3
NAME: ____________________________________________GR. & SEC: _____________________
Competency:
The learner:
1. proves the Midline Theorem. (M9GE-lll-d-1)
2. proves theorems on trapezoids and kites. (M9GE-lll-d-2)
To the Learners:
Before starting the module, I want you to set aside other tasks that will disturb you
while enjoying the lessons. Read the simple instructions below to successfully
enjoy the objectives of this kit. Have fun!
1. Follow carefully all the contents and instructions indicated in every page of this
module.
2. Write on your notebook the concepts about the lessons. Writing enhances learning;
that is important to develop and keep in mind.
3. Perform all the provided activities in the module.
4. Let your facilitator/guardian assess your answers using the answer key card.
5. Analyze conceptually the posttest and apply what you have learned.
6. Enjoy studying!
Expectations
This module was designed to help you prove the midline theorem and the theorems
on trapezoids and kites.
After going through this module, you are expected to:
1. Prove the Midline Theorem and solve problem using it.
2. Prove the theorems related to trapezoid and kites.
3. Solve problems involving trapezoids and kites by applying the theorems.
Pre-test
Direction: Choose the letter of the correct answer.
1. In the figure at the right, DE is the midline of โˆ†๐ด๐ต๐ถ and AC = 12 cm. What is the
length of DE?
B
a. 6 cm
b. 8 cm
D
E
c. 12 cm
d. 24 cm
2. What is true about an isosceles trapezoid?
a. It has exactly one pair of parallel sides.
b. It has congruent legs.
c. It has congruent base angles.
d. All of the above.
MATH 9 QUARTER 3 WEEK 3
A
C
3. In the figure at the right, PQRS is an isosceles trapezoid.
If ๐‘š∠๐‘ƒ = 105°. What is the measure of ∠๐‘…?
P
105หš
a. 75°
b. 85°
c. 105°
S
d. 180°
4. In the figure at the right, PQ = 16cm and SR = 24 cm.
What is the measurement of ฬ…ฬ…ฬ…ฬ…
๐‘‡๐‘ˆ?
a. 8 cm
b. 18 cm
c. 20 cm
d. 40 cm
P
T
S
Q
R
Q
U
R
5. What is the length of the diagonal of a kite whose area is 176 sq.cm and the other
diagonal is 16 cm long?
a. 22 cm
b. 24 cm
c. 26 cm
d. 28 cm
Looking Back to your Lesson
In a parallelogram,
1. any two opposite sides are congruent;
2. any two opposite angles are congruent;
3. two consecutive angles are supplementary;
4. the diagonals bisect each other;
5. the diagonals of a parallelogram divides the parallelogram into two congruent
triangles.
The different characteristics of special types of parallelogram
In a rectangle,
1. all four angles are right angles;
2.the diagonals are congruent.
In a rhombus,
1. each diagonal is the perpendicular bisector of the other diagonal;
2. each diagonal bisects a pair of opposite angles.
In a square,
1. all four sides are congruent;
2. all angles are right angles;
3. opposite angles are congruent and supplementary;
5. consecutive angles are supplementary and congruent;
6. the diagonals are congruent;
8. each diagonal bisects a pair of opposite angles.
7. each diagonal is the perpendicular bisector of the other diagonal;
Introduction of the Topic
You have already studied the different parallelograms. Now you need to explore
the other kinds of quadrilaterals. Specifically, trapezoids and kites; their properties;
and how they will be of use to real life situations. But before that, you should study
first the proof of the midline theorem which you can also apply to solve problems.
MATH 9 QUARTER 3 WEEK 3
The Midline Theorem
The segment that joins the midpoints of two sides of a triangle is parallel to the third
side and half as long.
B
1
3 E
D
F
2
Given: In โˆ†๐ด๐ต๐ถ , D is the midpoint of ฬ…ฬ…ฬ…ฬ…
๐ด๐ต and E
ฬ…ฬ…ฬ…ฬ…
is the midpoint of ๐ต๐ถ .
Prove: ฬ…ฬ…ฬ…ฬ…
๐ท๐ธ || ฬ…ฬ…ฬ…ฬ…
๐ด๐ถ and ๐ท๐ธ =
C 4
A
1
๐ด๐ถ
2
Proof:
Statements
Reasons
1. In โˆ†๐ด๐ต๐ถ , D is the midpoint of ฬ…ฬ…ฬ…ฬ…
๐ด๐ต and
ฬ…ฬ…ฬ…ฬ… .
E is the midpoint of ๐ต๐ถ
2. In a ray opposite ฬ…ฬ…ฬ…ฬ…
๐ท๐ธ , there is a point F
ฬ…ฬ…ฬ…ฬ… ≅ ฬ…ฬ…ฬ…ฬ…
such that ๐ท๐ธ
๐ธ๐น
1. Given
3. ฬ…ฬ…ฬ…ฬ…
๐ธ๐ต ≅ ฬ…ฬ…ฬ…ฬ…
๐ธ๐ถ
3. Definition of Midpoint
4. ∠2 ≅ ∠3
4. Vertical angles are congruent.
5. โˆ†๐ท๐ต๐ธ ≅ โˆ†๐น๐ถ๐ธ
5. SAS Congruence Postulate (2,3 & 4)
6. ∠1 ≅ ∠4
ฬ…ฬ…ฬ…ฬ… || ๐ถ๐น
ฬ…ฬ…ฬ…ฬ…
7. ๐ด๐ต
6. CPCTC
ฬ…ฬ…ฬ…ฬ…
8. ฬ…ฬ…ฬ…ฬ…
๐ท๐ด ≅ ๐ท๐ต
ฬ…ฬ…ฬ…ฬ…
ฬ…ฬ…ฬ…ฬ… ≅ ๐น๐ถ
9. ๐ท๐ต
8. Definition of Midpoint
ฬ…ฬ…ฬ…ฬ… ≅ ๐น๐ถ
ฬ…ฬ…ฬ…ฬ…
10. ๐ท๐ด
10. Transitive Property (8 & 9)
11. Quadrilateral ADFC is a Parallelogram
12. ฬ…ฬ…ฬ…ฬ…
๐ท๐ธ || ฬ…ฬ…ฬ…ฬ…
๐ด๐ถ
11. Definition of Parallelogram
12.Ray ๐ท๐น contains ฬ…ฬ…ฬ…ฬ…
๐ท๐ธ
13. ๐ท๐ธ + ๐ธ๐น = ๐ท๐น
13. Segment Addition Postulate
14. ๐ท๐ธ + ๐ท๐ธ = ๐ท๐น
14. Substitution (2)
15. 2๐ท๐ธ = ๐ท๐น
ฬ…ฬ…ฬ…ฬ… ≅ ๐ท๐น
ฬ…ฬ…ฬ…ฬ…
16. ๐ด๐ถ
15. Addition (14)
17. 2๐ท๐ธ = ๐ด๐ถ
17. Substitution (15 & 16)
18. ๐ท๐ธ =
2. In a ray, there is exactly one point at a
given distance from the endpoint of the ray.
(Point Plotting Theorem)
7. If two lines are cut by a transversal such
that a pair of alternate interior angles are
congruent, then the lines are parallel.
9. CPCTC- Corresponding Parts of Congruent
Triangles are Congruent
16. Property of Parallelogram
18. Multiplication Property of Equality (17)
1
๐ด๐ถ
2
Example
ฬ…ฬ…ฬ…ฬ… ๐‘Ž๐‘›๐‘‘ ๐ต๐ถ
ฬ…ฬ…ฬ…ฬ… respectively.
In โˆ†๐ด๐ต๐ถ, D and E are the midpoints of ๐ด๐ต
B
D
A
E
C
MATH 9 QUARTER 3 WEEK 3
1. If DE = 13, then AC = 26.
4. If BC = 38, then BE = 19.
2. If BC = 38, then BE = 19.
5. If AC = 57, then DE = 28.5.
3. If AD = 11.5, then AB = 23.
6. If DE = x – 2 and AC = x + 10,
then DE = 12
Properties of Trapezoids
A trapezoid is a quadrilateral with exactly one pair of parallel sides.
The parallel sides are the called the bases. A trapezoid has two pairs of base angles.
The base angles of a trapezoid are two consecutive angles whose common side is a base.
The nonparallel sides are called the legs of the trapezoid. If the legs of a trapezoid are
congruent, then the trapezoid is an isosceles trapezoid.
Theorems on Trapezoid
The Midsegment Theorem. The median of a trapezoid is parallel to each base
and its length is one half the sum of the lengths of the bases.
Look at the proof of the theorem and see how the statements flow to arrive at the
conclusion.
A
B
Given: Trapezoid ABCD with median PQ
ฬ…ฬ…ฬ…ฬ… โˆฅ ๐ด๐ต
ฬ…ฬ…ฬ…ฬ… || ๐ท๐ถ
ฬ…ฬ…ฬ…ฬ… and ๐‘ƒ๐‘„ = 1 (๐ท๐ถ + ๐ด๐ต)
Prove: ๐‘ƒ๐‘„
2
P
Q
D
C
E
Proof:
Statements
Reasons
ฬ…ฬ…ฬ…ฬ…
1. Trapezoid ๐ด๐ต๐ถ๐ท with median ๐‘ƒ๐‘„
1. Given
2. Let ฬ…ฬ…ฬ…ฬ…
๐ด๐‘„ and ฬ…ฬ…ฬ…ฬ…
๐ท๐ถ be extended and
meet at E.
3. ฬ…ฬ…ฬ…ฬ…
๐ด๐ต || ฬ…ฬ…ฬ…ฬ…
๐ท๐ถ
2. The Line Postulate at E
ฬ…ฬ…ฬ…ฬ… ≅ ๐ถ๐‘„
ฬ…ฬ…ฬ…ฬ…
4. ๐ต๐‘„
4. Definition of median of a trapezoid
5. ∠๐ด๐ต๐‘„ ≅ ∠๐ธ๐ถ๐‘„
5. If two parallel lines are cut by a
transversal, then the alternate interior
angles are congruent.
6. ∠๐ต๐‘„๐ด ≅ ∠๐ถ๐‘„๐ธ
6. Vertical angles are congruent.
7. โˆ†๐ต๐‘„๐ด ≅ โˆ†๐ถ๐‘„๐ธ
ฬ…ฬ…ฬ…ฬ… ≅ ๐ธ๐ถ
ฬ…ฬ…ฬ…ฬ… , ๐ด๐‘„
ฬ…ฬ…ฬ…ฬ… ≅ ฬ…ฬ…ฬ…ฬ…
8. ๐ด๐ต
๐ธ๐‘„
7. ASA Postulate (4,5 & 6)
ฬ…ฬ…ฬ…ฬ… || ๐ท๐ธ
ฬ…ฬ…ฬ…ฬ… and ๐‘ƒ๐‘„ =
9. ๐‘ƒ๐‘„
3. Definition of a trapezoid
8. CPCTC- Corresponding Parts of
Congruent Triangles are Congruent
1
๐ท๐ธ
2
9. The Midline Theorem
10. ฬ…ฬ…ฬ…ฬ…
๐‘ƒ๐‘„ || ฬ…ฬ…ฬ…ฬ…
๐ด๐ต
10. A line parallel to one of two parallel line
is parallel to the other line.
11. ๐ท๐ธ = ๐ท๐ถ + ๐ธ๐ถ
11. Definition of Betweenness
12. ๐ด๐ต = ๐ธ๐ถ
12. Definition of congruent segments
13. ๐ท๐ธ = ๐ท๐ถ + ๐ด๐ต
13. Substitution (11 &12)
14. ๐‘ƒ๐‘„ =
1
(๐ท๐ถ
2
+ ๐ด๐ต)
14. Substitution (9 & 13)
Consider the following examples, see how the theorem is used to solve the given
problems.
Q
P
12
Example 1
1. In the figure, ฬ…ฬ…ฬ…ฬ…ฬ…
๐‘€๐‘ is the median of trapezoid PQRS.
M
N
Find MN.
Solution:
R
S
28
MATH 9 QUARTER 3 WEEK 3
1
By Midsegment Theorem
1
2
Substitution
๐‘€๐‘ = 2 (๐‘ƒ๐‘„ + ๐‘†๐‘…)
๐‘€๐‘ = (12 + 28)
๐‘ด๐‘ต = ๐Ÿ๐ŸŽ units
Example 2
ฬ…ฬ…ฬ…ฬ… is the median of trapezoid LMNO.
In the figure, ๐‘ƒ๐‘„
Find x, LM, and ON.
Solution:
1
P
By Midsegment Theorem
๐‘ƒ๐‘„ = 2 (๐ฟ๐‘€ + ๐‘‚๐‘)
1
25 = [(3๐‘ฅ + 2) + (4๐‘ฅ − 1)]
2
Substitution
4x-1
๐‘‚๐‘ = 3๐‘ฅ + 2
๐‘‚๐‘ = 3(7) + 2
๐‘‚๐‘ = 21 + 2
๐‘ถ๐‘ต = ๐Ÿ๐Ÿ‘ ๐’–๐’๐’Š๐’•๐’”
Theorems on Isosceles Trapezoid
Isosceles trapezoids have certain properties that you need to learn to have a
better understanding of its functions. Go through and study the proof of each theorem
on isosceles trapezoid.
Theorem: The base angles of an isosceles trapezoid are congruent.
Given: ABCD is an isosceles trapezoid
A
B
Prove: ∠๐ท ≅ ∠๐ถ
D
Proof:
Statements
E
F
C
Reasons
1. ABCD is an isosceles trapezoid
ฬ…ฬ…ฬ…ฬ… ≅ ๐ต๐ถ
ฬ…ฬ…ฬ…ฬ…
2. ๐ด๐ท
1. Given
3. Draw ๐ด๐ธ ⊥ ๐ท๐ถ and ๐ต๐น ⊥ ๐ท๐ถ
3. There is exactly one perpendicular
from a point to a line.
ฬ…ฬ…ฬ…ฬ… ≅ ๐ต๐น
ฬ…ฬ…ฬ…ฬ…
4. ๐ด๐ธ
4. Parallel lines are everywhere
equidistant.
5. ∠๐ด๐ธ๐ท ๐‘Ž๐‘›๐‘‘ ∠๐ต๐น๐ถ are right angles.
5. Definition of perpendicularity
6. โˆ†๐ด๐ธ๐ท ๐‘Ž๐‘›๐‘‘ โˆ†๐ต๐น๐ถ are right triangles
6. Definition of right triangles
7. โˆ†๐ด๐ธ๐ท ≅ โˆ†๐ต๐น๐ถ
7. Hypotenuse-Leg Theorem
8. ∠๐ท ≅ ∠๐ถ
8. CPCTC
2. Definition of Isosceles Trapezoid
Theorem: Opposite angles of an isosceles trapezoid are supplementary.
Given: Isosceles Trapezoid MASK
Prove: ∠๐ด ๐‘Ž๐‘›๐‘‘ ∠๐พ are supplementary
∠๐‘€ ๐‘Ž๐‘›๐‘‘ ∠๐‘† are supplementary
Proof:
Statements
1. Isosceles Trapezoid MASK
MATH 9 QUARTER 3 WEEK 3
Reasons
1. Given
M
Q
O
50 = 7๐‘ฅ + 1
7๐‘ฅ = 50 − 1
7๐‘ฅ = 49
๐‘ฅ=7
Find the measure of ๐ฟ๐‘€ and ๐‘‚๐‘
๐ฟ๐‘€ = 4๐‘ฅ − 1
๐ฟ๐‘€ = 4(7) − 1
๐ฟ๐‘€ = 28 − 1
๐‘ณ๐‘ด = ๐Ÿ๐Ÿ• ๐’–๐’๐’Š๐’•๐’”
3x+2
L
N
2. ∠๐‘€ ≅ ∠๐พ , ∠๐ด ≅ ∠๐‘†
2. An isosceles trapezoid has congruent base
angles.
ฬ…ฬ…ฬ…ฬ… || ๐‘€๐พ
ฬ…ฬ…ฬ…ฬ…ฬ…
3. ๐ด๐‘†
3. Definition of trapezoid
4. ∠๐‘€ ๐‘Ž๐‘›๐‘‘ ∠๐ด are supplementary
∠๐‘† ๐‘Ž๐‘›๐‘‘ ∠๐พ are supplementary
4. If two parallel lines are cut by a transversal,
the interior angles on the same side of
transversal are supplementary.
5. ∠๐พ ๐‘Ž๐‘›๐‘‘ ∠๐ด are supplementary
∠๐‘† ๐‘Ž๐‘›๐‘‘ ∠๐‘€ are supplementary
5. Substitution (4 & 2)
Look at the example. See how the theorem is used to solve the given problem.
Example
Find the measure of each angle in the given isosceles trapezoid.
Solution:
๐’Ž∠๐‘ต = ๐Ÿ–๐Ÿ°
Base angles of an isosceles trapezoid are congruent.
๐‘š∠๐ถ = 180° − 82°
Opposite angles of an isosceles trapezoid are supplementary.
๐’Ž∠๐‘ช = ๐Ÿ—๐Ÿ–
Since base angles of an isosceles trapezoid are congruent, then ๐’Ž∠๐‘ถ = ๐Ÿ—๐Ÿ–.
Theorem: The diagonals of an isosceles trapezoid are congruent.
A
B
Given: ABCD is an isosceles trapezoid
ฬ…ฬ…ฬ…ฬ… ≅ ๐ต๐ท
ฬ…ฬ…ฬ…ฬ…
Prove: ๐ด๐ถ
C
D
Proof:
Statements
Reasons
1. Isosceles Trapezoid ABCD where
ฬ…ฬ…ฬ…ฬ…
๐ด๐ท ≅ ฬ…ฬ…ฬ…ฬ…
๐ต๐ถ and ฬ…ฬ…ฬ…ฬ…
๐ด๐ต โˆฅ ฬ…ฬ…ฬ…ฬ…
๐ถ๐ท
1. Given
2. ∠๐ท ≅ ∠๐ถ
2. The base angles of an isosceles
trapezoid are congruent.
3. ฬ…ฬ…ฬ…ฬ…
๐ท๐ถ ≅ ฬ…ฬ…ฬ…ฬ…
๐ท๐ถ
3. Reflexive Property
4. โˆ†๐ด๐ท๐ถ ≅ โˆ†๐ต๐ถ๐ท
4. SAS Postulate – If 2 sides and the
included angle of one triangle are
congruent to the corresponding part of
another triangle, the triangles are
congruent.
ฬ…ฬ…ฬ…ฬ… ≅ ๐ต๐ท
ฬ…ฬ…ฬ…ฬ…
5. ๐ด๐ถ
5. CPCTC
Look at the example. See how the theorems are used to solve for the measure of
the median, diagonals and angles of the given trapezoid.
Example
Given isosceles trapezoid GRAB whose median is ED, diagonals GA and RB,
๐‘š∠๐ต๐บ๐‘… = 111°, ๐บ๐ด = 63 ๐‘๐‘š and ๐บ๐ต = 18 ๐‘๐‘š. Find EB, RB, ED, ๐‘š∠๐บ๐ต๐ด and ๐‘š∠๐‘…๐ด๐ต.
45 cm.
G
R
E
B
D
67 cm
Solve for EB (Def. of median of a trapezoid)
๐ธ๐ต =
๐ธ๐ต =
1
๐บ๐ต
2
1
(18)
2
๐‘ฌ๐‘ฉ = ๐Ÿ— ๐’„๐’Ž
MATH 9 QUARTER 3 WEEK 3
A
Solve for RB (Diagonals are congruent)
ฬ…ฬ…ฬ…ฬ…
ฬ…ฬ…ฬ…ฬ… ≅ ๐บ๐ด
๐‘…๐ต
๐‘…๐ต = ๐บ๐ด
๐‘น๐‘ฉ = ๐Ÿ”๐Ÿ‘ ๐’„๐’Ž
Solve for ED (Midsegment Theorem)
1
๐ธ๐ท = (๐บ๐‘… + ๐ต๐ด)
2
1
๐ธ๐ท = (45 + 67)
2
1
๐ธ๐ท = (112)
2
๐‘ฌ๐‘ซ = ๐Ÿ“๐Ÿ” ๐’„๐’Ž
Solve for ๐‘š∠๐บ๐ต๐ด (Same side interior angles
are supplementary)
๐‘š∠๐บ๐ต๐ด = 180 – ๐‘š∠๐ต๐บ๐‘…
๐‘š∠๐บ๐ต๐ด = 180 − 111
๐’Ž∠๐‘ฎ๐‘ฉ๐‘จ = ๐Ÿ”๐Ÿ—
Solve for ๐‘š∠๐‘…๐ด๐ต (Base angles are congruent)
๐‘š∠๐‘…๐ด๐ต = ๐‘š∠๐บ๐ต๐ด
๐’Ž∠๐‘น๐‘จ๐‘ฉ = ๐Ÿ”๐Ÿ—
Properties of Kite
In this section, you will study about kite and its theorems.
A kite is a quadrilateral with two distinct pairs of equal adjacent sides.
Refer to the KITE JKLM, where ฬ…ฬ…ฬ…
๐ฝ๐พ ≅ ฬ…ฬ…ฬ…ฬ…
๐พ๐ฟ and ฬ…ฬ…ฬ…ฬ…
๐ฝ๐‘€ ≅ ฬ…ฬ…ฬ…ฬ…
๐‘€๐ฟ.
1.One of the diagonals divides the kite into two congruent triangles,
while the other diagonal divides the kite into two isosceles triangles.
• Diagonal ฬ…ฬ…ฬ…ฬ…ฬ…
๐พ๐‘€ divides the KITE JKLM into two congruent triangles โˆ†๐พ๐ฝ๐‘€ ≅ โˆ†๐พ๐ฟ๐‘€.
ฬ…ฬ…ฬ…
• Diagonal ๐ฝ๐ฟ divides the KITE JKLM into two isosceles triangles โˆ† ๐ฝ๐พ๐‘™ ๐‘Ž๐‘›๐‘‘ โˆ†๐ฝ๐‘€๐ฟ.
2. One of the diagonals is a bisector of the other diagonal.
ฬ…ฬ…ฬ….
• Diagonal ฬ…ฬ…ฬ…ฬ…ฬ…
๐พ๐‘€ bisect ฬ…ฬ…ฬ…
๐ฝ๐ฟ, therefore ฬ…ฬ…ฬ…
๐ฝ๐ถ ≅ ฬ…๐ถ๐ฟ
3. Only one pair of opposite angles is congruent.
• ∠ ๐‘€๐ฝ๐พ ≅ ∠๐‘€๐ฟ๐พ
4. One of the diagonals bisects the opposite angles of the kite.
• ∠ ๐ฝ๐พ๐‘€ ≅ ∠๐‘€๐พ๐ฟ and ∠ ๐ฝ๐‘€๐พ ≅ ∠๐ฟ๐‘€๐พ
Theorems on Kite
Theorem: The diagonals of a kite are perpendicular to each other.
C
ฬ…ฬ…ฬ…ฬ…
ฬ…ฬ…ฬ…ฬ…
ฬ…ฬ…ฬ…ฬ…
ฬ…ฬ…ฬ…ฬ…
Given: ABCD is a kite with ๐ต๐ถ ≅ ๐ต๐ด and ๐ท๐ถ ≅ ๐ท๐ด
Prove: ฬ…ฬ…ฬ…ฬ…
๐ต๐ท is the perpendicular bisector of ฬ…ฬ…ฬ…ฬ…
๐ด๐ถ
B
D
A
Proof:
Statements
ฬ…ฬ…ฬ…ฬ… ≅ ๐ต๐ด
ฬ…ฬ…ฬ…ฬ… and ๐ท๐ถ
ฬ…ฬ…ฬ…ฬ… ≅ ๐ท๐ด
ฬ…ฬ…ฬ…ฬ… 1. Given
1. ABCD is a kite with ๐ต๐ถ
Reasons
2. B and D lie on the perpendicular
bisector of AC
3. ฬ…ฬ…ฬ…ฬ…
๐ต๐ท is the perpendicular bisector of ฬ…ฬ…ฬ…ฬ…
๐ด๐ถ
2. Converse of the Perpendicular
Bisector Theorem
4. ๐ด๐ถ ⊥ ๐ต๐ท
4.Definition of perpendicular bisector.
3. Through any two points, there is
exactly one line.
Look at the example; see how the theorem is used to find the measure of the angles in
a kite.
Example: Find ๐‘š∠1, ๐‘š∠2, ๐‘Ž๐‘›๐‘‘ ๐‘š∠๐‘…๐ด๐ท in the kite DEAR. Given ๐‘š∠๐ธ๐ด๐ท = 37.
D
E
2
1
R
MATH 9 QUARTER 3 WEEK 3
37หš
A
Solution:
๐’Ž∠๐Ÿ = 90
๐‘š∠1 + ๐‘š∠2 + ๐‘š∠๐ธ๐ด๐ท = 180
Diagonals of a kite are perpendicular
The sum of the measures of the interior
angles of a triangle is 180.
Substitution
Simplify
Addition Property of Equality
90 + ๐‘š∠2 + 37 = 180
๐‘š∠2 + 127 = 180
๐’Ž∠๐Ÿ = 53
Since โˆ†๐ท๐ธ๐ด ≅ โˆ†๐ท๐‘…๐ด by SSS Postulate, then ∠๐ธ๐ด๐ท ≅ ∠๐‘…๐ด๐ท by CPCTC.
Thus, ๐’Ž∠๐‘น๐‘จ๐‘ซ = 37.
Theorem: The area of a kite is half the product of the lengths of its diagonals.
P
Given: Kite ROPE
O
1
Prove: Area of kite ROPE = 2 (๐‘‚๐ธ)(๐‘ƒ๐‘…)
W
E
R
Proof:
Statements
Reasons
1. Kite ROPE
1. Given
2. ๐‘‚๐ธ ⊥ ๐‘ƒ๐‘…
2. The diagonals of a kite are
perpendicular to each other.
3. Area of kite ROPE = Area of โˆ†๐‘‚๐‘ƒ๐ธ + Area of โˆ†๐‘‚๐‘…๐ธ
3. Area Addition Postulate
4. Area Formula for Triangles
1
4. Area of โˆ†๐‘‚๐‘ƒ๐ธ = 2 (๐‘‚๐ธ)(๐‘ƒ๐‘Š)
1
2
Area of โˆ†๐‘‚๐‘…๐ธ = (๐‘‚๐ธ)(๐‘Š๐‘…)
1
5. Substitution Property
1
5. Area of Kite ROPE = 2 (๐‘‚๐ธ)(๐‘ƒ๐‘Š) +2 (๐‘‚๐ธ)(๐‘Š๐‘…)
6. Area of Kite ROPE = 2 (๐‘‚๐ธ)(๐‘ƒ๐‘Š + ๐‘Š๐‘…)
6. Distributive Property (5)
7. PW + WR = PR
7. Segment Addition Postulate
1
8. Area of Kite ROPE =
8. Substitution Property (6 & 7)
1
(๐‘‚๐ธ)(๐‘ƒ๐‘…)
2
Look at the example; see how the theorem is used to solve the given problems.
Example
1. Given: SA = 14 cm and TN = 6 cm. What is the area of the kite?
N
S
T
A
Solution:
๐ด๐‘Ÿ๐‘’๐‘Ž ๐‘œ๐‘“ ๐พ๐‘–๐‘ก๐‘’ ๐‘๐ด๐‘†๐‘‡ = 1/2 ( ๐‘๐‘Ÿ๐‘œ๐‘‘๐‘ข๐‘๐‘ก ๐‘œ๐‘“ ๐‘กโ„Ž๐‘’ ๐‘‘๐‘–๐‘Ž๐‘”๐‘œ๐‘›๐‘Ž๐‘™๐‘ )
1
= 2 (๐‘†๐ด)(๐‘‡๐‘)
1
= 2 (14 ๐‘๐‘š)(6 ๐‘๐‘š)
1
= 2 (84 ๐‘๐‘š2 )
๐‘จ๐’“๐’†๐’‚ ๐’๐’‡ ๐‘ฒ๐’Š๐’•๐’† ๐‘ต๐‘จ๐‘บ๐‘ป = ๐Ÿ’๐Ÿ ๐’„๐’Ž๐Ÿ
MATH 9 QUARTER 3 WEEK 3
Activities
Your goal in this section is to apply the properties and theorems on triangle,
trapezoids, and kites in doing the activities that follow.
Activity 1: Midline Theorem
O and P are the midpoints of ฬ…ฬ…ฬ…ฬ…
๐ฟ๐‘€and ฬ…ฬ…ฬ…ฬ…ฬ…
๐‘€๐‘, respectively. Complete each statement.
1.
2.
3.
4.
5.
If
If
If
If
If
M
OP = 18, then LN = _________.
LN = 34, then OP = _________.
O
P
MO = 12.5, then ML = __________.
L
N
MN = 29, then PN = __________.
OP = 3x – 2 and LN = 9x – 13, then x = _____, OP = _______ and LN = ______.
Activity 2: Median of a trapezoid
Using trapezoid LIKE with median ฬ…ฬ…ฬ…ฬ…
๐‘๐‘‚, find the indicated base/median.
1. If LI = 23 and EK = 36, find NO.
L
2. If LI= 15.5 and EK = 22.5, find NO.
N
3. If NO = 19 and LI = 13, find EK.
4. If NO = 21.5 and EK = 28, find LI.
5. If LI = 3x + 8, EK = 6x + 4 and NO = 24, find LI and EK.
I
O
E
K
Activity 3: Isosceles Trapezoid
A. Given isosceles trapezoid GRAB whose median is ED and diagonals GA and RB.
Determine the relationship between each of the following.
37 cm
ฬ…ฬ…ฬ…ฬ… and ๐ต๐ด
ฬ…ฬ…ฬ…ฬ…
1. ๐บ๐‘…
G
R
ฬ…ฬ…ฬ…ฬ… and ๐‘…๐ด
ฬ…ฬ…ฬ…ฬ…
2. ๐บ๐ต
E
D
3. ฬ…ฬ…ฬ…ฬ…
๐บ๐ด and ฬ…ฬ…ฬ…ฬ…
๐‘…๐ต
4. ฬ…ฬ…ฬ…ฬ…
๐ธ๐ท and ฬ…ฬ…ฬ…ฬ…
๐ต๐ด
B
A
52 cm
5. ∠๐ต and ∠๐ด
B. Given isosceles trapezoid GRAB whose median is ED and diagonals GA and RB,
๐‘š∠๐บ๐ต๐ด = 74° , ๐‘…๐ต = 56 ๐‘๐‘š and ๐บ๐ต = 21 ๐‘๐‘š .Find GE, GA, ED, ๐‘š∠๐ต๐บ๐‘… and ๐‘š∠๐‘…๐ด๐ต.
Activity 4: Kite
In kite MATH, ๐‘š∠๐‘‡๐ด๐‘† = 52° and๐‘š∠๐‘‡๐ป๐ด = 33°, MA = 10, MH = 17 and MT = 16
A
Find the measure of the following.
10
1. AT
2. TH
S 52หš
3. MS
4. AS (Hint: Pythagorean Theorem) M
5. ๐‘š∠๐‘€๐‘†๐ด
6. ๐‘š∠๐‘€๐ด๐ป
7. ๐‘š∠๐‘€๐ป๐ด
8. ๐‘š∠๐ด๐‘‡๐ป
9. ๐‘š∠๐‘€๐ด๐‘‡
10. ๐‘š∠๐‘€ + ๐‘š∠๐ด + ๐‘š∠๐‘‡ + ๐‘š∠๐ป
17
T
33หš
H
Remember
The Midline Theorem. The segment that joins the midpoints of two sides of a triangle
is parallel to the third side and half as long.
Theorem on Trapezoid
The Midsegment Theorem. The median of a trapezoid is parallel to each base and
its length is one half the sum of the lengths of the bases.
Theorems on Isosceles Trapezoid
โ— The base angles of an isosceles trapezoid are congruent.
MATH 9 QUARTER 3 WEEK 3
โ— Opposite angles of an isosceles trapezoid are supplementary.
โ— The diagonals of an isosceles trapezoid are congruent.
Theorems on Kite
โ— The diagonals of a kite are perpendicular to each other.
โ— The area of a kite is half the product of the lengths of its diagonals.
Check your Understanding
Draw out conclusions by applying the different theorems on trapezoid and kites.
1. In an isosceles trapezoid MARE, where (MA) ฬ… โˆฅ (ER) ฬ…, what is the relationship
between ∠M and ∠A? ∠E and ∠R? Explain.
2. WXYZ is an isosceles trapezoid, how do you compare (WY) ฬ… and (XZ) ฬ…? Why?
3. A and B are the midpoints of the legs (TQ) ฬ… and (SR ) ฬ… respectively of trapezoid
QRST, how would you find the measure of (AB) ฬ…? Why?
4. A and B are the midpoints of the legs TQ and SR of trapezoid QRST, what is the
relationship?
between AB and QR? AB and TS? Explain.
5. In trapezoid ABCD, if AC = BD, what can you say about trapezoid ABCD? Why is
that so?
6. In kite RSTV. RS = RV and TS = TV. What can you conclude about โˆ†RTV and โˆ†RTS
? Why?
Post-test
Direction: Choose the letter of the correct answer.
1. In the figure at the right, DE is the midline of โˆ†๐ด๐ต๐ถ and AC = 12 cm. What is the
length of DE?
B
a. 6 cm
b. 8 cm
D
E
c. 12 cm
d. 24 cm
A
C
2. What is true about an isosceles trapezoid?
a. It has exactly one pair of parallel sides.
b. It has congruent legs.
c. It has congruent base angles.
d. All of the above.
3. In the figure at the right, PQRS is an isosceles trapezoid.
If ๐‘š∠๐‘ƒ = 105°. What is the measure of ∠๐‘…?
a.
b.
c.
d.
75°
85°
105°
180°
P
S
105หš
Q
R
4. In the figure at the right PQ = 16cm and SR = 24 cm.
P
ฬ…ฬ…ฬ…ฬ…?
Q
What is the measurement of ๐‘‡๐‘ˆ
a. 8 cm
T
U
b. 18 cm
c. 20 cm
S
R
d. 40 cm
5. What is the length of the diagonal of a kite whose area is 176 sq.cm and the other
diagonal is 16 cm long?
a. 22 cm
b. 24 cm
c. 26 cm
d. 28 cm
MATH 9 QUARTER 3 WEEK 3
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