Uploaded by Hari Thakur

A pn junction diode at 25oC carries a current of 100 mA when the diode voltage is 0

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A pn junction diode at 25oC carries a current of 100 mA when the diode voltage is 0.5V. what is
the reverse saturation current.
soln
we have Id = Io(e38.9Vd - 1)
100∗10−3
or, Io = (𝑒 38.9∗0.5 −1) = 3.5 * 10-10
therefore,
Io = 3.5*10-10 amp
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