UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS
GCE Ordinary Level
MARK SCHEME for the October/November 2010 question paper
for the guidance of teachers
4037 ADDITIONAL MATHEMATICS
4037/23
Paper 2, maximum raw mark 80
This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of
the examination. It shows the basis on which Examiners were instructed to award marks. It does not
indicate the details of the discussions that took place at an Examiners’ meeting before marking began,
which would have considered the acceptability of alternative answers.
Mark schemes must be read in conjunction with the question papers and the report on the
examination.
•
CIE will not enter into discussions or correspondence in connection with these mark schemes.
CIE is publishing the mark schemes for the October/November 2010 question papers for most IGCSE,
GCE Advanced Level and Advanced Subsidiary Level syllabuses and some Ordinary Level
syllabuses.
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Page 2
Mark Scheme: Teachers’ version
GCE O LEVEL – October/November 2010
Syllabus
4037
Paper
23
Mark Scheme Notes
Marks are of the following three types:
M
Method mark, awarded for a valid method applied to the problem. Method marks are
not lost for numerical errors, algebraic slips or errors in units. However, it is not
usually sufficient for a candidate just to indicate an intention of using some method or
just to quote a formula; the formula or idea must be applied to the specific problem in
hand, e.g. by substituting the relevant quantities into the formula. Correct application
of a formula without the formula being quoted obviously earns the M mark and in some
cases an M mark can be implied from a correct answer.
A
Accuracy mark, awarded for a correct answer or intermediate step correctly obtained.
Accuracy marks cannot be given unless the associated method mark is earned (or
implied).
B
Accuracy mark for a correct result or statement independent of method marks.
•
When a part of a question has two or more “method” steps, the M marks are generally
independent unless the scheme specifically says otherwise; and similarly when there are
several B marks allocated. The notation DM or DB (or dep*) is used to indicate that a
particular M or B mark is dependent on an earlier M or B (asterisked) mark in the scheme.
When two or more steps are run together by the candidate, the earlier marks are implied and
full credit is given.
•
The symbol √ implies that the A or B mark indicated is allowed for work correctly following
on from previously incorrect results. Otherwise, A or B marks are given for correct work
only. A and B marks are not given for fortuitously “correct” answers or results obtained from
incorrect working.
•
Note:
B2 or A2 means that the candidate can earn 2 or 0.
B2, 1, 0 means that the candidate can earn anything from 0 to 2.
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Page 3
Mark Scheme: Teachers’ version
GCE O LEVEL – October/November 2010
Syllabus
4037
Paper
23
The following abbreviations may be used in a mark scheme or used on the scripts:
AG
Answer Given on the question paper (so extra checking is needed to ensure that
the detailed working leading to the result is valid)
BOD
Benefit of Doubt (allowed when the validity of a solution may not be absolutely
clear)
CAO
Correct Answer Only (emphasising that no “follow through” from a previous error
is allowed)
ISW
Ignore Subsequent Working
MR
Misread
PA
Premature Approximation (resulting in basically correct work that is insufficiently
accurate)
SOS
See Other Solution (the candidate makes a better attempt at the same question)
Penalties
MR –1
A penalty of MR –1 is deducted from A or B marks when the data of a question or
part question are genuinely misread and the object and difficulty of the question
remain unaltered. In this case all A and B marks then become “follow through √ ”
marks. MR is not applied when the candidate misreads his own figures – this is
regarded as an error in accuracy.
OW –1,2 This is deducted from A or B marks when essential working is omitted.
PA –1
This is deducted from A or B marks in the case of premature approximation.
S –1
Occasionally used for persistent slackness – usually discussed at a meeting.
EX –1
Applied to A or B marks when extra solutions are offered to a particular equation.
Again, this is usually discussed at the meeting.
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Page 4
1
Mark Scheme: Teachers’ version
GCE O LEVEL – October/November 2010
Syllabus
4037
dy
−4
= k (x + 4)
dx
k = –30
M1
A1
dy
× ∂x with x = 6 and ∂x = p
dx
−3
p
–0.003p or
1000
Use ∂y =
2
Paper
23
M1
A1√
[4]
Integrate 3x2 – 6x
(y =)x3 – 3x2 (+ c)
M1
A1
Substitute x = 4, y = 22
y = x3 – 3x2 + 6
M1
A1
[4]
3
(a) (i) 4
B1
(ii) 3
B1
(iii) 5
B1
(b) (i) π or 180
B1
(ii) 6
B1
[5]
4
(i) 1 + 6x + 15x2 + 20x3
B2,1,0
(ii) Substitute x = p – p2
Multiply out brackets to obtain terms in p3. (–30 p3 + 20p3)
–10
M1
M1
A1
[5]
5
(a)
(4
− 15)
(b) (i) C
−1
=
B1+B1
1 4

2 − 2
5  or C −1 = − 1  − 4

− 3 
2 2
− 5
3 
(ii) X = C–1D evaluated
 17 12 


 − 9 − 8
B1+B1
M1
A1
[6]
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Page 5
6
Mark Scheme: Teachers’ version
GCE O LEVEL – October/November 2010
Syllabus
4037
Paper
23
(a)
B1
A
B
(b)
B1+B1
R
P
Q
(c) 24 – x + x + 18 – x + 3x = 50 or 24 + 18 – x + 3x = 50
Solve for x (4)
12
B1
M1
A1
[6]
7
Eliminate y (or x)
4x2 + 12x – 160 = 0 (or y2 + 18y – 88 = 0)
Factorise 3 term quadratic
x = 5 and –8 (or y = –22 and 4)
y = –22 and 4 (or x = 5 and –8)
Use Pythagoras
29.1 or 845 or 13 5
M1
A1
M1
A1
A1√
M1
A1
[7]
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Page 6
8
(i)
Mark Scheme: Teachers’ version
GCE O LEVEL – October/November 2010
(5 + 3 2 )
2
2
(ii)
Syllabus
4037
= 25 + 30 2 + 18 or 25 + 15 2 + 15 2 + 18
(43 + 30 2 ) = 2 (5 + 3 2 )
(
(iv)
A1
)
B1
1
5+3 2
B1
1
5−3 2
×
5+3 2 5−3 2
M1
5−3 2
7
alternative for last 3 marks
1
43 − 30 2
×
43 + 30 2 43 − 30 2
A1
(M1)
43 − 30 2
49
5−3 2
7
9
(i)
B1 AG
M1
6+5 2
(iii) 5 − 3 2
Paper
23
(A1)
(A1)
[7]
82 + 152
AO = 17
M1
A1
 17 2 + 17 2 − 30 2 

(ii) AOB = π − 2 arctan(815 ) or arccos

2
×
17
×
17


AOB = 2.16
(iii) Complete, correct plan with s = rθ
82.7
(iv) Complete, correct plan with A =
M1
A1
M1
A1
1 2
rθ
2
M1
432
A1
[8]
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Page 7
Mark Scheme: Teachers’ version
GCE O LEVEL – October/November 2010
Syllabus
4037
10 Use product rule
2xex + x2ex
Paper
23
M1
A1
Evaluate gradient of tangent at P
e + 2e = 3e
M1
A1
Equation tangent y – e = 3e(x – 1) or y = 3ex – 2e
At A, x = 0 ⇒ y = −2e or –5.44
M1
A1
Use m1m2 = –1, equation normal is y − e = −
1
(x − 1)
3e
At B, y = 0 ⇒ x = 3e 2 + 1 or 23.2
A1
A1
3
Area OAB = 3e + e or 63(.0) or 63.1
11 (i)
M1
[9]
AQ = 3b − a
M1
M1
A1
OX = OA + µ AQ
a + µ (3b − a )
(ii) BP = 2a − b
M1
M1
A1
OX = OB + λ BP
b + λ (2a − b )
1 − µ = 2λ 

(iii) Equate vectors and solve 
 3µ = 1 − λ 
µ = 0.2
λ = 0.4
M1
A1
A1
[9]
12E (i) Plot with (attempt at) linear scales
v
2
4
6
8
v2p 24.9
45.4 65.9
86.4
M1
A1
(ii) v2p = a + bv
Valid attempt at gradient
b = 10.2 to 10.3
a = 4 to 4.5
(iii) Attempt to rearrange to Y =
pv on y-axis
B1
M1
A1
B1
a
+ ...
v
M1
A1
(iv) Gradient is a
y intercept is b
A1
A1
[10]
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Page 8
Mark Scheme: Teachers’ version
GCE O LEVEL – October/November 2010
12O (i) Plot with (attempt at) linear scales
ln t
0.69
2.08
3.18
ln r
3.09
4.90
6.33
Syllabus
4037
Paper
23
M1
3.99
7.38
(ii) Gradient is 1.3
Intercept is 2.2
A1
B1
B1
ln r = 1.3ln t + 2.2
ln r = 1.3ln t + ln 9
ln r = ln t1.3 + ln 9
r = 9t1.3
M1
M1
M1
A1√
(iii) Gradient is 1.3
Intercept 0.95 or lg 9
B1√
B1√
[10]
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