Section 2.2 Quadratic Functions

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Section 2.2
Quadratic Functions
Quadratic Functions
ο‚› Can
be written in two forms (π‘Ž ≠ 0). . .
𝑓 π‘₯ = π‘Ž(π‘₯ − β„Ž)2 +π‘˜
OR
𝑓 π‘₯ = π‘Žπ‘₯ 2 + 𝑏π‘₯ + 𝑐
Parabola
parabola/pΙ™ΛˆrabΙ™lΙ™/
axis of
symmetry
π‘₯=3
vertex
(3, -2)
Standard Form
𝒇 𝒙 = 𝒂(𝒙 − 𝒉)𝟐 +π’Œ, 𝒂 ≠ 𝟎
Vertex
(𝒉, π’Œ)
Axis of Symmetry
𝒙=𝒉
Opens Up
Opens Down
Minimum
Maximum
𝒂>𝟎
𝒂<𝟎
Tester
ο‚› Vertex?
ο‚› Max
ο‚› Axis
or min?
of Symmetry?
ο‚› Open
ο‚›π‘Ž
up or down?
positive or negative?
Example 1
𝑓 π‘₯ = −3 π‘₯ − 4
ο‚› vertex:
ο‚› max
or min
ο‚› opens
ο‚› line
up or opens down
of symmetry:
2
+7
Polynomial Form
𝒇 𝒙 = π’‚π’™πŸ + 𝒃𝒙 + 𝒄, 𝒂 ≠ 𝟎
−𝒃
−𝒃
,𝒇
πŸπ’‚
πŸπ’‚
Vertex
Axis of Symmetry
Opens Up
Opens Down
𝒙=
Minimum
Maximum
−𝒃
πŸπ’‚
𝒂>𝟎
𝒂<𝟎
i.e. to find the π‘₯coord.
of
the
−𝑏
vertex, find 2π‘Ž .
For 𝑦 , plug what
you get into the
equaion.
Example 2
𝑓 π‘₯ = −3π‘₯ 2 − 12π‘₯ + 5
ο‚› vertex:
ο‚› max
or min
ο‚› opens
ο‚› line
up or opens down
of symmetry:
Graphing Parabolas
1.
Find the vertex.
ο‚›
Standard Form – (β„Ž, π‘˜)
ο‚›
Polynomial Form – find
−𝑏
2π‘Ž
and plug it into the equation
2.
Find the 𝒙-intercepts by setting the equation equal to
0 and solving.
3.
Find the π’š-intercept by plugging in 0 for π‘₯.
4.
Plug in additional 𝒙-values if necessary.
5.
Plot points & connect the dots to form a smooth curve.
Example 3.0
Graph the function. State the axis of symmetry,
domain and range.
𝑦 = π‘₯−1
2
−9
Example 3.1
Graph the function. State the axis of symmetry,
domain and range.
𝑦−3= π‘₯−1
2
Example 4
Graph the function. State the axis of symmetry,
domain and range.
9
1
𝑦= − π‘₯−
4
2
2
Trip Down Memory Lane . . .
ο‚› Finding
the x-intercepts involves solving
quadratic equations.
ο‚› How
do you solve these?
ο‚›
π‘₯2 − 9 = 0
ο‚›
π‘₯ 2 − 7π‘₯ + 10 = 0
ο‚›
3π‘₯ 2 − 7π‘₯ + 2 = 0
ο‚›
π‘₯ 2 − π‘₯ + 21 = 0
Example 5
Graph the function. State the axis of symmetry,
domain and range.
𝑦 = π‘₯ 2 − 2π‘₯ − 8
Example 6
Graph the function. State the axis of symmetry,
domain and range.
𝑦 = π‘₯ 2 + 4π‘₯ − 1
Example 7
Determine without graphing.
𝑓 π‘₯ = −2π‘₯ 2 − 12π‘₯ + 3
a.
Does it have a min or a max?
b.
Min or Max:
c.
Domain and Range:
Applications of Quadratics
Two concepts often arise in word problems. . .
Quadratic Concept
Vertex
Examples of Applications
“Maximum height”
“Minimum area”
“when does the object hit
the ground”
π‘₯ −intercepts
“when will it be at a height
of zero”
Example 8
a)
How far does it travel?
b)
What is the maximum height?
c)
From what height was it released?
Example 9
Among all pairs of numbers whose sum is 22, find a
pair whose product is as large as possible. What is
the maximum product?
Example 10
Questions???
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