Georgian Mathematical Journal Volume 10 (2003), Number 2, 363–379 ESTIMATES OF FOURIER COEFFICIENTS V. TSAGAREISHVILI Abstract. Some well-known properties of the trigonometric system as well as of the Haar and Welsh systems are generalized to general orthonormal systems. 2000 Mathematics Subject Classification: 42A16, 42C10. Key words and phrases: Orthonormal system, Fourier coefficients, modulus of continuity, bounded variation. 1. Introduction In the theory of functions an important place is occupied by generalization of properties of specific orthonormal series to general orthonormal systems. Here we note only some of the authors who have significant results concerning the mentioned problems: Marcinkiewicz [1], Stechkin [2], Olevskii [3], Bochkarev [4], [5], Mitiagin [6], Kashin [7], McLaughlin [8]. It was proved that in many cases some properties of the well-known orthogonal systems are typical for general orthogonal systems (see, e.g., [2], [3], [4], [5]). However, not all properties of the well-known orthogonal systems are extending on general orthogonal systems. Therefore, in order to obtain well-known results for general orthogonal systems, we need to impose specific conditions on the given system. 2. Auxiliary Notation and Results Let δ ∈ (0, 1]. If a function f ∈ C([0, 1]), then its modulus of continuity is defined as follows ω(δ, f ) = sup max |f (x) − f (x + h)|, |h|≤δ 0≤x≤1−h where 0 < h ≤ 1. If a function f ∈ L2 ([0, 1]), then the integral modulus of continuity has the form µZ 1−h ¶ 21 ω2 (δ, f ) = sup |f (x) − f (x + h)|2 dx . |h|≤δ 0 We say that a function f ∈ Lip α if ω(δ, f ) = O(δ α ) as δ → 0. Let (ϕn ) be an orthogonal system on [0, 1]. Then the Fourier coefficients with respect to (ϕn ) for the function f ∈ L([0, 1]) are defined as follows Z 1 cn (f ) = f (x)ϕn (x) dx, n = 1, 2, . . . . 0 c Heldermann Verlag www.heldermann.de ISSN 1072-947X / $8.00 / ° 364 V. TSAGAREISHVILI The best approximation with respect to the system (ϕn ) in the sense of L2 ([0, 1]) is defined by the following equality: ° ° n ° ° X ° ° En(2) (f ) = inf °f (x) − am ϕm (x)° . ° {am } ° m=1 2 If (ϕn ) is a complete system on [0, 1], then ! 21 Ã∞ X c2k (f ) . En(2) (f ) = k=n In the sequel we will denote by (ψn ) either one of the orthonormal systems of Haar or Walsh (see, e.g., [9, p. 53, 54]), or the trigonometric system. For these systems the following results are valid. They are important for our purpose. Theorem A. If Z1 cn (f ) = f (x)ψn (x) dx, 0 then the following ¡ ¡relations ¢¢ are valid: 1 a) cn (f ) = O ¡ω ¡n , f ¢¢for every f ∈ C([0, 1]); b) cn (f ) = O ω2 n1 , f for every f ∈ L2 ([0, 1]). Theorem B. For every function f ∈ L2 ([0, 1]) the relation µ µ ¶¶ 1 (2) En = O ω2 ,f n holds. The relation a) of Theorem A for the Haar system was proved by B. Golubov [10] and the relation b) was proved by P. Ul’yanov [11], for the Walsh system it was proved by Fine [12]. Theorem B for the Haar system was proved by Ul’yanov [11]. As to the trigonometric system, Theorems A and B are well-known (see, e.g., [13, p. 79]). It is well-known that Theorems A and B are not valid for general orthogonal systems. In fact, the following theorem holds. Theorem C. Let f be a function from L2 ([0, 1]) and (cn ) be an arbitrary sequence from `2 satisfying the condition Z 1 ∞ X 2 cn = f 2 (x) dx. n=1 0 Then there exists an orthonormal system (ϕn ) on [0, 1] such that Z 1 cn = f (x)ϕn (x) dx, n = 1, 2, . . . . 0 ESTIMATES OF FOURIER COEFFICIENTS 365 Theorem C is proved by A. Olevskii [3]. From this theorem follows that if f ∈ L2 ([0, 1]) and the numbers cn satisfy the conditions a) ∞ X Z c2n 1 = |cn | = +∞, n→∞ ω2 ( 1 , f ) n f 2 (x) dx and b) lim 0 n=1 then there exists an orthonormal system of functions (ϕn ) such that Z 1 cn = f (x)ϕn (x) dx, n = 1, 2, . . . . 0 Therefore there exists a function f ∈ L2 ([0, 1]) such that |cn (f )| = +∞. n→∞ ω2 ( 1 , f ) n lim The following propositions are valid (see [15]). Lemma 1. Let the function f ∈ L2 ([0, 1]) take finite values at every point of the interval [0, 1] and Φ ∈ L2 ([0, 1]). Then the following equality is valid: Z 1 0 µ ¶¶ Z i n−1 µ µ ¶ X n i i+1 f (x)Φ(x) dx = f Φ(x) dx −f n n 0 i=1 µ ¶¶ Z 1 n Z i µ X n i + Φ(x) dx + f (1) Φ(x) dx. f (x) − f i−1 n 0 i=1 n (1) Lemma 2. Let (ϕn ) be an orthonormal system of functions on [0, 1]. Let En denote the¡ set of¢the natural numbers i (i = 1, 2, . . . , n) for which there exists a point t ∈ i−1 , i such that n n Z Z t sign i−1 n ϕn (x) dx 6= sign 0 ϕn (x) dx. 0 Then the inequality ¯ µZ ¯ ¶ 21 ¯ 1 X ¯¯Z ni ¯ ϕ2n (x) dx ϕn (x) dx¯ ≤ ¯ ¯ ¯ 0 0 i∈En holds. 366 V. TSAGAREISHVILI 3. Main Results Let (an ) be a sequence of real numbers from `2 , Introduce the following notation: N +m X (m) PN (x) ≡ à eN ≡ ak ϕk (x), k=N ∞ X m = 1, 2, . . . , ! 21 c2k (f ) , k=N ¯ k ¯ ¯ ¯ N (m) ¯ HN ≡ sup PN (x) dx¯ , ¯ ¯ 0 ¯ m k=1 à ∞ ! 21 X hN ≡ a2k . N −1 ¯Z X k=N Theorem 1. Let f ∈ C([0, 1]) and (ϕn ) be an orthonormal system of functions R1 on [0, 1] satisfying ϕn (x) dx = 0, n = 1, 2, . . . . 0 Then the relation µ µ ¶¶ 1 eN = O ω ,f N holds if and only if the condition HN = O(hN ) for every sequence (ak ) ∈ `2 is fulfilled. Proof. Sufficiency. If cn (f ) = R1 f (x)ϕn (x)dx, then 0 N +m X c2k (f ) = k=N N +m X Z k=N Z 1 = f (x) 0 1 ck (f ) f (x)ϕk (x) dx 0 N +m X k=N Z 1 ck (f )ϕk (x) dx = 0 (m) f (x)PN (x) dx. Using the assertion of Lemma 1, we obtain ¶ µ ¶¶ Z i Z 1 N −1 µ µ X N i i+1 (m) (m) f (x)PN (x) dx = f PN (x) dx −f N N 0 0 i=1 µ ¶¶ i µ Z Z N 1 X N i (m) (m) + f (x) − f PN (x) dx + f (1) PN (x) dx. i−1 N 0 i=1 N (2) (3) ESTIMATES OF FOURIER COEFFICIENTS Estimate the right-hand side of equality (3). We have ¯ ¯ ¶ µ ¶¶ Z i −1 µ µ ¯N ¯ X N i i + 1 ¯ ¯ (m) PN (x) dx¯ f −f ¯ ¯ ¯ N N 0 i=1 ¯ ¯ ¶ µ ¶¯ ¯Z i N −1 ¯ µ ¯ X ¯ ¯ ¯ N (m) i i + 1 ¯ ¯ ¯ ≤ PN (x) dx¯ ¯ ¯f N − f ¯ ¯ ¯ N 0 i=1 ¯ ¯ ¶N µ ¶ µ −1 ¯Z i ¯ X 1 1 ¯ N (m) ¯ ,f , f hN . ≤ω PN (x) dx¯ ≤ O(1) ω ¯ ¯ 0 ¯ N N i=1 367 (4) Applying the Hölder inequality, we obtain ¯N −1 Z i µ ¯ µ ¶¶ ¯X N ¯ i ¯ ¯ (m) f (x) − f PN (x) dx¯ ¯ i−1 ¯ ¯ N i=1 N µ µ ¶N ¶ µZ 1 ³ −1 Z i ¯ ¯ ´2 ¶ 21 X N 1 1 ¯ (m) ¯ (m) ≤ω ,f ,f PN (x) dx ¯PN (x)¯ dx ≤ ω i−1 N N 0 i=1 N ! 21 µ ¶ ÃNX µ ¶ +m 1 1 2 ck (f ) = O(1)ω ,f ≤ O(1)ω , f eN . (5) N N k=N Finally, since ¯Z ¯ ¯ ¯ R1 ϕn (x) dx = 0, n = 1, 2, . . . , from (3), (4) and (5) we have 0 1 0 ¯ ¯ ¶ ¶ ¶ ¶ µ µ µ µ 1 1 , f eN + O ω , f eN ≤O ω N N µ µ ¶ ¶ 1 =O ω , f eN . N (m) f (x)PN (x) dx¯¯ Hence, applying (2), we get N +m X c2k (f ) µ µ ¶ ¶ 1 =O ω , f eN , N c2k (f ) µ µ ¶ ¶ 1 =O ω , f eN , N k=N i.e., ∞ X k=N From (6) we have à ∞ X k=N ! 21 c2k (f ) µ µ ¶¶ 1 =O ω ,f . N Sufficiency of the theorem is proved. Necessity. Let HN 6= O(hN ), i.e., HN lim = +∞. N hN (6) 368 V. TSAGAREISHVILI Therefore there exist a sequence (an ) ∈ `2 and natural numbers mN ↑ ∞ such that (m ) H N lim N = +∞, (7) N hN where ¯ ¯ N −1 ¯Z k ¯ X (mN ) ¯ N (mN ) ¯ HN = PN (x) dx¯ ¯ ¯ 0 ¯ k=1 and (m ) PN N (x) N +mN = X ak ϕk (x). k=N Consider the sequence of functions ¶ Z xµ Z u (mN ) sign PN (t) dt du, fN (x) = 0 Taking into account the condition obtain Z 1 0 N = 1, 2, . . . . (8) 0 R1 ϕn (x) dx = 0, n = 1, 2, . . . , from (1) we 0 (m ) fN (x)PN N (x) dx N −1 µ X µ ¶¶ Z i N i+1 (m ) = fN − fN PN N (x) dx N 0 i=1 ¶¶ µ i µ Z N X N 1 (m ) PN N (x) dx. (9) + fN (x) − fN i−1 N i=1 N i N ¶ µ Applying (8) we have ¯ ¯ µ ¶¶ N Z i µ ¯ ¯X N i (mN ) ¯ ¯ PN (x) dx¯ fN (x) − fN ¯ i−1 ¯ ¯ N i=1 N N Z i 1 X N ¯¯ (mN ) ¯¯ ≤ ¯PN (x)¯ dx N i=1 i−1 N 12 N +mN µZ 1 ³ ¶ 12 ´ X 2 1 1 (m ) a2k . PN N (x) dx = ≤ N N 0 k=N Taking into account the assertions of Lemma 2 and (8), we get µ ¶ µ ¶¶ Z i N −1 µ X N i i+1 (m ) PN N (x) dx fN − fN N N 0 i=1 µ µ ¶ µ ¶¶ Z i X N i i+1 (m ) = fN − fN PN N (x) dx N N 0 i∈FN \EN (10) ESTIMATES OF FOURIER COEFFICIENTS + Xµ i∈EN µ fN i N ¶ µ − fN i+1 N ¶¶ Z i N 0 (mN ) PN 369 (x) dx, where FN = {1, 2, . . . , N }. If i ∈ FN \ EN , then µ ¶ µ ¶ Z i+1 Z u N i i+1 (m ) fN − fN =− sign PN N (t) dt du i N N 0 N Z i N 1 (m ) =− sign PN N (t)dt. N 0 Therefore ¯ ¯ ¯ ¯ µ µ ¶ µ ¶¶ Z i X ¯ ¯ N i i+1 (mN ) ¯ fN − fN PN (x) dx¯¯ ¯ N N 0 ¯i∈FN \EN ¯ ¯Z i ¯ ¯ 1 X ¯¯ N (mN ) ¯ = PN (x) dx¯ . ¯ ¯ 0 ¯ N (11) (12) i∈FN \EN At last, as far as ¯ µ ¶ ¶¯ µ ¯ ¯ i + 1 i ¯< 1 ¯fN − f N ¯ N ¯ N N and, by virtue of Lemma 2, we have ¯ µZ ¯ ¯ ´2 ¶ 21 1³ X ¯¯Z Ni (m ) (mN ) ¯ N PN (x) dx¯ ≤ PN (x) dx ¯ ¯ ¯ 0 0 i∈EN 12 à ! 21 N +mN ∞ X X a2k ≤ a2k = ≡ hN . k=N N N = 1, 2, . . . . Using (12) and (15), we get ¯N −1 µ µ ¶ ¯ µ ¶¶ Z i ¯X ¯ N i i+1 (mN ) ¯ ¯ fN PN (x) dx¯ − fN ¯ ¯ ¯ N N 0 i=1 ¯Z i ¯ ¯Z i ¯ ¯ ¯ N ¯ X 1 X ¯¯ N (mN ) 1 (m ) ¯ ¯ ¯ ≥ PN (x) dx¯ − PN N (x) dx¯ ¯ ¯ ¯ 0 ¯ N ¯ 0 ¯ N ≥ 1 (mN ) hN H − . N N N (14) k=N Then, taking into account (13) and (14), we obtain ¯ ¯ µ ¶¶ Z i ¯X µ µ i ¶ ¯ N i+1 1 (mN ) ¯ ¯ fN − fN PN (x) dx¯ ≤ h , ¯ ¯ N N ¯ N N 0 i∈E i∈FN \EN (13) i∈EN (15) 370 V. TSAGAREISHVILI Hence due to (7) we have ¯1 ¯ ¯R ¯ (mN ) ¯ N ¯ fN (x)PN (x) dx¯¯ 0 hN and consequently lim (m ) H N hN ≥ N − , hN hN ¯ ¯1 ¯ ¯R (mN ) N ¯¯ fN (x)PN (x) dx¯¯ 0 hN n→∞ = +∞. (16) Further, since kfN kLip 1 = kfN kC + sup x,y |fN (x) − fN (y)| , |x − y| then from (8) it follows that kfN kLip 1 ≤ 2. (17) Finally, by virtue of the Banach–Steinhaus theorem (see (16) and (17)) there exists a function f0 ∈ Lip 1 such that ¯1 ¯ ¯R ¯ (mN ) N ¯¯ fN (x)PN (x) dx¯¯ 0 lim = +∞. (18) n→∞ hN As far as ¯Z ¯ ¯ ¯ ¯ ¯ ¯ ¯Z 1 ¯ N +mN X ¯ ¯ ¯ (mN ) f0 (x)PN (x) dx¯¯ = ¯¯ ak ϕk (x) dx¯¯ f0 (x) 0 ¯ ¯ 0 k=N ¯ ¯ ¯ ¯ ¯ ¯N +mN ¯N +mN Z 1 ¯ ¯ ¯ X ¯ X ¯ = ¯¯ ak f0 (x)ϕk (x) dx¯¯ = ¯¯ ak ck (f0 )¯¯ 0 ¯ k=N ¯ ¯ k=N ¯ 21 21 N +mN N +mN X X c2k (f0 ) < hN · eN , a2k ≤ 1 k=N k=N then taking into account that ω ¡1 N ¢ ¡ ¢ , f0 = O N1 , from (18) we have h ·e ¡ 1 N ¢N = +∞, n→∞ ω , f 0 · hN N lim i.e., e ¡ 1 N ¢ = +∞. n→∞ ω , f0 N lim ¤ ESTIMATES OF FOURIER COEFFICIENTS 371 Theorem 2. Let the functions f and Φ be from L2 ([0, 1]). Then ¯Z ¯ ¯ ¯ 1 0 ¯ µ ¶ ¯ 1 f (x)Φ(x) dx¯¯ ≤ ω2 , f (Vn + 2kΦk2 ) n ¯Z 1 ¯ Z 1 ¯ ¯ ¯ +n |f (x)| dx ¯ Φ(x) dx¯¯ , 1 1− n where Vn = n−1 P ¯R ¯ Φ(x) dx¯. k/n 0 ¯ k=1 (19) 0 Proof. Applying the Abel transformation, we get n n Z X Z k n k−1 n k=1 =n f (x) dx ÃZ n−1 X k n k−1 n k n k−1 n k=1 Z Φ(x) dx Z f (x) dx − k n f (x) dx Φ(x) dx 0 1 Φ(x) dx f (x) dx 1 1− n !Z k n Z 1 +n k+1 n 0 µ ¶¶ Z k n 1 =n Φ(x) dx f (x) − f x + dx k−1 n 0 n k=1 Z 1 Z 1 +n f (x) dx Φ(x) dx. n−1 Z X k n µ 1 1− n (20) 0 Since Z k n k−1 n Z f (x)Φ(x) dx − n Z =n Z =n Z =n k n k−1 n k n k−1 n k n Z dt k−1 n ÃZ Z k−1 n k n k n k−1 n k n k−1 n k n k−1 n Z f (t) dt k n k−1 n Z f (x)Φ(x) dx − n Z f (x) dt − k n k−1 n Φ(x) dx Z k n k−1 n f (t) dt ! k n k−1 n Φ(x) dx f (t) dt Φ(x) dx (f (x) − f (t)) Φ(x) dx dt (21) and Z 1 f (x)Φ(x) dx = 0 n Z X k=1 k n k−1 n f (x)Φ(x) dx, (22) 372 V. TSAGAREISHVILI then, taking into account (20), (21) and (22), one has Z 1 f (x)Φ(x) dx = 0 +n n−1 Z X k=1 Z n−1 Z X k−1 n Z k n k−1 n k=1 µ k n k=1 Z 1 f (x) dx 1 1− n Φ(x) dx = n 0 µ k n µ f (x) − f k−1 n 1 +n k=1 f (x)Φ(x) dx − n n Z X f (t) dt k n k−1 n Φ(x) dx µ ¶¶ Z 1 Z k Z 1 n 1 f (x) − f x + dx Φ(x) dx + n f (x) dx Φ(x) dx k−1 1 n 0 1− n 0 n ÃZ k ! Z k Z k n X n n n = f (x)Φ(x) dx − n f (t) dt Φ(x) dx +n n−1 Z X k n k−1 n k=1 µ k n k=1 +n n Z X µ f (x) − f k−1 n 1 x+ n k−1 n 1 x+ n n Z X Z k n dx Z k n dx f (x)Φ(x) dx 0 k n k−1 n k=1 ¶¶ ¶¶ k−1 n Z k n k−1 n (f (x) − f (t)) Φ(x) dx dt Z Z 1 Φ(x) dx+n 1 1− n 0 1 f (x) dx Φ(x) dx. 0 Consequently, ¶¶ Z k n 1 f (x)Φ(x) dx = n dx Φ(x) dx f (x) − f x + k−1 n 0 0 n k=1 Z 1 Z 1 n Z k Z k X n n +n (f (x) − f (t)) Φ(x) dx dt + n f (x) dx Φ(x) dx. Z n−1 Z X 1 k=1 k−1 n k−1 n µ µ 1 1− n (k) k n µ k−1 n Assuming ξn (t) = Z k n 1 n t+ k−1 , n (23) 0 we get µ ¶¶ ¶ µ ¶¶ Z µ µ 1 1 1 1 1 k−1 k f (x) − f x + dx = f t+ −f t+ dt n n 0 n n n n µ ¶¶ Z µ ¡ (k) ¢ 1 1 1 (k) = f ξn (t) − f ξn (t) + dt. n 0 n Hence we have ¯Z k µ µ µ ¶¶ ¯¯ ¶¯ Z 1¯ ¯ n ¯ ¡ (k) ¢ ¯ 1 1 ¯ ¯ 1 (k) ¯f ξn (t) − f ξn (t) + ¯ dt f (x) − f x + dx¯ ≤ ¯ ¯ ¯ ¯ k−1 ¯ n 0 n n n µ ¶¯ µZ 1 ¶ 21 Z ¯ 1 ¯¯ 1 1 1 ¯¯ 2 f (t) − f t + dt ≤ sup ≤ |f (t) − f (t + h)| dt n 0 ¯ n ¯ n |h|≤ 1 0 n µ ¶ 1 1 ,f . (24) = ω2 n n ESTIMATES OF FOURIER COEFFICIENTS By virtue of the Hölder inequality we obtain ¯Z k Z k ¯ ¯ n ¯ n ¯ ¯ (f (x) − f (t)) Φ(x) dx dt¯ ¯ ¯ k−1 k−1 ¯ n n ! 12 ÃZ Z k ÃZ k ≤ n n k−1 n k−1 n 1 ≤√ n ÃZ k n k−1 n (f (x) − f (t))2 dx Z k n k−1 n k−1 n ! 21 Φ2 (x) dx ! 21 ÃZ (f (x) − f (t))2 dx dt Applying the equality (see [11]) Z bZ b Z p |f (x) − f (t)| dx dt = 2 a k n a b−a µZ k n k−1 n b−ξ 373 dt ! 21 Φ2 (x) dx . (25) ¶ p |f (y + ξ) − f (y)| dy dξ, 0 a we get Z k n k−1 n Z k n k−1 n Z 1 n (f (x) − f (t))2 dx dt = 2 0 ÃZ k −ξ n k−1 n ! |f (y + ξ) − f (y)|2 dy dξ. (26) Therefore, by virtue of (25) and (26) we have ¯ ¯ n Z k Z k ¯ ¯X n n ¯ ¯ (f (x) − f (t)) Φ(x)dx dt¯ ¯ k−1 k−1 ¯ ¯ n n k=1 ÃZ 1 Z k ! 21 ÃZ k ! 21 n −ξ X n n n 2 (f (y + ξ) − f (y))2 dy dξ · Φ2 (x) dx ≤√ k−1 k−1 n k=1 0 n n ÃZ 1 n Z k ! 21 à n Z k ! 12 X n n X n 2 2 ≤√ (f (y + ξ) − f (y)) dy dξ · Φ2 (x) dx k−1 k−1 n 0 k=1 n n k=1 ! 21 µZ ÃZ 1 Z ¶ 21 1 1 n 2 (f (y + ξ) − f (y))2 dy dξ Φ2 (x) dx ≤√ · n 0 0 0 ¶ µ ¶ µ 2kΦk2 1 2 1 1 , f · kΦk2 = ω2 ,f . (27) ≤ √ · √ ω2 n n n n n At last, taking into account (24), we have ¯ ¯ µ ¶¶ Z k n−1 Z k µ ¯X ¯ n n 1 ¯ ¯ Φ(x) dx¯ f (x) − f x + dx ¯ k−1 ¯ ¯ n 0 n k=1 ¯ ¯ ¡ µ ¶ X n−1 ¯Z k ¯ ω 1 , f¢ 1 1 2 n ¯ n ¯ ≤ ω2 ,f · Vn . Φ(x) dx¯ = ¯ ¯ 0 ¯ n n n k=1 374 V. TSAGAREISHVILI Hence from (23) and (27) we get ¡1 ¢ ¯Z 1 ¯ µ ¶ ¯ ¯ ω 1 2kΦk 2 n ,f 2 ¯ f (x)Φ(x) dx¯¯ ≤ n · Vn + n ω2 ,f ¯ n n n 0 ¯Z 1 ¯ Z 1 ¯ ¯ ¯ +n |f (x)|dx ¯ Φ(x) dx¯¯ . 1 1− n 0 Theorem 2 is proved completely. ¤ Theorem 3. Let (ϕn ) be an orthonormal system of functions on [0, 1] satisR1 fying the condition ϕn (x) dx = 0, n = 1, 2, . . . . Then 0 µ µ ¶¶ 1 cn (f ) = O ω2 ,f n for every f ∈ L2 ([0, 1]) if and only if Vn = O(1), where Vn = n−1 P ¯R ¯ k n 0 k=1 ϕn (x) dx|. Proof. Sufficiency. Assuming in (19) that Φ(x) = ϕn (x), we obtain ¯Z 1 ¯Z 1 ¯ ¯ ¶ µ Z 1 ¯ ¯ ¯ ¯ 1 ¯ ¯ ¯ ≤ ω2 ¯. |f (x)| dx f (x)ϕ (x) dx , f (V + 2kϕ k )+n ϕ (x) dx n n n 2 n ¯ ¯ ¯ ¯ 1 n 0 1− n k Since Vn = n−1 P ¯ Rn ¯ k=1 ϕn (x) dx| = O(1) and 0 µ R1 0 |cn (f )| = O ω2 0 ϕn (x) dx = 0, n = 1, 2, . . . , we have µ 1 ,f n ¶¶ . Necessity. If Vn 6= O(1), then as it is known (see [15]) there exists f0 ∈ Lip 1 such that lim n|cn (f0 )| = +∞. (28) ¡1 ¢ ¡ 1n→∞ ¢ As far as ω2 n , f0 = O n , from (28) we have cn (f0 ) ¡ ¢ = +∞. n→∞ ω2 1 , f0 n lim Theorem 4. Let (ϕn ) be an orthonormal system on [0, 1] satisfying Z1 ϕn (x)dx = 0, n = 1, 2, . . . . 0 Then the relation µ e N = O ω2 µ 1 ,f N ¶¶ for every f ∈ L2 ([0, 1]) ¤ ESTIMATES OF FOURIER COEFFICIENTS 375 holds if and only if HN = O(hN ) for every sequence (an ) ∈ `2 . Proof. Sufficiency. Let f ∈ L2 ([0, 1]). As it was shown above (see (2)), the equality Z 1 Z 1 N +k N +k X X (k) 2 cm (f ) = f (x) cm ϕm (x) dx = f (x)PN (x) dx (29) 0 m=N 0 m=N holds. By virtue of Theorem 2, we get ¯ ¯Z 1 µ ¶³ ´ ¯ ¯ 1 (k) (k) ¯ ¯ ≤ ω2 f (x)P (x) dx k , f H + 2kP N 2 . N N ¯ ¯ N (30) 0 Since µZ 1 (k) kPN k2 = 0 ³ Z ´2 ¶ 12 (k) PN (x) = = à N +k X à N +k X 1 0 !2 cm (f )ϕm (x) 21 dx m=N ! 21 c2m (f ) ≤ eN , m=N and by virtue of the condition of Theorem 4 HN = O(eN ), from (30) we have ¯Z 1 ¯ ¶ µ ¯ ¯ 1 (k) ¯ ¯ , f eN , f (x)PN (x) dx¯ ≤ c · ω2 ¯ N 0 where c does not depend on N . Finally, from (29) we get N +k X µ c2m (f ) ≤ c · ω2 m=N hence ∞ X 1 ,f N ¶ eN , µ c2m (f ) ≤ c · ω2 m=N From (31) we have µ eN = O ω2 µ 1 ,f N 1 ,f N k = 1, 2, . . . , ¶ eN . (31) ¶¶ . Thus the sufficiency is proved. Necessity. Let HN 6= O(hN ). Then by virtue of Theorem 1 there exists a function f0 ∈ Lip 1 such that lim N eN = +∞. ¡ ¢ ¡ ¢ As far as for the function f0 the relation ω2 N1 , f0 = O N1 holds, from (31) it follows e ¡ N ¢ = +∞. lim n→∞ ω2 1 , f0 n n→∞ 376 V. TSAGAREISHVILI Theorem is proved completely. ¤ Theorem 5. From every orthonormal system ϕn on [0, 1] satisfying the R1 condition ϕn (x) dx = 0, n = 1, 2, . . . , one can choose a subsystem ψk = ϕnk 0 for which the following conditions are fulfilled: ¡ ¡ ¢¢ 1) cn (f ) = ¡O ¡ω2 n1 ¢¢ ,f , 2) eN = O ¡ω ¡N1 , f ¢¢, 3) eN = O ω2 N1 , f . Proof. Let εi (k) = ÃZ ∞ X i k !2 ϕs (x) dx , i = 1, 2, . . . , k. 0 s=1 By virtue of the Bessel inequality, εi (k) ≤ 1 for every i = 1, 2, . . . , k. Therefore for each fixed k we can choose a number si (k) such that the inequality ÃZ i !2 ∞ X k 1 ϕs (x) dx < 3 k 0 s=si (k) holds. Now if s(k) = max si (k), then 1≤i≤k ∞ X ÃZ s=s(k) i k !2 ϕs (x) dx 1 . k3 < 0 Hence for every i = 1, 2, . . . , k we have ¯ ¯Z i ¯ ¯ k 1 ¯ ¯ ϕs (x) dx¯ < 3/2 ¯ ¯ k ¯ 0 if s ≥ s(k). Assuming ϕs(k) = ψk , we get ¯Z i ¯ ¯ ¯ k 1 ¯ ¯ ψk (x) dx¯ < 3/2 . ¯ ¯ 0 ¯ k This inequality implies the inequality ¯ ¯ k−1 ¯Z i ¯ X ¯ ¯ k Vk = ψk (x) dx¯ < 1, ¯ ¯ ¯ 0 n = 1, 2, . . . , (32) i=1 and also the estimate ¯ ¯ à ! 21 k−1 k+l ÃZ i !2 12 k+l k−1 ¯Z i X k+l ¯ X X X X k k ¯ ¯ a2m am ψm (x) dx¯ ≤ ψm (x) dx ¯ ¯ 0 ¯ 0 i=1 i=1 m=k m=k ≤ à k+l X m=k ! 21 a2m · k−1 X 1 i=1 k < m=k à k+l X m=k ! 12 a2m . ESTIMATES OF FOURIER COEFFICIENTS 377 is valid. Therefore Hk = O(hk ). (33) Hence the validity of Theorem 5 follows from Theorems 1,2,3,4 and from the relations (32) and (33). ¤ Remark 1. It follows from the proof of Theorem 1 that the relation µ µ ¶¶ 1 eN = O ω2 ,f N (34) holds for every f ∈ C([0, 1]) if and only if relation (34) holds for every f ∈ Lip 1. Hence it follows Corollary 1. Relation (34) holds for every f ∈ L2 ([0, 1]) if and only if the condition µ ¶ 1 eN = O N holds for every function f ∈ Lip 1. Corollary 2. The relation µ cn (f ) = O ω2 µ 1 ,f n ¶¶ holds for every f ∈ L2 ([0, 1]) if and only if the condition µ ¶ 1 cn (f ) = O n holds for every f ∈ Lip 1 (see [15]). Remark 2. a) If (ϕn ) is a trigonometric system, then the inequality ¯ ¯ n−1 ¯Z k n−1 ¯ X X 1 1 ¯ ¯ n Vn = sin πnx dx¯ ≤ < ¯ ¯ ¯ 0 πn π k=1 k=1 is valid. b) Let (χn ) be the Haar system (see [11]). Then if n = 2m + l (1 ≤ l ≤ 2m ), we have ¯Z k ¯ ¯ n ¯ m 2 ¯ ¯ χn (x) dx¯ ≤ 2− 2 < √ . ¯ ¯ 0 ¯ n k On the other hand, note that only one integral zero when k = 1, 2, . . . , n. Thus Rn χn (x) dx is different from 0 ¯ ¯ n−1 ¯Z k ¯ X 2 ¯ n ¯ Vn = χn (x) dx¯ ≤ √ . ¯ ¯ 0 ¯ n k=1 378 V. TSAGAREISHVILI Further on, it is easy to verify that if n = 2s + l, in case l ≤ 2s the following estimate is valid: ¯ ¯ ¯ ¯ n+q n−1 ¯Z k n−1 ¯Z k X ¯ X ¯ X n n ¯ ¯ ¯ ¯ Pn(q) (x) dx¯ ≡ am χm (x) dx¯ ¯ ¯ ¯ 0 ¯ ¯ ¯ 0 m=n k=1 k=1 ¯Z k n+q ¯ ¯Z k ¯ n ¯ n ¯ ¯ ¯ X X s+1 X n 2 ¯ ¯ ¯ ¯ (q) ≤ Pn (x) dx¯ . am χm (x) dx¯ + (36) ¯ ¯ k ¯ 0 ¯ ¯ ¯ s+1 m=n k=1 k=1 2 Applying the Hölder inequality, we get ¯ Z ¯ ! 12 à n+q n ¯Z k ¯ 1 X X ¯ ¯ n a2m |Pn(q) (x)| dx ≤ Pn(q) (x) dx¯ ≤ ≤ hn . ¯ k ¯ s+1 ¯ 0 k=1 (37) m=n 2 Then, if n + q > 2s+1 , then ¯ ¯ ¯ ¯ k k n+q n ¯Z n ¯Z 2s+1 ¯ X ¯ X s+1 X s+1 X 2 2 ¯ ¯ ¯ ¯ am χm (x) dx¯ ≤ am χm (x) dx¯ ¯ ¯ ¯ 0 ¯ ¯ 0 ¯ m=n m=n k=1 k=1 ¯Z k ¯ n+q n ¯ ¯ X ¯ 2s+1 X ¯ + am χm (x) dx¯ . ¯ ¯ 0 ¯ s+1 k=1 m=2 (38) +1 Since m ≥ 2s+1 , we have Z k 2s+1 χm (x) dx = 0 0 and the second summand in (38) is equal to zero. On the other hand, as far as 2s+1 − n ≤ 2s , we get ¯ ¯ ¯ ¯ s+1 k k 2s+1 n ¯Z n ¯Z ¯ 2X ¯ X X ¯ ¯ ¯ 2s+1 X ¯ 2s+1 am χm (x) dx¯ ≤ χm (x) dx¯ |am | ¯ ¯ ¯ m=n ¯ ¯ 0 ¯ 0 m=n k=1 k=1 2s+1 ≤ X 1 |am | · √ ≤ m m=n à 2s+1 X ! 12 à 2s+1 ! 12 X 1 a2m ≤ hn . m m=n m=n (39) Finally, taking into account in (36) the inequalities (37), (38) and (39), we obtain ¯ ¯ n ¯Z k ¯ X ¯ ¯ n (q) Pn (x) dx¯ = O(hn ). ¯ ¯ ¯ 0 k=1 Consequently, Hn = O(hn ). c) Let now (ϕn ) be the Walsh system (see [12]). Then since ¯Z k ¯ ¯ n ¯ 1 ¯ ¯ ϕn (x) dx¯ < , ¯ ¯ 0 ¯ n ESTIMATES OF FOURIER COEFFICIENTS we get 379 ¯ ¯ n−1 ¯Z k ¯ X n ¯ ¯ Vn = ϕn (x) dx¯ < 1. ¯ ¯ 0 ¯ k=1 In this case the inequality Hn = O(hn ) is analogously proved as in case of the Haar system. In conclusion, we can say that the efficiency of the conditions of Theorems 1, 2, and 3 is evident. It should be noted that the above results were partially announced in [14]. References 1. J. Marcinkiewicz, Quelques theoremes sur les sériés orthogonales. Ann. Polon. 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Javakhishvili Tbilisi State University 2, University St., Tbilisi 0143, Georgia