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Rate-Time-Distance

Problems

Algebra 1

Rate-Time-Distance Problems

• An object is in uniform motion when it moves without changing its speed, or rate. These problems fall into 3 categories: Motion in opposite directions, Motion in the same direction, & Round Trip. Each is solved using a chart, a sketch, and the distance formula

.

D

RT or T

D or R

R

D

T

Motion in the Same Direction

A helicopter leaves Central Airport and flies north at 180 mi/h. Twenty minutes later a plane leaves the airport and follows the helicopter at 330 mi/h. How long does it take the plane to overtake the helicopter.

Rate Time Distance

Helicopter

Plane

180

330 t + ⅓ t

180(t + ⅓)

330t

Rate Time Distance

Helicopter

Plane

180

330 t + ⅓ 180(t + ⅓) t 330t

When the plane overtakes the helicopter, the two distances are equal.

330 t

330 t

180

 t

180 t

1

3

60

150 t

60 t

2

5 h or 24 min.

Officer Barbrady left his home at 2:15 PM and had driven 60 miles when he ran out of gas. He walked 2 miles to a gas station, where he arrived at 4:15 pm. If he drives 10 times as faster than he walks, how fast does he walk?

Distance Rate Time

Driving

Walking

60

2

10r r

60

10 r

2 r

Set to Equal

Time Driving

Time Walking

2h (2 : 15 to 4 : 15)

60

10 r

2 r

2

60

10 r

2

10 r

20 r

80

80

1

20

10 r

2

4

80

10 r r

2

1

Office Barbrady walked at a rate of 4/mph

Two cars leave the same town at the same time. One travels north at 60 mph and the other south at 45 mph . In how many hours will they be 420 miles apart ?

Rate

60

45

Time t t

Distance

60 t

45 t

Rate

60

45

Time t t

Distance

60 t

45 t

60 t

45 t

420

105 t

 t

420

4

In 4 hours the cars will be 420 miles apart

.

Bicyclist Brent and Jane started at noon from 60 km apart and rode toward each other, meeting at 1:30 P.M.

Brent’s speed was 4 km/h greater than

Jane’s speed. Find their speeds.

Rate Time Distance

Brent

Jane

r + 4 r

1.5

1.5

1.5(r + 4)

1.5r

Rate Time Distance

Brent

r + 4 1.5

1.5(r + 4)

Jane

r 1.5

1.5r

1 .

5

 r

4

1 .

5 r

1 .

5 r

6

1 .

5 r

3 r

54

60

60

18

4

22

Brent' s Speed r

18 Jane' s Speed

Round Trip

A ski lift carried Maria up a slope at the rate of 6 km/h, and she skied back down parallel to the lift at 34 km/h. The round trip took 30 min. How far did she ski?

Rate Time Distance

Up

Down

6

34

0.5 - t t

6(0.5 – t)

34 t

Rate Time Distance

Up

6 0.5 - t

for a distance of 2.55km

.

6(0.5 – t)

Down

34 t 34 t

In round trip problems, the two distances are equal.

34 t

6

0 .

5

 t

34 t

40

3

34 t t

6 t t

0 .

075

3

2 .

55

0 .

075

40

  km

Rate-Time-Distance

Problems

Review Additional Problems Part

B

Sherry and Bob like to jog in the park. Sherry can jog at 5 mph, while Bob can jog at 7 mph.

If Sherry starts 30 minutes ahead of Bob, how long will it take Bob to catch up to Sherry?

Let x = the time it takes Bob to catch Sherry

Sherry

Bob

Rate

5

7

Time x + 1/2 x

Distance

5(x + 1/2)

7x

Sherry started 30 minutes or 1/2 hour before Bob, so her time must reflect that amount. Rate is in miles per hour, time must be in hours so our units match.

Sherry

Bob

Rate

5

7

Time Distance x + 1/2 5(x + 1/2) x 7x

When Bob catches-up with Sherry their distances will be equal. So the Equation will be sherry’s distance equals Bob’s distance.

2 .

5

1

2

7 x

5 x

2 .

5

7 x

5

2 x

It will take Bob 1.25 hrs to catch up with Sherry.

1 .

25

 x

Bernadette drove 120 miles. The first part of the trip she averaged 60 mph, but on the second part of the trip she ran into some congestion and averaged 48 mph. If the total driving time was 2.2 hours, how much time did she spend at 60 mph?

Part 1

Part 2

Rate

60

48

Time t

2.2-t

Distance

60t

48(2.2-t)

Rate Time Distance

Part 1

Part 2

60 t

2.2-t

60t

48 48(2.2-t)

60 t

48

2 .

2

 t

120

60 t

105 .

6

48 t

12 t

 t

14 .

4

1 .

2

120

The time traveled at 60 mph was 1.2 hours.

A passenger train’s speed is 60 mi/h, and a freight train’s speed is

40 mi/h. The passenger train travels the same distance in 1.5 h less time than the freight train. How long does each train take to make the trip.

Rate Time Distance

Freight train 4.5h.

Passenger train 3h

Ali rode her bike to visit a friend. She traveled at 10 mi/h.

While she was there, it began to rain. Her friend drove her home in a car traveling 25 mi/h. Ali took 1.5 hours longer to go to her friend’s than to return home. How many hours did it take Ali ti ride to her friend’s house?

Rate Time Distance

2.5 h

Katie rides her bike the same distance as Jill walks. Katie rides her bike 10 km/h faster than Jill walks. If it takes Katie 1 h. and

Jill 3 h to travel the same distance, how fast does each travel?

Rate Time Distance

Katie 15 km/ h

Jill 5 km/h

At 10:00 A.M., a car leaves a house at a rate of 60 mi/h. At the same time, another car leaves the same house at a rate of 50 mi/h in the opposite direction. At what time will the car be 330 miles apart?

Rate Time Distance

1:00 P.M.

Brittney begins walking ay 3 mi/h toward the library. Her friend meets her at the halfway point and drives her the rest of the way to the library. The distance to the library is 4 miles. How many hours did Marla walk?

Rate Time Distance

2/3 h or 40 min.

Ryan begins walking towards John’s house at 3 mi/h. John leaves his house at the same time and walks towards Fred’s house on the same path at a rate of 2 mi/h. How long will it be before they meet if the distance between the houses is 4 miles?

Rate Time Distance

4/5 h. or 48 min

A train leaves the station at 6:00 P.M. traveling west at 80 mi/h.

On a parallel track, a second train leaves the station 3 hours later traveling west at 100 mi/h. At what time will the second train catch up with the first?

Rate Time Distance

9:00 A.M.

It takes 1 hour longer to fly to St. Paul at 200 mi/h than it does to return at 250 mi/h. How far way is St. Paul.

Rate Time Distance

1000 mi

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