ME 475/675 Introduction to Combustion

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ME 475/675 Introduction to
Combustion
Lecture 20
Chapter 5 Some Important Chemical Mechanisms, 𝐻2 − 𝑂2 , CO
oxidation, Oxidation of Hydrocarbons, Global reaction rates
Announcements
• HW 7, Due Monday, 10/12/15
• College Distinguished Lecture
• Tesla’s JB Straubel to speak about Nevada’s clean energy future
• Sunday, October 11, 2015
• 5 pm posters; 6 pm Lecture
• http://www.unr.edu/nevada-today/news/2015/jb-straubel-to-speak-at-university
HW 7 hints
• X2
• H2 / O2 reaction
• Carefully apply steady state approximations
• 4.16:
• NO formation
• you’ve already done part A
𝑑 𝑁𝑂
•
= 2π‘˜1𝑓 𝑂 π‘’π‘ž 𝑁2 π‘’π‘ž , so 𝑁𝑂 = 2π‘˜1𝑓 𝑂 π‘’π‘ž 𝑁2
𝑑𝑑
• Use equilibrium constant to find backward rate
π‘’π‘ž 𝑑
• 4.18
• CO combustion
• Find characteristic time (can assume one reactant is much more plentiful than other)
• 4.19
• Use TPEQUIL to find equilibrium NO mole fraction for each conditions and compared to
the amount calculated at 10 ms. Follow directions
Chapter 5 Some Important Chemical Mechanisms
• Can be very complex, and is a topic of
current research, so changing with time
• The 𝐻2 − 𝑂2 system,
• Page 149-140 lists 20 reactions (40 when
reversed)
• Initiating, Reactions 1 and 2
• Create 𝐻 and 𝐻𝑂2 radicals
• Reactions involving O, H and OH:
• Chain reactions: 3-6 (create 𝑂𝐻, 𝑂 π‘Žπ‘›π‘‘ 𝐻)
• Chain terminating (ter-molecular) 7-10
• Reactions involving 𝐻𝑂2 (hydroperoxy) and
𝐻2 𝑂2 (hydrogen peroxide)
•
•
•
•
High pressure
Reactions 11-14 form 𝐻𝑂2 and then OH, O
Reactions 15-16 form 𝐻2 𝑂2 and O
Reactions 17-20 consume 𝐻2 𝑂2 , H and OH
Explosive limit dependence on pressure and pressure
Explosive
No Explosion, 11
destroys H atoms
Explosive
Radicals not
destroyed by walls
(reactions 3-6)
No Explosion, Walls
Destroy Radicals
CO oxidation
• This is important since hydrocarbon (𝐢π‘₯ 𝐻𝑦 ) combustion has 2 main steps
• 𝐢π‘₯ 𝐻𝑦 + 𝑂2 → 𝐢𝑂 + β‹―
• 𝐢𝑂 + 𝑂2 → 𝐢𝑂2 + β‹―
• This second step is “slow” unless 𝐻2 or 𝐻2 𝑂 are present (these molecules help produce 𝑂𝐻)
• If 𝐻2 𝑂 is the primary 𝐻 containing species
•
•
•
•
𝐢𝑂 + 𝑂2 → 𝐢𝑂2 + 𝑂
𝑂 + 𝐻2 𝑂 → 𝑂𝐻 + 𝑂𝐻
𝐢𝑂 + 𝑂𝐻 → 𝐢𝑂2 + 𝐻
𝐻 + 𝑂2 → 𝑂𝐻 + 𝑂
(slow but produces needed 𝑂, initiator of chain)
(produces needed 𝑂𝐻)
(key producer of 𝐢𝑂2 , needs 𝑂𝐻)
(produces more 𝑂𝐻)
• If 𝐻2 is present
• 𝑂 + 𝐻2 → 𝑂𝐻 + 𝐻
• 𝑂𝐻 + 𝐻2 → 𝐻2 𝑂 + 𝐻 (These lead to 𝐻𝑂2 formation, see 𝐻2 − 𝑂2 system)
• 𝐢𝑂 + 𝐻𝑂2 → 𝐢𝑂2 + 𝑂𝐻
Oxidation of Hydrocarbons
• Alkanes (or Paraffins)
• Saturated, straight-chain or branching-chain, singlebonded hydrocarbons, 𝐢𝑛 𝐻2𝑛+2
• Discuss Higher Alkanes 𝑛 ≥ 3
• Discuss 𝑛 = 1 and 2 (methane 𝐢𝐻4 , ethane 𝐢2 𝐻6 ), later
• Three step process
• 𝑂 π‘Žπ‘›π‘‘ 𝐻 attach fuel (remove H from fuel)
• Produces Alkenes (𝐢𝑛 𝐻2𝑛 , double carbon bonds) 𝐻 and water
• Alkenes oxidize
• Produces 𝐢𝑂 π‘Žπ‘›π‘‘ 𝐻2 (all is converted to Water)
• 𝐢𝑂 burns (𝐢𝑂 + 𝑂𝐻 → 𝐢𝑂2 + 𝐻 )
• Nearly all the heat release occurs in this step
Mole Fraction and Temperature versus Location (time)
• Propane 𝐢3 𝐻8 in air
• 𝐢3 𝐻8 mole fraction decreases with
distance (time)
• Alkenes (𝐢3 𝐻6 , 𝐢2 𝐻4 ), 𝐻2 and CO
increase with distance, reach a
maximum and drop off
• The temperature rises significantly at
locations where the CO is being
consumed (heat release) and 𝐢𝑂2 is
being produced
• Minor species (some oxygenated)
increase then decrease
More detailed 8-step process (I. Glassman)
1. Break C-C bond (weaker than C-H bonds)
1. 𝐢3 𝐻8 + 𝑀 → 𝐢2 𝐻5 + 𝐢𝐻3 + 𝑀
2. Create alkenes (olifins?) by H-atom abstraction
1. 𝐢2 𝐻5 + 𝑀 → 𝐢2 𝐻4 + 𝐻 + 𝑀
2.
𝐢𝐻3 + 𝑀 → 𝐢𝐻2 + 𝐻 + 𝑀
3. 𝐻 atoms help produce pool of radicals
1. 𝐻 + 𝑂2 → 𝑂𝐻 + 𝑂
4. Radicals attack fuel
1. 𝐢3 𝐻8 + 𝑂𝐻 → 𝐢3 𝐻7 + 𝐻2 𝑂
2. 𝐢3 𝐻8 + 𝐻 → 𝐢3 𝐻7 + 𝐻2
3. 𝐢3 𝐻8 + 𝑂 → 𝐢3 𝐻7 + 𝑂𝐻
5. New hydrocarbon radicals decay into alkenes via H-atom abstraction
1. 𝐢3 𝐻7 + 𝑀 → 𝐢3 𝐻6 + 𝐻 + 𝑀
2. Follows b-session rule
b-session rule
• Radical site:
• site of unpaired electron
• Strengthens the adjacent bond(s) but weakens the next bond
• The C-C or C-H bond that breaks will be one bond away from the radical site
• Two possibilities (as seen in temporal evolution two slides back):
• 𝐢3 𝐻7 + 𝑀 → 𝐢3 𝐻6 + 𝐻 + 𝑀 or
• 𝐢3 𝐻7 + 𝑀 → 𝐢2 𝐻4 + 𝐢𝐻3 + 𝑀
Continuation of 8-step process
6. O-atoms attach olefins from steps 2 and 5
1. 𝐢3 𝐻6 + 𝑂 → 𝐢2 𝐻5 + 𝐻𝐢𝑂 (formyl radical)
2. 𝐢3 𝐻6 + 𝑂 → 𝐢2 𝐻4 + 𝐻2 𝐢𝑂 (formaldehyde)
7. Methyl radicals (𝐢𝐻3 ), formaldehyde (𝐻2 𝐢𝑂) and Methylene (𝐢𝐻3 ) oxidize
1. Produces 𝐢𝑂
8. 𝐢𝑂 oxidizes to produce 𝐢𝑂2
Global and Quasi-global mechanisms rates
• Empirical
• 𝐢π‘₯ 𝐻𝑦 + π‘₯ +
𝑦
4
𝑂2
π‘˜πΊ
𝑦
2
π‘₯𝐢𝑂2 + 𝐻2 𝑂
• stoichiometric mixture with 𝑂2 , not air
•
𝑑 𝐢π‘₯ 𝐻𝑦
𝑑𝑑
= −𝐴𝑒π‘₯𝑝
πΈπ‘Ž 𝑅𝑒
𝑇
𝐢π‘₯ 𝐻𝑦
π‘š
𝑂2
𝑛
=
π‘”π‘šπ‘œπ‘™π‘’
π‘π‘š3 𝑠
• Page 157, Table 5.1: 𝐴, πΈπ‘Ž 𝑅𝑒 , π‘š π‘Žπ‘›π‘‘ 𝑛 for different fuels
• These values are based on flame speed data fit (Ch 8)
• In Table 5.1 units for 𝐴 =
• However, we often want 𝐴
•
1 π‘”π‘šπ‘œπ‘™π‘’ 1−π‘š−𝑛
𝑠
π‘π‘š3
• 𝐴
1 π‘˜π‘šπ‘œπ‘™π‘’ 1−π‘š−𝑛
𝑠
π‘š3
π‘”π‘šπ‘œπ‘™π‘’ 1−π‘š−𝑛
−
π‘š+𝑛
π‘”π‘šπ‘œπ‘™π‘’
π‘”π‘šπ‘œπ‘™π‘’
π‘π‘š3
=
π‘π‘š3 𝑠
π‘π‘š3
𝑠
1−π‘š−𝑛
1 π‘˜π‘šπ‘œπ‘™π‘’
in units of
𝑠
π‘š3
π‘˜π‘šπ‘œπ‘™π‘’
1000 π‘”π‘šπ‘œπ‘™π‘’
=𝐴
1−π‘š−𝑛
100 π‘π‘š 3
π‘š
1 π‘”π‘šπ‘œπ‘™π‘’ 1−π‘š−𝑛
𝑠
π‘π‘š3
=
1 π‘”π‘šπ‘œπ‘™π‘’ 1−π‘š−𝑛
𝑠
π‘π‘š3
Usually Want These Units
1000
1−π‘š−𝑛
=
1 π‘˜π‘šπ‘œπ‘™π‘’ 1−π‘š−𝑛
𝑠
π‘š3
10001−π‘š−𝑛 = 𝐴 𝑇𝑒π‘₯π‘‘π‘π‘œπ‘œπ‘˜ 10001−π‘š−𝑛
Given in Table 5.1, p. 157
Other empirical models
• Multistep models
• Text pp. 157-8
• Fuel Surrogates
• Text pp. 158-9
Methane Combustion, 𝐢𝐻4
• 325 steps, 53 species
• Text pp. 160-7
• Two pathways
• High temperature
• Low temp (< 1500 K)
Oxides of Nitrogen Formation
• Important contribution to air pollution
• 4 mechanisms
•
•
•
•
Thermal (Zeldovich): High temperature for a range of Φ
Fenimore (or prompt): Fuel Rich Φ > 1
𝑁2 𝑂-intermediate (very lean Φ < 1 and low temperature)
NNH: new
• Thermal
•
•
•
•
𝑂 + 𝑁2 → 𝑁𝑂 + 𝑁
𝑁 + 𝑂2 → 𝑁𝑂 + 𝑂
𝑁 + 𝑂𝐻 → 𝑁𝑂 + H
Coupled with fuel combustion through 𝑂2 , 𝑂 π‘Žπ‘›π‘‘ 𝑂𝐻.
Chapter 6 Coupling Chemical and Thermal Analysis of
Reacting systems
• Four simple systems, p 184
• Constant pressure and fixed Mass
Reactor
• Constituents (reactants and products,
𝑖), 𝑖 = 1,2, … 𝑁
• P and m constant
• Find as a function of time, t
• 𝑇 (energy)
• 𝑖 (species generation)
π‘š
• 𝑉 = , 𝑛𝑒𝑒𝑑 𝜌 (state, mixture)
𝜌
• Assume we know
𝑑𝑖
𝑑𝑑
= πœ”π‘– = 𝑓𝑛 𝑖
• From chemical Kinetics
• Energy 𝑄 − π‘Š =
𝑑𝑒
π‘š
𝑑𝑑
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