NEW ERA UNIVERSITY
9 Central Ave, New Era, Quezon City, 1107 Metro Manila
Department of Architecture and Engineering
CE 213 – 18
ENGINEERING UTILITIES
SCHEDULE: TUESDAY / 10: 00 AM – 1:00 PM
ACUZAR, JUDEL JHOANNA MARIE G.
2BSCE-1
January 12, 2021
QUIZ # 3
A. FROM THE FOLLOWING FIGURE, FIND THE MATERIALS REQUIRED FOR ITS CONSTRUCTION
FIGURE
1
2.00
M
3.00
M
4.00
M
4.50
M
C
1
C
3
C
2
FLOOR
LINE
CHB
FOOTING
4.00
M
DETAILS :
2.50
M
C
4
11.00 M
C
5
3.00 M
0.50
M
5.00
M
A. CHB SIZE = 15 X 20 X 40
CHB FOOTING: THICKNESS =0.20 m WIDTH = 0.30 m
B. COLUMNS
COLUMN LENGTH
C1
C2
C3
C4
C5
5.0
9.0
11.0
9.0
3.5
FOOTINGS
WIDTH LENGTH
0.50
0.60
0.50
0.60
0.50
0.60
0.50
0.60
0.50
0.60
THICKNESS
0.25
0.25
0.25
0.25
0.25
C. PLASTERING BOTH SIDES OF THE FIREWALL : THICKNESS = 12 mm
January 12, 2021
1
NEW ERA UNIVERSITY
9 Central Ave, New Era, Quezon City, 1107 Metro Manila
Department of Architecture and Engineering
REQUIREMENTS:
1. Compute the total quantity of CHB and its Mortar : cement and sand ,
Class B Mixture
2. Compute the total Concrete for CHB footing : Cement, Gravel and
Sand. Class B mixture.
3. Compute the total Concrete for the columns and
footings. Class B mixture Cement, gravel, and sand.
4. Compute for the total cement and sand for the plastering works.
TOTAL QUANTITY OF CHB AND ITS MORTAR: CEMENT AND SAND, CLASS B MIXTURE
•
SOLVING FOR TOTAL QUANTITY OF CHB
➢ Knowing the total area
𝑨𝒓𝒆𝒂 𝑨:
4𝑚
𝑨 = 4𝑚 ∗ 5𝑚
𝑨 = 20 𝑠𝑞. 𝑚.
5𝑚
𝑨𝒓𝒆𝒂 𝑩:
𝑨 = (9𝑚 + 11𝑚/2) ∗ 11𝑚
11𝑚
9𝑚
𝑨 = 110 𝑠𝑞. 𝑚.
11𝑚
𝑨𝒓𝒆𝒂 𝑪:
6𝑚
3.5𝑚
𝑨 = (6𝑚 + 3.5𝑚/2) ∗ 5𝑚
𝑨 = 23.75𝑠𝑞. 𝑚.
5𝑚
𝑺𝒖𝒎𝒎𝒂𝒕𝒊𝒐𝒏 𝒐𝒇 𝑨𝒓𝒆𝒂:
𝟐𝟎 𝒔𝒒. 𝒎. +𝟏𝟏𝟎 𝒔𝒒. 𝒎. +𝟐𝟑. 𝟕𝟓𝒔𝒒. 𝒎
𝑨𝒓𝒆𝒂 = 𝟏𝟓𝟑. 𝟕𝟓 𝒔𝒒. 𝒎.
January 12, 2021
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NEW ERA UNIVERSITY
9 Central Ave, New Era, Quezon City, 1107 Metro Manila
Department of Architecture and Engineering
Getting Total Quantity of CHB:
1 sq. m = 12.5 CHB
153.75 sq. m * 12.5 CHB
CHB= 1921.875 pieces or 1922 pieces
Getting Total Quantity of Mortar:
1 sq.m = 1.018 bags oof cement
153.75 sq. m * 1.018 bags of cement
Cement = 156.5175 or 157 bags of cement
Getting Total Quantity of Mortar:
1 sq. m = 0.0844 cu. m
153.75 sq. m * 0.844 cu. m
Sand = 12.9765 cu. m or 13 cu. m of sand
Getting total concrete of CHB footing (Class B mixture):
0.20m * 20m * 0.30m = 1.2 cu.m
1.2 cu. m * 7.5 = 9 bags of cement
1.2 cu. m * 0.5 = 0.6 cu.m of sand
1.2 cu. m * 1.0 = 1.2 cu.m of gravel
January 12, 2021
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NEW ERA UNIVERSITY
9 Central Ave, New Era, Quezon City, 1107 Metro Manila
Department of Architecture and Engineering
Getting total concrete of columns and footing (Class B mixture):
C1= 0.60 * 0.60 * 5 = 1.8 cu.m
C2= 0.60 * 0.60 * 9 = 3.24 cu.m
C3= 0.60 * 0.60 * 11= 3.96 cu.m
C4= 0.60 * 0.60 * 9 = 3.24 cu.m
C5= 0.60 * 0.60 * 3.5 = 1.26 cu.m
Volume for posts
V= c1 + c2 + c3 + c4 +c5 = 13.5 cu. m
Volume for footings
V= 0.60 * 0.60 * 0.25 = 0.09 cu.m *5
V= 0.45 cu.m
Summation of volume
V= 13.5 + 0.45 = 13.95 cu.m
Volume of concrete:
13.95 * 7.5 = 104.625 or 105 bags of cement
13.95 * 0.5 = 6.975 or 7 cu.m of sand
13.95 * 1.0 = 13.95 cu. m of gravel
Getting total cement and sand for plastering works ( Class B mixture):
CLASS B = 1:3
12mm = 0.144
153.75 * 0.144 = 22.14 or 22 bags of cement
153.75 * 0.012 = 1.845 or 2 cu. m of sand
January 12, 2021
4
NEW ERA UNIVERSITY
9 Central Ave, New Era, Quezon City, 1107 Metro Manila
Department of Architecture and Engineering
January 12, 2021
5