Solve Quadratics with Square Roots

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Solving Quadratic Equations by Finding Square Roots

Focus 9 Learning Goal –

( HS.A-SSE.A.1, HS.A-SSE.A.2, HS.A-SEE.B., HS.A-APR.A.1, HS.A-

APR.B.3, HS.A-REI.B.4)

= Students will factor polynomials using multiple methods, perform operations (excluding division) on polynomials and sketch rough graphs using key features.

4

In addition to level 3, students make connections to other content areas and/or contextual situations outside of math.

3

Students will factor polynomials using multiple methods, perform operations

(excluding division) on polynomials and sketch rough graphs using key features.

- Factor using methods including common factors, grouping, difference of two squares, sum and difference of two cubes, and combination of methods.

- Add, subtract, and multiply polynomials,

- Explain how the multiplicity of the zeros provides clues as to how the graph will behave.

- Sketch a rough graph using the zeros and other easily identifiable points.

2

Students will factor polynomials using limited methods, perform operations

(excluding division) on polynomials, and identify key features on a graph.

- Add and subtract polynomials.

- Multiply polynomials using an area model.

- Factor polynomials using an area model.

- Identify the zeros when suitable factorizations are available.

- Identify key features of a graph.

1

Students will have partial success at a 2 or 3, with help.

0

Even with help, the student is not successful at the learning goal.

Remember: Linear equation is x to the first power ax+by=c

Quadratic equation: is x to the second power

Standard Form:

ax

2

+bx+c=0

a

0

Find Solutions to ax

2

+c=0

(Get x

2

alone in form x

2

=d)

Once you get x

2

=d take the square root of both sides to get x.

3 Results

1. x 2 =d If d is a positive number, then you have 2 solutions x

  d

2. x 2 =d If d=0 then there is only one solution x=0

3. x 2 =d If d is a negative number, there is no solution

(Can’t take sq. root of a negative)

1.

Examples:

2.

x 2 =4 x 2

 x

 x 2 =5

4 x 2

2 x

 

x can be + or -, when squared it is positive

5

5

Solve:

4x 2 + 100 = 0

-100 -100

4x 2 = -100 x 2 = -25

(divide both sides by 4)

NO Solution

3x 2 -99 = 0

3x 2 = 99 x 2 = 33 x

 

33

Two Solutions

The surface area of a cube is 150ft 2 . Find the length of each edge.

SA = 6s 2 x x x

Sides of the cube are 5 ft.

You can’t have a negative length.

150 = 6s 2

25 = s 2

5

 s

1st

DIVIDE

BY 6

Watch out below!

A construction worker on the top floor of a 200 foot tall building accidentally drops a heavy wrench. How many sections will it take to hit the ground?

The formula d=rt is used when the speed is constant. However, when an object is dropped, the speed continually increases.

Use the formula: h = -16t 2 + s h = final height of object t = time s = starting height of object h = -16t 2 + s

0 = -16t 2 + 200

-200 = -16t 2

12.5 = t 2

√12.5 = t

About 3.54 seconds.

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