Math 308 Worksheet 5: Sections 7.2 - 7.3 18 & 20 July 2012 Solving a system of two equations in two unknowns Key Idea. Start with a system of two equations in two unknowns (1a) (1b) ax + by = 0 cx + dy = 0 . Notice that (x, y) = (0, 0) is always a solution of (1). We write 0 ∈ SOL(1) . 0 The point (b, −a) is a solution of the first equation (1a). It will also be a solution of the second equation (1b) if (2) 0 = cb − da . This tells us: the second equation (1b) is redundant if (2) holds. Remark. A second useful way to think about (2) is to rewrite it as −a/b = −c/d. This is precisely the statement that the two lines (1a) and (1b) have the same slope. Since they both have y–intersept 0, (2) is telling us: they are the same line! Case 1: 0 6= ad − bc. Then (x, y) = (0, 0) is the only solution to (1). We write 0 SOL(1) = . 0 Case 2: 0 = ad − bc. Then every point of the form (x, y) = (tb, −ta) = t(b, −a) is a solution of (1). We write b t∈R . SOL(1) = t −a Key Idea. The system (1) can be expressed as a single matrix equation: a b x ax + by 0 dfn (3) = = . c d y cx + dy 0 Write A = a b c d . Then 0 det(A) 6= 0 =⇒ SOL(3) = , 0 b det(A) = 0 =⇒ SOL(3) = t −a t∈R . Eigenvalue and Eigenspace Summary Definition. A vector V = v1 v2 is an eigenvector of the matrix A = a b c d , with eigenvalue λ if AV = λV . Remark. If V is an eigenvector with eigenvalue λ, then so is tV , for any number t ∈ R you choose. The eigenspace E(λ) is the set of all the eigenvectors of V . (In most cases, E(λ) is the line {tV | t ∈ R} spanned by V .) a−λ b To find the eigenvalues λ of A. Solve the equation 0 = det . c d−λ To find the eigenspaceE(λ). an eigenvalue Select λ, that you found above. To 0 a−λ b v1 v1 find the eigenspace, solve = for V = . 0 c d−λ v2 v2 Remark. Be aware that eigenvectors are not unique. When you solve for V , you will get a one-paramater space of solutions. This reflects the fact: if V is an eigenvector, then so is tV for any number t ∈ R you choose. Exercise 1. Compute the eigenvalues and eigenspaces for each of the matrices below. 5 4 1 0 −2 3 6 −5 2 3 −2 3 4 5 9 −5 2 2 4 −4 9 −3 −1 4 7 −3 1 1 3 1 . 3 1 −4 5 −4 −1 Exercise 2. Use the information 5 10 A = 1 2 and A 1 −2 −3 6 −14 2 = to determine the eigenvalues and eigenspaces of A. Exercise 3. Use the information 1 5 A = 3 15 and A 7 −1 to determine the eigenvalues and eigenspaces of A. Complex Eigenvalues = When the eigenvalues λ = α ± iβ of the matrix A are complex (β 6= 0), the eigenvectors will also be complex. If we write an eigenvector V of one eigenvalue α + iβ as r1 + is1 r1 s1 V = = + i = R + iS , r2 + is2 r2 s2 then R − iS is an eigenvector for the second eigenvalue α − iβ. Moreover, the eigenequation AV = λV tells us that AR = αR − βS Exercise 4. Use the information 3 6 6 A = − 2 4 3 and AS = βR + αS . and A 2 1 = 9 6 + 4 2 . to determine the eigenvalues and eigenspaces of A. Exercise 5. Use the information 5 15 2 A = − 1 3 4 and A 1 2 = 10 2 + 3 6 . to determine the eigenvalues and eigenspaces of A. Generalized Eigenvectors When the matrix A has only one eigenvalue λ, then we may be in one of two situations: λ 0 . Then every vector is an eigenCase 1. The first possibility is that A = 0 λ v1 vector; that is, the eigenspace is E(λ) = v1 , v2 ∈ R all vectors. v2 λ 0 Case 2. In this case, A 6= , and the eigenspace E(λ) is a single eigen-line. 0 λ In this case, we look for generalized eigenvectors. w1 Definition. If λ is an eigenvalue of A with eigenvector V , then W = is a w2 generalized eigenvector for the pair λ, A if AW = V + λW . To find generalized eigenvectors W for λ, V . Solve w1 for W = . w2 v1 v2 = a−λ b c d−λ w1 w2 Remark. Be aware that (like eigenvectors) generalized eigenvectors are not unique. When you solve for W you will get a one-paramater space of solutions. This reflects the fact: if W is a generalized eigenvector, then so is W + tV for any number t ∈ R you choose. Exercise 6. The third row of matrices in Exercise 1 consists of matrices with a single eigenvalue: compute generalized eigenvectors each matrix. Exercise 7. Use the information 3 6 A = 2 4 2 1 and A = 7 4 . to determine the eigenvalues, eigenspaces and generalized eigenvectors of A. Exercise 8. Use the information 5 15 = A 1 3 1 2 and A 8 7 = . to determine the eigenvalues, eigenspaces and generalized eigenvectors of A. Exercise 9. Use the information 2 1 A = 4 2 −2 0 and A 0 2 = . to determine the eigenvalues, eigenspaces and generalized eigenvectors of A. Exercise 10. Use the information 1 3 A = 12 −24 and A 1 2 = −3 −6 . to determine the eigenvalues, eigenspaces and generalized eigenvectors of A. Exercise 11. Use the information 7 0 A = 3 0 and A 4 0 = 7 3 . to determine the eigenvalues, eigenspaces and generalized eigenvectors of A. Homework. As part of your preparation for Quiz 3 (Wednesday, July 25) and the Final Exam (Tuesday, August 07), I recommend the following: (A) Section 7.2: Problems 22, 23, 25. (B) Section 7.3: Problems 16-18. Scholastic dishonesty. Copying work done by others, either in-class or out of class, is an act of scholastic dishonesty and will be prosecuted to the full extent allowed by University policy. Collaboration on assignments, either in-class or out-of-class, is forbidden unless permission to do so is granted by your instructor. For more information on university policies regarding scholastic dishonesty, see University Student Rules. Academic Integrity Statement. An Aggie does not lie, cheat or steal or tolerate those who do. Copyright policy. All printed materials disseminated in class or on the web are protected by Copyright laws. One xerox copy (or download from the web) is allowed for personal use. Multiple copies or sale of any of these materials is strictly prohibited. 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